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C Copyright (c) 2003-2010 University of Florida
C
C This program is free software; you can redistribute it and/or modify
C it under the terms of the GNU General Public License as published by
C the Free Software Foundation; either version 2 of the License, or
C (at your option) any later version.
C This program is distributed in the hope that it will be useful,
C but WITHOUT ANY WARRANTY; without even the implied warranty of
C MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
C GNU General Public License for more details.
C The GNU General Public License is included in this distribution
C in the file COPYRIGHT.
c This subroutine scans a string and returns the first valid integer
c that falls into one of the following two regular expressions:
c " *[+-]? *[0-9]+" --> 1, +1, -1
c " *\( *[+-]? *[0-9]+.*\)" --> (1), (+1), (-1)
c If the string is blank, then iVal=UNDEFINED, nChars=0, iErrPos=0.
c INPUT
c char*(*) sz : the string to parse
c OUTPUT
c int iVal : the valid integer (undefined if iErrPos!=0)
c int nChars : the number of characters processed (undefined if iErrPos!=0)
c int iErrPos : the position of an invalid character
#include "iachar.h"
subroutine parse_int(sz,iVal,nChars,iErrPos)
implicit none
c ARGUMENTS
character*(*) sz
integer iVal, nChars, iErrPos
c INTERNAL VARIABLES
integer maxlen, i, j
logical bParen, bNeg
character*1 czSpace, czTab
c INTRINSIC FUNCTIONS
integer index
intrinsic index
character*1 achar
intrinsic achar
c ----------------------------------------------------------------------
iErrPos = 0
maxlen = len(sz)
czSpace = achar(_IACHAR_SPACE)
czTab = achar(_IACHAR_TAB)
i = 1
do while ((sz(i:i).eq.czSpace.or.sz(i:i).eq.czTab).and.
& i.le.maxlen)
i = i + 1
end do
if (i.gt.maxlen) then
c o the string is blank
nChars = 0
return
end if
c o parenthetical?
bParen = (sz(i:i).eq.'(')
if (bParen) then
j = i + 1
do while (sz(j:j).ne.')'.and.j.le.maxlen)
j = j + 1
end do
c o no closing parenthesis
if (j.gt.maxlen) iErrPos = i
maxlen = j - 1
c o find the next non-blank character
i = i + 1
do while ((sz(i:i).eq.czSpace.or.sz(i:i).eq.czTab).and.
& i.le.maxlen)
i = i + 1
end do
c o the string is blank
if (i.gt.maxlen) iErrPos = i
if (iErrPos.ne.0) return
end if
c o sign?
j = index('0123456789-+',sz(i:i))
if (j.eq.0) then
iErrPos = i
return
end if
bNeg = (j.eq.11)
if (j.gt.10) then
c o find the next non-blank character
j = i + 1
do while ((sz(j:j).eq.czSpace.or.sz(j:j).eq.czTab).and.
& j.le.maxlen)
j = j + 1
end do
c o the string is missing the number
if (j.gt.maxlen) then
iErrPos = i
return
end if
i = j
end if
c o process all integers from i to maxlen
iVal = 0
j = index('0123456789',sz(i:i))
if (j.eq.0) then
c o no first number
iErrPos = i
return
end if
do while (j.ne.0.and.i.le.maxlen)
iVal = 10*iVal + (j-1)
i = i + 1
j = index('0123456789',sz(i:i))
end do
if (bNeg) iVal = -iVal
c o record the number of characters processed
nChars = i - 1
if (bParen) nChars = maxlen+1
c ----------------------------------------------------------------------
return
c end subroutine parse_int
end
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