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/* Memcpy.c - Copy a block of memory
Copyright (C) 1995, 1996 Malc Arnold.
This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 2, or (at your option)
any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program; if not, write to the Free Software
Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA. */
#include <stdio.h>
/****************************************************************************/
/* RCS info. */
#ifndef lint
static char *RcsId = "$Id: memcpy.c,v 2.0 1997/09/06 11:56:40 malc Rel $";
#endif /* ! lint */
/****************************************************************************/
/*LINTLIBRARY*/
/****************************************************************************/
char *memcpy(buf, src, len)
char *buf, *src;
int len;
{
/* Copy len bytes from src into buf */
char *rbuf = buf;
int c;
/* This is pretty simple really */
for (c = 0; c < len; c++) {
*buf++ = *src++;
}
return(rbuf);
}
/****************************************************************************/
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