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/*
* zmod - modulo arithmetic routines
*
* Copyright (C) 1999 David I. Bell, Landon Curt Noll and Ernest Bowen
*
* Primary author: David I. Bell
*
* Calc is open software; you can redistribute it and/or modify it under
* the terms of the version 2.1 of the GNU Lesser General Public License
* as published by the Free Software Foundation.
*
* Calc is distributed in the hope that it will be useful, but WITHOUT
* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY
* or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General
* Public License for more details.
*
* A copy of version 2.1 of the GNU Lesser General Public License is
* distributed with calc under the filename COPYING-LGPL. You should have
* received a copy with calc; if not, write to Free Software Foundation, Inc.
* 59 Temple Place, Suite 330, Boston, MA 02111-1307, USA.
*
* @(#) $Revision: 29.4 $
* @(#) $Id: zmod.c,v 29.4 2006/06/11 00:08:56 chongo Exp $
* @(#) $Source: /usr/local/src/cmd/calc/RCS/zmod.c,v $
*
* Under source code control: 1991/05/22 23:03:55
* File existed as early as: 1991
*
* Share and enjoy! :-) http://www.isthe.com/chongo/tech/comp/calc/
*/
/*
* Routines to do modulo arithmetic both normally and also using the REDC
* algorithm given by Peter L. Montgomery in Mathematics of Computation,
* volume 44, number 170 (April, 1985). For multiple multiplies using
* the same large modulus, the REDC algorithm avoids the usual division
* by the modulus, instead replacing it with two multiplies or else a
* special algorithm. When these two multiplies or the special algorithm
* are faster then the division, then the REDC algorithm is better.
*/
#include "config.h"
#include "zmath.h"
#define POWBITS 4 /* bits for power chunks (must divide BASEB) */
#define POWNUMS (1<<POWBITS) /* number of powers needed in table */
static void zmod5(ZVALUE *zp);
static void zmod6(ZVALUE z1, ZVALUE *res);
static void zredcmodinv(ZVALUE z1, ZVALUE *res);
static REDC *powermodredc = NULL; /* REDC info for raising to power */
BOOL havelastmod = FALSE;
static ZVALUE lastmod[1];
static ZVALUE lastmodinv[1];
/*
* Square a number and then mod the result with a second number.
* The number to be squared can be negative or out of modulo range.
* The result will be in the range 0 to the modulus - 1.
*
* given:
* z1 number to be squared
* z2 number to take mod with
* res result
*/
void
zsquaremod(ZVALUE z1, ZVALUE z2, ZVALUE *res)
{
ZVALUE tmp;
FULL prod;
FULL digit;
if (ziszero(z2) || zisneg(z2))
math_error("Mod of non-positive integer");
/*NOTREACHED*/
if (ziszero(z1) || zisunit(z2)) {
*res = _zero_;
return;
}
/*
* If the modulus is a single digit number, then do the result
* cheaply. Check especially for a small power of two.
*/
if (zistiny(z2)) {
digit = z2.v[0];
if ((digit & -digit) == digit) { /* NEEDS 2'S COMP */
prod = (FULL) z1.v[0];
prod = (prod * prod) & (digit - 1);
} else {
z1.sign = 0;
prod = (FULL) zmodi(z1, (long) digit);
prod = (prod * prod) % digit;
}
itoz((long) prod, res);
return;
}
/*
* The modulus is more than one digit.
* Actually do the square and divide if necessary.
*/
zsquare(z1, &tmp);
if ((tmp.len < z2.len) ||
((tmp.len == z2.len) && (tmp.v[tmp.len-1] < z2.v[z2.len-1]))) {
*res = tmp;
return;
}
zmod(tmp, z2, res, 0);
zfree(tmp);
}
/*
* Calculate the number congruent to the given number whose absolute
* value is minimal. The number to be reduced can be negative or out of
* modulo range. The result will be within the range -int((modulus-1)/2)
* to int(modulus/2) inclusive. For example, for modulus 7, numbers are
* reduced to the range [-3, 3], and for modulus 8, numbers are reduced to
* the range [-3, 4].
*
* given:
* z1 number to find minimum congruence of
* z2 number to take mod with
* res result
*/
void
zminmod(ZVALUE z1, ZVALUE z2, ZVALUE *res)
{
ZVALUE tmp1, tmp2;
int sign;
int cv;
if (ziszero(z2) || zisneg(z2)) {
math_error("Mod of non-positive integer");
/*NOTREACHED*/
}
if (ziszero(z1) || zisunit(z2)) {
*res = _zero_;
return;
}
if (zistwo(z2)) {
if (zisodd(z1))
*res = _one_;
else
*res = _zero_;
return;
}
/*
* Do a quick check to see if the number is very small compared
* to the modulus. If so, then the result is obvious.
*/
if (z1.len < z2.len - 1) {
zcopy(z1, res);
return;
}
/*
* Now make sure the input number is within the modulo range.
* If not, then reduce it to be within range and make the
* quick check again.
*/
sign = z1.sign;
z1.sign = 0;
cv = zrel(z1, z2);
if (cv == 0) {
*res = _zero_;
return;
}
tmp1 = z1;
if (cv > 0) {
z1.sign = (BOOL)sign;
zmod(z1, z2, &tmp1, 0);
if (tmp1.len < z2.len - 1) {
*res = tmp1;
return;
}
sign = 0;
}
/*
* Now calculate the difference of the modulus and the absolute
* value of the original number. Compare the original number with
* the difference, and return the one with the smallest absolute
* value, with the correct sign. If the two values are equal, then
* return the positive result.
*/
zsub(z2, tmp1, &tmp2);
cv = zrel(tmp1, tmp2);
if (cv < 0) {
zfree(tmp2);
tmp1.sign = (BOOL)sign;
if (tmp1.v == z1.v)
zcopy(tmp1, res);
else
*res = tmp1;
} else {
if (cv)
tmp2.sign = !sign;
if (tmp1.v != z1.v)
zfree(tmp1);
*res = tmp2;
}
}
/*
* Compare two numbers for equality modulo a third number.
* The two numbers to be compared can be negative or out of modulo range.
* Returns TRUE if the numbers are not congruent, and FALSE if they are
* congruent.
*
* given:
* z1 first number to be compared
* z2 second number to be compared
* z3 modulus
*/
BOOL
zcmpmod(ZVALUE z1, ZVALUE z2, ZVALUE z3)
{
ZVALUE tmp1, tmp2, tmp3;
FULL digit;
LEN len;
int cv;
if (zisneg(z3) || ziszero(z3)) {
math_error("Non-positive modulus in zcmpmod");
/*NOTREACHED*/
}
if (zistwo(z3))
return (((z1.v[0] + z2.v[0]) & 0x1) != 0);
/*
* If the two numbers are equal, then their mods are equal.
*/
if ((z1.sign == z2.sign) && (z1.len == z2.len) &&
(z1.v[0] == z2.v[0]) && (zcmp(z1, z2) == 0))
return FALSE;
/*
* If both numbers are negative, then we can make them positive.
*/
if (zisneg(z1) && zisneg(z2)) {
z1.sign = 0;
z2.sign = 0;
}
/*
* For small negative numbers, make them positive before comparing.
* In any case, the resulting numbers are in tmp1 and tmp2.
*/
tmp1 = z1;
tmp2 = z2;
len = z3.len;
digit = z3.v[len - 1];
if (zisneg(z1) && ((z1.len < len) ||
((z1.len == len) && (z1.v[z1.len - 1] < digit))))
zadd(z1, z3, &tmp1);
if (zisneg(z2) && ((z2.len < len) ||
((z2.len == len) && (z2.v[z2.len - 1] < digit))))
zadd(z2, z3, &tmp2);
/*
* Now compare the two numbers for equality.
* If they are equal we are all done.
*/
if (zcmp(tmp1, tmp2) == 0) {
if (tmp1.v != z1.v)
zfree(tmp1);
if (tmp2.v != z2.v)
zfree(tmp2);
return FALSE;
}
/*
* They are not identical. Now if both numbers are positive
* and less than the modulus, then they are definitely not equal.
*/
if ((tmp1.sign == tmp2.sign) &&
((tmp1.len < len) || (zrel(tmp1, z3) < 0)) &&
((tmp2.len < len) || (zrel(tmp2, z3) < 0))) {
if (tmp1.v != z1.v)
zfree(tmp1);
if (tmp2.v != z2.v)
zfree(tmp2);
return TRUE;
}
/*
* Either one of the numbers is negative or is large.
* So do the standard thing and subtract the two numbers.
* Then they are equal if the result is 0 (mod z3).
*/
zsub(tmp1, tmp2, &tmp3);
if (tmp1.v != z1.v)
zfree(tmp1);
if (tmp2.v != z2.v)
zfree(tmp2);
/*
* Compare the result with the modulus to see if it is equal to
* or less than the modulus. If so, we know the mod result.
*/
tmp3.sign = 0;
cv = zrel(tmp3, z3);
if (cv == 0) {
zfree(tmp3);
return FALSE;
}
if (cv < 0) {
zfree(tmp3);
return TRUE;
}
/*
* We are forced to actually do the division.
* The numbers are congruent if the result is zero.
*/
zmod(tmp3, z3, &tmp1, 0);
zfree(tmp3);
if (ziszero(tmp1)) {
zfree(tmp1);
return FALSE;
} else {
zfree(tmp1);
return TRUE;
}
}
/*
* Given the address of a positive integer whose word count does not
* exceed twice that of the modulus stored at lastmod, to evaluate and store
* at that address the value of the integer modulo the modulus.
*/
static void
zmod5(ZVALUE *zp)
{
LEN len, modlen, j;
ZVALUE tmp1, tmp2;
ZVALUE z1, z2, z3;
HALF *a, *b;
FULL f;
HALF u;
int subcount = 0;
if (zrel(*zp, *lastmod) < 0)
return;
modlen = lastmod->len;
len = zp->len;
z1.v = zp->v + modlen - 1;
z1.len = len - modlen + 1;
z1.sign = z2.sign = z3.sign = 0;
if (z1.len > modlen + 1) {
math_error("Bad call to zmod5!!!");
/*NOTREACHED*/
}
z2.v = lastmodinv->v + modlen + 1 - z1.len;
z2.len = lastmodinv->len - modlen - 1 + z1.len;
zmul(z1, z2, &tmp1);
z3.v = tmp1.v + z1.len;
z3.len = tmp1.len - z1.len;
if (z3.len > 0) {
zmul(z3, *lastmod, &tmp2);
j = modlen;
a = zp->v;
b = tmp2.v;
u = 0;
len = modlen;
while (j-- > 0) {
f = (FULL) *a - (FULL) *b++ - (FULL) u;
*a++ = (HALF) f;
u = - (HALF) (f >> BASEB);
}
if (z1.len > 1) {
len++;
if (tmp2.len > modlen)
f = (FULL) *a - (FULL) *b - (FULL) u;
else
f = (FULL) *a - (FULL) u;
*a++ = (HALF) f;
}
while (len > 0 && *--a == 0)
len--;
zp->len = len;
zfree(tmp2);
}
zfree(tmp1);
while (len > 0 && zrel(*zp, *lastmod) >= 0) {
subcount++;
if (subcount > 2) {
math_error("Too many subtractions in zmod5");
/*NOTREACHED*/
}
j = modlen;
a = zp->v;
b = lastmod->v;
u = 0;
while (j-- > 0) {
f = (FULL) *a - (FULL) *b++ - (FULL) u;
*a++ = (HALF) f;
u = - (HALF) (f >> BASEB);
}
if (len > modlen) {
f = (FULL) *a - (FULL) u;
*a++ = (HALF) f;
}
while (len > 0 && *--a == 0)
len--;
zp->len = len;
}
if (len == 0)
zp->len = 1;
}
static void
zmod6(ZVALUE z1, ZVALUE *res)
{
LEN len, modlen, len0;
int sign;
ZVALUE zp0, ztmp;
if (ziszero(z1) || zisone(*lastmod)) {
*res = _zero_;
return;
}
sign = z1.sign;
z1.sign = 0;
zcopy(z1, &ztmp);
modlen = lastmod->len;
zp0.sign = 0;
while (zrel(ztmp, *lastmod) >= 0) {
len = ztmp.len;
zp0.len = len;
len0 = 0;
if (len > 2 * modlen) {
zp0.len = 2 * modlen;
len0 = len - 2 * modlen;
}
zp0.v = ztmp.v + len - zp0.len;
zmod5(&zp0);
len = len0 + zp0.len;
while (len > 0 && ztmp.v[len - 1] == 0)
len--;
if (len == 0) {
zfree(ztmp);
*res = _zero_;
return;
}
ztmp.len = len;
}
if (sign)
zsub(*lastmod, ztmp, res);
else
zcopy(ztmp, res);
zfree(ztmp);
}
/*
* Compute the result of raising one number to a power modulo another number.
* That is, this computes: a^b (modulo c).
* This calculates the result by examining the power POWBITS bits at a time,
* using a small table of POWNUMS low powers to calculate powers for those bits,
* and repeated squaring and multiplying by the partial powers to generate
* the complete power. If the power being raised to is high enough, then
* this uses the REDC algorithm to avoid doing many divisions. When using
* REDC, multiple calls to this routine using the same modulus will be
* slightly faster.
*/
void
zpowermod(ZVALUE z1, ZVALUE z2, ZVALUE z3, ZVALUE *res)
{
HALF *hp; /* pointer to current word of the power */
REDC *rp; /* REDC information to be used */
ZVALUE *pp; /* pointer to low power table */
ZVALUE ans, temp; /* calculation values */
ZVALUE modpow; /* current small power */
ZVALUE lowpowers[POWNUMS]; /* low powers */
ZVALUE ztmp;
int curshift; /* shift value for word of power */
HALF curhalf; /* current word of power */
unsigned int curpow; /* current low power */
unsigned int curbit; /* current bit of low power */
int i;
if (zisneg(z3) || ziszero(z3)) {
math_error("Non-positive modulus in zpowermod");
/*NOTREACHED*/
}
if (zisneg(z2)) {
math_error("Negative power in zpowermod");
/*NOTREACHED*/
}
/*
* Check easy cases first.
*/
if ((ziszero(z1) && !ziszero(z2)) || zisunit(z3)) {
/* 0^(non_zero) or x^y mod 1 always produces zero */
*res = _zero_;
return;
}
if (ziszero(z2)) { /* x^0 == 1 */
*res = _one_;
return;
}
if (zistwo(z3)) { /* mod 2 */
if (zisodd(z1))
*res = _one_;
else
*res = _zero_;
return;
}
if (zisunit(z1) && (!z1.sign || ziseven(z2))) {
/* 1^x or (-1)^(2x) */
*res = _one_;
return;
}
/*
* Normalize the number being raised to be non-negative and to lie
* within the modulo range. Then check for zero or one specially.
*/
ztmp.len = 0;
if (zisneg(z1) || zrel(z1, z3) >= 0) {
zmod(z1, z3, &ztmp, 0);
z1 = ztmp;
}
if (ziszero(z1)) {
if (ztmp.len)
zfree(ztmp);
*res = _zero_;
return;
}
if (zisone(z1)) {
if (ztmp.len)
zfree(ztmp);
*res = _one_;
return;
}
/*
* If modulus is large enough use zmod5
*/
if (z3.len >= conf->pow2) {
if (havelastmod && zcmp(z3, *lastmod)) {
zfree(*lastmod);
zfree(*lastmodinv);
havelastmod = FALSE;
}
if (!havelastmod) {
zcopy(z3, lastmod);
zbitvalue(2 * z3.len * BASEB, &temp);
zquo(temp, z3, lastmodinv, 0);
zfree(temp);
havelastmod = TRUE;
}
/* zzz */
for (pp = &lowpowers[2]; pp <= &lowpowers[POWNUMS-1]; pp++) {
pp->len = 0;
pp->v = NULL;
}
lowpowers[0] = _one_;
lowpowers[1] = z1;
ans = _one_;
hp = &z2.v[z2.len - 1];
curhalf = *hp;
curshift = BASEB - POWBITS;
while (curshift && ((curhalf >> curshift) == 0))
curshift -= POWBITS;
/*
* Calculate the result by examining the power POWBITS bits at
* a time, and use the table of low powers at each iteration.
*/
for (;;) {
curpow = (curhalf >> curshift) & (POWNUMS - 1);
pp = &lowpowers[curpow];
/*
* If the small power is not yet saved in the table,
* then calculate it and remember it in the table for
* future use.
*/
if (pp->v == NULL) {
if (curpow & 0x1)
zcopy(z1, &modpow);
else
modpow = _one_;
for (curbit = 0x2;
curbit <= curpow;
curbit *= 2) {
pp = &lowpowers[curbit];
if (pp->v == NULL) {
zsquare(lowpowers[curbit/2],
&temp);
zmod5(&temp);
zcopy(temp, pp);
zfree(temp);
}
if (curbit & curpow) {
zmul(*pp, modpow, &temp);
zfree(modpow);
zmod5(&temp);
zcopy(temp, &modpow);
zfree(temp);
}
}
pp = &lowpowers[curpow];
if (pp->v != NULL) {
zfree(*pp);
}
*pp = modpow;
}
/*
* If the power is nonzero, then accumulate the small
* power into the result.
*/
if (curpow) {
zmul(ans, *pp, &temp);
zfree(ans);
zmod5(&temp);
zcopy(temp, &ans);
zfree(temp);
}
/*
* Select the next POWBITS bits of the power, if
* there is any more to generate.
*/
curshift -= POWBITS;
if (curshift < 0) {
if (hp == z2.v)
break;
curhalf = *--hp;
curshift = BASEB - POWBITS;
}
/*
* Square the result POWBITS times to make room for
* the next chunk of bits.
*/
for (i = 0; i < POWBITS; i++) {
zsquare(ans, &temp);
zfree(ans);
zmod5(&temp);
zcopy(temp, &ans);
zfree(temp);
}
}
for (pp = &lowpowers[2]; pp <= &lowpowers[POWNUMS-1]; pp++) {
if (pp->v != NULL)
freeh(pp->v);
}
*res = ans;
if (ztmp.len)
zfree(ztmp);
return;
}
/*
* If the modulus is odd and small enough then use
* the REDC algorithm. The size where this is done is configurable.
*/
if (z3.len < conf->redc2 && zisodd(z3)) {
if (powermodredc && zcmp(powermodredc->mod, z3)) {
zredcfree(powermodredc);
powermodredc = NULL;
}
if (powermodredc == NULL)
powermodredc = zredcalloc(z3);
rp = powermodredc;
zredcencode(rp, z1, &temp);
zredcpower(rp, temp, z2, &z1);
zfree(temp);
zredcdecode(rp, z1, res);
zfree(z1);
return;
}
/*
* Modulus or power is small enough to perform the power raising
* directly. Initialize the table of powers.
*/
for (pp = &lowpowers[2]; pp <= &lowpowers[POWNUMS-1]; pp++) {
pp->len = 0;
pp->v = NULL;
}
lowpowers[0] = _one_;
lowpowers[1] = z1;
ans = _one_;
hp = &z2.v[z2.len - 1];
curhalf = *hp;
curshift = BASEB - POWBITS;
while (curshift && ((curhalf >> curshift) == 0))
curshift -= POWBITS;
/*
* Calculate the result by examining the power POWBITS bits at a time,
* and use the table of low powers at each iteration.
*/
for (;;) {
curpow = (curhalf >> curshift) & (POWNUMS - 1);
pp = &lowpowers[curpow];
/*
* If the small power is not yet saved in the table, then
* calculate it and remember it in the table for future use.
*/
if (pp->v == NULL) {
if (curpow & 0x1)
zcopy(z1, &modpow);
else
modpow = _one_;
for (curbit = 0x2; curbit <= curpow; curbit *= 2) {
pp = &lowpowers[curbit];
if (pp->v == NULL) {
zsquare(lowpowers[curbit/2], &temp);
zmod(temp, z3, pp, 0);
zfree(temp);
}
if (curbit & curpow) {
zmul(*pp, modpow, &temp);
zfree(modpow);
zmod(temp, z3, &modpow, 0);
zfree(temp);
}
}
pp = &lowpowers[curpow];
if (pp->v != NULL) {
zfree(*pp);
}
*pp = modpow;
}
/*
* If the power is nonzero, then accumulate the small power
* into the result.
*/
if (curpow) {
zmul(ans, *pp, &temp);
zfree(ans);
zmod(temp, z3, &ans, 0);
zfree(temp);
}
/*
* Select the next POWBITS bits of the power, if there is
* any more to generate.
*/
curshift -= POWBITS;
if (curshift < 0) {
if (hp-- == z2.v)
break;
curhalf = *hp;
curshift = BASEB - POWBITS;
}
/*
* Square the result POWBITS times to make room for the next
* chunk of bits.
*/
for (i = 0; i < POWBITS; i++) {
zsquare(ans, &temp);
zfree(ans);
zmod(temp, z3, &ans, 0);
zfree(temp);
}
}
for (pp = &lowpowers[2]; pp <= &lowpowers[POWNUMS-1]; pp++) {
if (pp->v != NULL)
freeh(pp->v);
}
*res = ans;
if (ztmp.len)
zfree(ztmp);
}
/*
* Given a positive odd N-word integer z, evaluate minv(-z, BASEB^N)
*/
static void
zredcmodinv(ZVALUE z, ZVALUE *res)
{
ZVALUE tmp;
HALF *a0, *a, *b;
HALF bit, h, inv, v;
FULL f;
LEN N, i, j, len;
N = z.len;
tmp.sign = 0;
tmp.len = N;
tmp.v = alloc(N);
zclearval(tmp);
*tmp.v = 1;
h = 1 + *z.v;
bit = 1;
inv = 1;
while (h) {
bit <<= 1;
if (bit & h) {
inv |= bit;
h += bit * *z.v;
}
}
j = N;
a0 = tmp.v;
while (j-- > 0) {
v = inv * *a0;
i = j;
a = a0;
b = z.v;
f = (FULL) v * (FULL) *b++ + (FULL) *a++;
*a0 = v;
while (i-- > 0) {
f = (FULL) v * (FULL) *b++ + (FULL) *a + (f >> BASEB);
*a++ = (HALF) f;
}
while (j > 0 && *++a0 == 0)
j--;
}
a = tmp.v + N;
len = N;
while (*--a == 0)
len--;
tmp.len = len;
zcopy(tmp, res);
zfree(tmp);
}
/*
* Initialize the REDC algorithm for a particular modulus,
* returning a pointer to a structure that is used for other
* REDC calls. An error is generated if the structure cannot
* be allocated. The modulus must be odd and positive.
*
* given:
* z1 modulus to initialize for
*/
REDC *
zredcalloc(ZVALUE z1)
{
REDC *rp; /* REDC information */
ZVALUE tmp;
long bit;
if (ziseven(z1) || zisneg(z1)) {
math_error("REDC requires positive odd modulus");
/*NOTREACHED*/
}
rp = (REDC *) malloc(sizeof(REDC));
if (rp == NULL) {
math_error("Cannot allocate REDC structure");
/*NOTREACHED*/
}
/*
* Round up the binary modulus to the next power of two
* which is at a word boundary. Then the shift and modulo
* operations mod the binary modulus can be done very cheaply.
* Calculate the REDC format for the number 1 for future use.
*/
zcopy(z1, &rp->mod);
zredcmodinv(z1, &rp->inv);
bit = zhighbit(z1) + 1;
if (bit % BASEB)
bit += (BASEB - (bit % BASEB));
zbitvalue(bit, &tmp);
zmod(tmp, rp->mod, &rp->one, 0);
zfree(tmp);
rp->len = (LEN)(bit / BASEB);
return rp;
}
/*
* Free any numbers associated with the specified REDC structure,
* and then the REDC structure itself.
*
* given:
* rp REDC information to be cleared
*/
void
zredcfree(REDC *rp)
{
zfree(rp->mod);
zfree(rp->inv);
zfree(rp->one);
free(rp);
}
/*
* Convert a normal number into the specified REDC format.
* The number to be converted can be negative or out of modulo range.
* The resulting number can be used for multiplying, adding, subtracting,
* or comparing with any other such converted numbers, as if the numbers
* were being calculated modulo the number which initialized the REDC
* information. When the final value is unconverted, the result is the
* same as if the usual operations were done with the original numbers.
*
* given:
* rp REDC information
* z1 number to be converted
* res returned converted number
*/
void
zredcencode(REDC *rp, ZVALUE z1, ZVALUE *res)
{
ZVALUE tmp1;
/*
* Confirm or initialize lastmod information when modulus is a
* big number.
*/
if (rp->len >= conf->pow2) {
if (havelastmod && zcmp(rp->mod, *lastmod)) {
zfree(*lastmod);
zfree(*lastmodinv);
havelastmod = FALSE;
}
if (!havelastmod) {
zcopy(rp->mod, lastmod);
zbitvalue(2 * rp->len * BASEB, &tmp1);
zquo(tmp1, rp->mod, lastmodinv, 0);
zfree(tmp1);
havelastmod = TRUE;
}
}
/*
* Handle the cases 0, 1, -1, and 2 specially since these are
* easy to calculate. Zero transforms to zero, and the others
* can be obtained from the precomputed REDC format for 1 since
* addition and subtraction act normally for REDC format numbers.
*/
if (ziszero(z1)) {
*res = _zero_;
return;
}
if (zisone(z1)) {
zcopy(rp->one, res);
return;
}
if (zisunit(z1)) {
zsub(rp->mod, rp->one, res);
return;
}
if (zistwo(z1)) {
zadd(rp->one, rp->one, &tmp1);
if (zrel(tmp1, rp->mod) < 0) {
*res = tmp1;
return;
}
zsub(tmp1, rp->mod, res);
zfree(tmp1);
return;
}
/*
* Not a trivial number to convert, so do the full transformation.
*/
zshift(z1, rp->len * BASEB, &tmp1);
if (rp->len < conf->pow2)
zmod(tmp1, rp->mod, res, 0);
else
zmod6(tmp1, res);
zfree(tmp1);
}
/*
* The REDC algorithm used to convert numbers out of REDC format and also
* used after multiplication of two REDC numbers. Using this routine
* avoids any divides, replacing the divide by two multiplications.
* If the numbers are very large, then these two multiplies will be
* quicker than the divide, since dividing is harder than multiplying.
*
* given:
* rp REDC information
* z1 number to be transformed
* res returned transformed number
*/
void
zredcdecode(REDC *rp, ZVALUE z1, ZVALUE *res)
{
ZVALUE tmp1, tmp2;
ZVALUE ztmp;
ZVALUE ztop;
ZVALUE zp1;
FULL muln;
HALF *h1;
HALF *h3;
HALF *hd = NULL;
HALF Ninv;
LEN modlen;
LEN len;
FULL f;
int sign;
int i, j;
/*
* Check first for the special values for 0 and 1 that are easy.
*/
if (ziszero(z1)) {
*res = _zero_;
return;
}
if ((z1.len == rp->one.len) && (z1.v[0] == rp->one.v[0]) &&
(zcmp(z1, rp->one) == 0)) {
*res = _one_;
return;
}
ztop.len = 0;
ztmp.len = 0;
modlen = rp->len;
sign = z1.sign;
z1.sign = 0;
if (z1.len > modlen) {
ztop.v = z1.v + modlen;
ztop.len = z1.len - modlen;
ztop.sign = 0;
if (zrel(ztop, rp->mod) >= 0) {
zmod(ztop, rp->mod, &ztmp, 0);
ztop = ztmp;
}
len = modlen;
h1 = z1.v + len;
while (len > 0 && *--h1 == 0)
len--;
if (len == 0) {
if (ztmp.len)
*res = ztmp;
else
zcopy(ztop, res);
return;
}
z1.len = len;
}
if (rp->mod.len < conf->pow2) {
Ninv = rp->inv.v[0];
res->sign = 0;
res->len = modlen;
res->v = alloc(modlen);
zclearval(*res);
h1 = z1.v;
for (i = 0; i < modlen; i++) {
h3 = rp->mod.v;
hd = res->v;
f = (FULL) *hd++;
if (i < z1.len)
f += (FULL) *h1++;
muln = (HALF) ((f & BASE1) * Ninv);
f = ((muln * (FULL) *h3++) + f) >> BASEB;
j = modlen;
while (--j > 0) {
f += (muln * (FULL) *h3++) + (FULL) *hd;
hd[-1] = (HALF) f;
f >>= BASEB;
hd++;
}
hd[-1] = (HALF) f;
}
len = modlen;
while (*--hd == 0 && len > 1)
len--;
if (len == 0)
len = 1;
res->len = len;
} else {
/* Here 0 < z1 < 2^bitnum */
/*
* First calculate the following:
* tmp2 = ((z1 * inv) % 2^bitnum.
* The mod operations can be done with no work since the bit
* number was selected as a multiple of the word size. Just
* reduce the sizes of the numbers as required.
*/
zmul(z1, rp->inv, &tmp2);
if (tmp2.len > modlen) {
h1 = tmp2.v + modlen;
len = modlen;
while (len > 0 && *--h1 == 0)
len--;
tmp2.len = len;
}
/*
* Next calculate the following:
* res = (z1 + tmp2 * modulus) / 2^bitnum
* Since 0 < z1 < 2^bitnum and the division is always exact,
* the quotient can be evaluated by rounding up
* (tmp2 * modulus)/2^bitnum. This can be achieved by defining
* zp1 by an appropriate shift and then adding one.
*/
zmul(tmp2, rp->mod, &tmp1);
zfree(tmp2);
if (tmp1.len > modlen) {
zp1.v = tmp1.v + modlen;
zp1.len = tmp1.len - modlen;
zp1.sign = 0;
zadd(zp1, _one_, res);
} else {
*res = _one_;
}
zfree(tmp1);
}
if (ztop.len) {
zadd(*res, ztop, &tmp1);
zfree(*res);
if (ztmp.len)
zfree(ztmp);
*res = tmp1;
}
/*
* Finally do a final modulo by a simple subtraction if necessary.
* This is all that is needed because the previous calculation is
* guaranteed to always be less than twice the modulus.
*/
if (zrel(*res, rp->mod) >= 0) {
zsub(*res, rp->mod, &tmp1);
zfree(*res);
*res = tmp1;
}
if (sign && !ziszero(*res)) {
zsub(rp->mod, *res, &tmp1);
zfree(*res);
*res = tmp1;
}
return;
}
/*
* Multiply two numbers in REDC format together producing a result also
* in REDC format. If the result is converted back to a normal number,
* then the result is the same as the modulo'd multiplication of the
* original numbers before they were converted to REDC format. This
* calculation is done in one of two ways, depending on the size of the
* modulus. For large numbers, the REDC definition is used directly
* which involves three multiplies overall. For small numbers, a
* complicated routine is used which does the indicated multiplication
* and the REDC algorithm at the same time to produce the result.
*
* given:
* rp REDC information
* z1 first REDC number to be multiplied
* z2 second REDC number to be multiplied
* res resulting REDC number
*/
void
zredcmul(REDC *rp, ZVALUE z1, ZVALUE z2, ZVALUE *res)
{
FULL mulb;
FULL muln;
HALF *h1;
HALF *h2;
HALF *h3;
HALF *hd;
HALF Ninv;
HALF topdigit = 0;
LEN modlen;
LEN len;
LEN len2;
SIUNION sival1;
SIUNION sival2;
SIUNION carry;
ZVALUE tmp;
ZVALUE z1tmp, z2tmp;
int sign;
sign = z1.sign ^ z2.sign;
z1.sign = 0;
z2.sign = 0;
z1tmp.len = 0;
if (zrel(z1, rp->mod) >= 0) {
zmod(z1, rp->mod, &z1tmp, 0);
z1 = z1tmp;
}
z2tmp.len = 0;
if (zrel(z2, rp->mod) >= 0) {
zmod(z2, rp->mod, &z2tmp, 0);
z2 = z2tmp;
}
/*
* Check for special values which we easily know the answer.
*/
if (ziszero(z1) || ziszero(z2)) {
*res = _zero_;
if (z1tmp.len)
zfree(z1tmp);
if (z2tmp.len)
zfree(z2tmp);
return;
}
if ((z1.len == rp->one.len) && (z1.v[0] == rp->one.v[0]) &&
(zcmp(z1, rp->one) == 0)) {
if (sign)
zsub(rp->mod, z2, res);
else
zcopy(z2, res);
if (z1tmp.len)
zfree(z1tmp);
if (z2tmp.len)
zfree(z2tmp);
return;
}
if ((z2.len == rp->one.len) && (z2.v[0] == rp->one.v[0]) &&
(zcmp(z2, rp->one) == 0)) {
if (sign)
zsub(rp->mod, z1, res);
else
zcopy(z1, res);
if (z1tmp.len)
zfree(z1tmp);
if (z2tmp.len)
zfree(z2tmp);
return;
}
/*
* If the size of the modulus is large, then just do the multiply,
* followed by the two multiplies contained in the REDC routine.
* This will be quicker than directly doing the REDC calculation
* because of the O(N^1.585) speed of the multiplies. The size
* of the number which this is done is configurable.
*/
if (rp->mod.len >= conf->redc2) {
zmul(z1, z2, &tmp);
zredcdecode(rp, tmp, res);
zfree(tmp);
if (sign && !ziszero(*res)) {
zsub(rp->mod, *res, &tmp);
zfree(*res);
*res = tmp;
}
if (z1tmp.len)
zfree(z1tmp);
if (z2tmp.len)
zfree(z2tmp);
return;
}
/*
* The number is small enough to calculate by doing the O(N^2) REDC
* algorithm directly. This algorithm performs the multiplication and
* the reduction at the same time. Notice the obscure facts that
* only the lowest word of the inverse value is used, and that
* there is no shifting of the partial products as there is in a
* normal multiply.
*/
modlen = rp->mod.len;
Ninv = rp->inv.v[0];
/*
* Allocate the result and clear it.
* The size of the result will be equal to or smaller than
* the modulus size.
*/
res->sign = 0;
res->len = modlen;
res->v = alloc(modlen);
hd = res->v;
len = modlen;
zclearval(*res);
/*
* Do this outermost loop over all the digits of z1.
*/
h1 = z1.v;
len = z1.len;
while (len--) {
/*
* Start off with the next digit of z1, the first
* digit of z2, and the first digit of the modulus.
*/
mulb = (FULL) *h1++;
h2 = z2.v;
h3 = rp->mod.v;
hd = res->v;
sival1.ivalue = mulb * ((FULL) *h2++) + ((FULL) *hd++);
muln = ((HALF) (sival1.silow * Ninv));
sival2.ivalue = muln * ((FULL) *h3++) + ((FULL) sival1.silow);
carry.ivalue = ((FULL) sival1.sihigh) + ((FULL) sival2.sihigh);
/*
* Do this innermost loop for each digit of z2, except
* for the first digit which was just done above.
*/
len2 = z2.len;
while (--len2 > 0) {
sival1.ivalue = mulb * ((FULL) *h2++)
+ ((FULL) *hd) + ((FULL) carry.silow);
sival2.ivalue = muln * ((FULL) *h3++)
+ ((FULL) sival1.silow);
carry.ivalue = ((FULL) sival1.sihigh)
+ ((FULL) sival2.sihigh)
+ ((FULL) carry.sihigh);
hd[-1] = sival2.silow;
hd++;
}
/*
* Now continue the loop as necessary so the total number
* of iterations is equal to the size of the modulus.
* This acts as if the innermost loop was repeated for
* high digits of z2 that are zero.
*/
len2 = modlen - z2.len;
while (len2--) {
sival2.ivalue = muln * ((FULL) *h3++)
+ ((FULL) *hd)
+ ((FULL) carry.silow);
carry.ivalue = ((FULL) sival2.sihigh)
+ ((FULL) carry.sihigh);
hd[-1] = sival2.silow;
hd++;
}
carry.ivalue += topdigit;
hd[-1] = carry.silow;
topdigit = carry.sihigh;
}
/*
* Now continue the loop as necessary so the total number
* of iterations is equal to the size of the modulus.
* This acts as if the outermost loop was repeated for high
* digits of z1 that are zero.
*/
len = modlen - z1.len;
while (len--) {
/*
* Start off with the first digit of the modulus.
*/
h3 = rp->mod.v;
hd = res->v;
muln = ((HALF) (*hd * Ninv));
sival2.ivalue = muln * ((FULL) *h3++) + (FULL) *hd++;
carry.ivalue = ((FULL) sival2.sihigh);
/*
* Do this innermost loop for each digit of the modulus,
* except for the first digit which was just done above.
*/
len2 = modlen;
while (--len2 > 0) {
sival2.ivalue = muln * ((FULL) *h3++)
+ ((FULL) *hd) + ((FULL) carry.silow);
carry.ivalue = ((FULL) sival2.sihigh)
+ ((FULL) carry.sihigh);
hd[-1] = sival2.silow;
hd++;
}
carry.ivalue += topdigit;
hd[-1] = carry.silow;
topdigit = carry.sihigh;
}
/*
* Determine the true size of the result, taking the top digit of
* the current result into account. The top digit is not stored in
* the number because it is temporary and would become zero anyway
* after the final subtraction is done.
*/
if (topdigit == 0) {
len = modlen;
while (*--hd == 0 && len > 1) {
len--;
}
res->len = len;
/*
* Compare the result with the modulus.
* If it is less than the modulus, then the calculation is complete.
*/
if (zrel(*res, rp->mod) < 0) {
if (z1tmp.len)
zfree(z1tmp);
if (z2tmp.len)
zfree(z2tmp);
if (sign && !ziszero(*res)) {
zsub(rp->mod, *res, &tmp);
zfree(*res);
*res = tmp;
}
return;
}
}
/*
* Do a subtraction to reduce the result to a value less than
* the modulus. The REDC algorithm guarantees that a single subtract
* is all that is needed. Ignore any borrowing from the possible
* highest word of the current result because that would affect
* only the top digit value that was not stored and would become
* zero anyway.
*/
carry.ivalue = 0;
h1 = rp->mod.v;
hd = res->v;
len = modlen;
while (len--) {
carry.ivalue = BASE1 - ((FULL) *hd) + ((FULL) *h1++)
+ ((FULL) carry.silow);
*hd++ = (HALF)(BASE1 - carry.silow);
carry.silow = carry.sihigh;
}
/*
* Now finally recompute the size of the result.
*/
len = modlen;
hd = &res->v[len - 1];
while ((*hd == 0) && (len > 1)) {
hd--;
len--;
}
res->len = len;
if (z1tmp.len)
zfree(z1tmp);
if (z2tmp.len)
zfree(z2tmp);
if (sign && !ziszero(*res)) {
zsub(rp->mod, *res, &tmp);
zfree(*res);
*res = tmp;
}
}
/*
* Square a number in REDC format producing a result also in REDC format.
*
* given:
* rp REDC information
* z1 REDC number to be squared
* res resulting REDC number
*/
void
zredcsquare(REDC *rp, ZVALUE z1, ZVALUE *res)
{
FULL mulb;
FULL muln;
HALF *h1;
HALF *h2;
HALF *h3;
HALF *hd = NULL;
HALF Ninv;
HALF topdigit = 0;
LEN modlen;
LEN len;
SIUNION sival1;
SIUNION sival2;
SIUNION sival3;
SIUNION carry;
ZVALUE tmp, ztmp;
FULL f;
int i, j;
ztmp.len = 0;
z1.sign = 0;
if (zrel(z1, rp->mod) >= 0) {
zmod(z1, rp->mod, &ztmp, 0);
z1 = ztmp;
}
if (ziszero(z1)) {
*res = _zero_;
if (ztmp.len)
zfree(ztmp);
return;
}
if ((z1.len == rp->one.len) && (z1.v[0] == rp->one.v[0]) &&
(zcmp(z1, rp->one) == 0)) {
zcopy(z1, res);
if (ztmp.len)
zfree(ztmp);
return;
}
/*
* If the modulus is small enough, then call the multiply
* routine to produce the result. Otherwise call the O(N^1.585)
* routines to get the answer.
*/
if (rp->mod.len >= conf->redc2
|| 3 * z1.len < 2 * rp->mod.len) {
zsquare(z1, &tmp);
zredcdecode(rp, tmp, res);
zfree(tmp);
if (ztmp.len)
zfree(ztmp);
return;
}
modlen = rp->mod.len;
Ninv = rp->inv.v[0];
res->sign = 0;
res->len = modlen;
res->v = alloc(modlen);
zclearval(*res);
h1 = z1.v;
for (i = 0; i < z1.len; i++) {
mulb = (FULL) *h1++;
h2 = h1;
h3 = rp->mod.v;
hd = res->v;
if (i == 0) {
sival1.ivalue = mulb * mulb;
muln = (HALF) (sival1.silow * Ninv);
sival2.ivalue = muln * ((FULL) *h3++)
+ (FULL) sival1.silow;
carry.ivalue = (FULL) sival1.sihigh
+ (FULL) sival2.sihigh;
hd++;
} else {
muln = (HALF) (*hd * Ninv);
f = (muln * ((FULL) *h3++) + (FULL) *hd++) >> BASEB;
j = i;
while (--j > 0) {
f += muln * ((FULL) *h3++) + *hd;
hd[-1] = (HALF) f;
f >>= BASEB;
hd++;
}
carry.ivalue = f;
sival1.ivalue = mulb * mulb + (FULL) carry.silow;
sival2.ivalue = muln * ((FULL) *h3++)
+ (FULL) *hd
+ (FULL) sival1.silow;
carry.ivalue = (FULL) sival1.sihigh
+ (FULL) sival2.sihigh
+ (FULL) carry.sihigh;
hd[-1] = sival2.silow;
hd++;
}
j = z1.len - i;
while (--j > 0) {
sival1.ivalue = mulb * ((FULL) *h2++);
sival2.ivalue = ((FULL) sival1.silow << 1)
+ muln * ((FULL) *h3++);
sival3.ivalue = (FULL) sival2.silow
+ (FULL) *hd
+ (FULL) carry.silow;
carry.ivalue = ((FULL) sival1.sihigh << 1)
+ (FULL) sival2.sihigh
+ (FULL) sival3.sihigh
+ (FULL) carry.sihigh;
hd[-1] = sival3.silow;
hd++;
}
j = modlen - z1.len;
while (j-- > 0) {
sival1.ivalue = muln * ((FULL) *h3++)
+ (FULL) *hd
+ (FULL) carry.silow;
carry.ivalue = (FULL) sival1.sihigh
+ (FULL) carry.sihigh;
hd[-1] = sival1.silow;
hd++;
}
carry.ivalue += (FULL) topdigit;
hd[-1] = carry.silow;
topdigit = carry.sihigh;
}
i = modlen - z1.len;
while (i-- > 0) {
h3 = rp->mod.v;
hd = res->v;
muln = (HALF) (*hd * Ninv);
sival1.ivalue = muln * ((FULL) *h3++) + (FULL) *hd++;
carry.ivalue = (FULL) sival1.sihigh;
j = modlen;
while (--j > 0) {
sival1.ivalue = muln * ((FULL) *h3++)
+ (FULL) *hd
+ (FULL) carry.silow;
carry.ivalue = (FULL) sival1.sihigh
+ (FULL) carry.sihigh;
hd[-1] = sival1.silow;
hd++;
}
carry.ivalue += (FULL) topdigit;
hd[-1] = carry.silow;
topdigit = carry.sihigh;
}
if (topdigit == 0) {
len = modlen;
while (*--hd == 0 && len > 1) {
len--;
}
res->len = len;
if (zrel(*res, rp->mod) < 0) {
if (ztmp.len)
zfree(ztmp);
return;
}
}
carry.ivalue = 0;
h1 = rp->mod.v;
hd = res->v;
len = modlen;
while (len--) {
carry.ivalue = BASE1 - ((FULL) *hd) + ((FULL) *h1++)
+ ((FULL) carry.silow);
*hd++ = (HALF)(BASE1 - carry.silow);
carry.silow = carry.sihigh;
}
len = modlen;
hd = &res->v[len - 1];
while ((*hd == 0) && (len > 1)) {
hd--;
len--;
}
res->len = len;
if (ztmp.len)
zfree(ztmp);
}
/*
* Compute the result of raising a REDC format number to a power.
* The result is within the range 0 to the modulus - 1.
* This calculates the result by examining the power POWBITS bits at a time,
* using a small table of POWNUMS low powers to calculate powers for those bits,
* and repeated squaring and multiplying by the partial powers to generate
* the complete power.
*
* given:
* rp REDC information
* z1 REDC number to be raised
* z2 normal number to raise number to
* res result
*/
void
zredcpower(REDC *rp, ZVALUE z1, ZVALUE z2, ZVALUE *res)
{
HALF *hp; /* pointer to current word of the power */
ZVALUE *pp; /* pointer to low power table */
ZVALUE ans, temp; /* calculation values */
ZVALUE ztmp;
ZVALUE modpow; /* current small power */
ZVALUE lowpowers[POWNUMS]; /* low powers */
int curshift; /* shift value for word of power */
HALF curhalf; /* current word of power */
unsigned int curpow; /* current low power */
unsigned int curbit; /* current bit of low power */
int sign;
int i;
if (zisneg(z2)) {
math_error("Negative power in zredcpower");
/*NOTREACHED*/
}
if (zisunit(rp->mod)) {
*res = _zero_;
return;
}
sign = zisodd(z2) ? z1.sign : 0;
z1.sign = 0;
ztmp.len = 0;
if (zrel(z1, rp->mod) >= 0) {
zmod(z1, rp->mod, &ztmp, 0);
z1 = ztmp;
}
/*
* Check for zero or the REDC format for one.
*/
if (ziszero(z1)) {
if (ziszero(z2))
*res = _one_;
else
*res = _zero_;
if (ztmp.len)
zfree(ztmp);
return;
}
if (zcmp(z1, rp->one) == 0) {
if (sign)
zsub(rp->mod, rp->one, res);
else
zcopy(rp->one, res);
if (ztmp.len)
zfree(ztmp);
return;
}
/*
* See if the number being raised is the REDC format for -1.
* If so, then the answer is the REDC format for one or minus one.
* To do this check, calculate the REDC format for -1.
*/
if (((HALF)(z1.v[0] + rp->one.v[0])) == rp->mod.v[0]) {
zsub(rp->mod, rp->one, &temp);
if (zcmp(z1, temp) == 0) {
if (zisodd(z2) ^ sign) {
*res = temp;
if (ztmp.len)
zfree(ztmp);
return;
}
zfree(temp);
zcopy(rp->one, res);
if (ztmp.len)
zfree(ztmp);
return;
}
zfree(temp);
}
for (pp = &lowpowers[2]; pp < &lowpowers[POWNUMS]; pp++)
pp->len = 0;
zcopy(rp->one, &lowpowers[0]);
zcopy(z1, &lowpowers[1]);
zcopy(rp->one, &ans);
hp = &z2.v[z2.len - 1];
curhalf = *hp;
curshift = BASEB - POWBITS;
while (curshift && ((curhalf >> curshift) == 0))
curshift -= POWBITS;
/*
* Calculate the result by examining the power POWBITS bits at a time,
* and use the table of low powers at each iteration.
*/
for (;;) {
curpow = (curhalf >> curshift) & (POWNUMS - 1);
pp = &lowpowers[curpow];
/*
* If the small power is not yet saved in the table, then
* calculate it and remember it in the table for future use.
*/
if (pp->len == 0) {
if (curpow & 0x1)
zcopy(z1, &modpow);
else
zcopy(rp->one, &modpow);
for (curbit = 0x2; curbit <= curpow; curbit *= 2) {
pp = &lowpowers[curbit];
if (pp->len == 0)
zredcsquare(rp, lowpowers[curbit/2],
pp);
if (curbit & curpow) {
zredcmul(rp, *pp, modpow, &temp);
zfree(modpow);
modpow = temp;
}
}
pp = &lowpowers[curpow];
if (pp->len > 0) {
zfree(*pp);
}
*pp = modpow;
}
/*
* If the power is nonzero, then accumulate the small power
* into the result.
*/
if (curpow) {
zredcmul(rp, ans, *pp, &temp);
zfree(ans);
ans = temp;
}
/*
* Select the next POWBITS bits of the power, if there is
* any more to generate.
*/
curshift -= POWBITS;
if (curshift < 0) {
if (hp-- == z2.v)
break;
curhalf = *hp;
curshift = BASEB - POWBITS;
}
/*
* Square the result POWBITS times to make room for the next
* chunk of bits.
*/
for (i = 0; i < POWBITS; i++) {
zredcsquare(rp, ans, &temp);
zfree(ans);
ans = temp;
}
}
for (pp = lowpowers; pp < &lowpowers[POWNUMS]; pp++) {
if (pp->len)
freeh(pp->v);
}
if (sign && !ziszero(ans)) {
zsub(rp->mod, ans, res);
zfree(ans);
} else {
*res = ans;
}
if (ztmp.len)
zfree(ztmp);
}
/*
* zhnrmod - compute z mod h*2^n+r
*
* We compute v mod h*2^n+r, where h>0, n>0, abs(r) <= 1, as follows:
*
* Let v = b*2^n + a, where 0 <= a < 2^n
*
* Now v mod h*2^n+r == b*2^n + a mod h*2^n+r,
* and thus v mod h*2^n+r == b*2^n mod h*2^n+r + a mod h*2^n+r.
*
* Because 0 <= a < 2^n < h*2^n+r, a mod h*2^n+r == a.
* Thus v mod h*2^n+r == b*2^n mod h*2^n+r + a.
*
* It can be shown that b*2^n mod h*2^n == 2^n * (b mod h).
*
* Thus for r == 0, v mod h*2^n+r == (2^n)*(b mod h) + a.
*
* It can be shown that v mod 2^n-1 == a+b mod 2^n-1.
*
* Thus for r == -1, v mod h*2^n+r == (2^n)*(b mod h) + a + int(b/h).
*
* It can be shown that v mod 2^n+1 == a-b mod 2^n+1.
*
* Thus for r == +1, v mod h*2^n+r == (2^n)*(b mod h) + a - int(b/h).
*
* Therefore, v mod h*2^n+r == (2^n)*(b mod h) + a - r*int(b/h).
*
* The above proof leads to the following calc resource file which computes
* the value z mod h*2^n+r:
*
* define hnrmod(v,h,n,r)
* {
* local a,b,modulus,tquo,tmod,lbit,ret;
*
* if (!isint(h) || h < 1) {
* quit "h must be an integer be > 0";
* }
* if (!isint(n) || n < 1) {
* quit "n must be an integer be > 0";
* }
* if (r != 1 && r != 0 && r != -1) {
* quit "r must be -1, 0 or 1";
* }
*
* lbit = lowbit(h);
* if (lbit > 0) {
* n += lbit;
* h >>= lbit;
* }
*
* modulus = h<<n+r;
* if (modulus <= 2^31-1) {
* return v % modulus;
* }
* ret = v;
*
* do {
* if (highbit(ret) < n) {
* break;
* }
* b = ret>>n;
* a = ret - (b<<n);
*
* switch (r) {
* case -1:
* if (h == 1) {
* ret = a + b;
* } else {
* quomod(b, h, tquo, tmod);
* ret = tmod<<n + a + tquo;
* }
* break;
* case 0:
* if (h == 1) {
* ret = a;
* } else {
* ret = (b%h)<<n + a;
* }
* break;
* case 1:
* if (h == 1) {
* ret = ((a > b) ? a-b : modulus+a-b);
* } else {
* quomod(b, h, tquo, tmod);
* tmod = tmod<<n + a;
* ret = ((tmod >= tquo) ? tmod-tquo : modulus+tmod-tquo);
* }
* break;
* }
* } while (ret > modulus);
* ret = ((ret < 0) ? ret+modlus : ((ret == modulus) ? 0 : ret));
*
* return ret;
* }
*
* This function implements the above calc resource file.
*
* given:
* v take mod of this value, v >= 0
* zh h from modulus h*2^n+r, h > 0
* zn n from modulus h*2^n+r, n > 0
* zr r from modulus h*2^n+r, abs(r) <= 1
* res v mod h*2^n+r
*/
void
zhnrmod(ZVALUE v, ZVALUE zh, ZVALUE zn, ZVALUE zr, ZVALUE *res)
{
ZVALUE a; /* lower n bits of v */
ZVALUE b; /* bits above the lower n bits of v */
ZVALUE h; /* working zh value */
ZVALUE modulus; /* h^2^n + r */
ZVALUE tquo; /* b // h */
ZVALUE tmod; /* b % h or (b%h)<<n + a */
ZVALUE t; /* temp ZVALUE */
ZVALUE t2; /* temp ZVALUE */
ZVALUE ret; /* return value, what *res is set to */
long n; /* integer value of zn */
long r; /* integer value of zr */
long hbit; /* highbit(res) */
long lbit; /* lowbit(h) */
int zrelval; /* return value of zrel() */
int hisone; /* 1 => h == 1, 0 => h != 1 */
/*
* firewall
*/
if (zisneg(zh) || ziszero(zh)) {
math_error("h must be > 0");
/*NOTREACHED*/
}
if (zisneg(zn) || ziszero(zn)) {
math_error("n must be > 0");
/*NOTREACHED*/
}
if (zge31b(zn)) {
math_error("n must be < 2^31");
/*NOTREACHED*/
}
if (!zisabsleone(zr)) {
math_error("r must be -1, 0 or 1");
/*NOTREACHED*/
}
/*
* setup for loop
*/
n = ztolong(zn);
r = ztolong(zr);
if (zisneg(zr)) {
r = -r;
}
/* lbit = lowbit(h); */
lbit = zlowbit(zh);
/* if (lbit > 0) { n += lbit; h >>= lbit; } */
if (lbit > 0) {
n += lbit;
zshift(zh, -lbit, &h);
} else {
h = zh;
}
/* modulus = h<<n+r; */
zshift(h, n, &t);
switch (r) {
case 1:
zadd(t, _one_, &modulus);
zfree(t);
break;
case 0:
modulus = t;
break;
case -1:
zsub(t, _one_, &modulus);
zfree(t);
break;
}
/* if (modulus <= MAXLONG) { return v % modulus; } */
if (!zgtmaxlong(modulus)) {
itoz(zmodi(v, ztolong(modulus)), res);
zfree(modulus);
if (lbit > 0) {
zfree(h);
}
return;
}
/* ret = v; */
zcopy(v, &ret);
/*
* shift-add modulus loop
*/
hisone = zisone(h);
do {
/*
* split ret into to chunks, the lower n bits
* and everything above the lower n bits
*/
/* if (highbit(ret) < n) { break; } */
hbit = (long)zhighbit(ret);
if (hbit < n) {
zrelval = (zcmp(ret, modulus) ? -1 : 0);
break;
}
/* b = ret>>n; */
zshift(ret, -n, &b);
b.sign = ret.sign;
/* a = ret - (b<<n); */
a.sign = ret.sign;
a.len = (n+BASEB-1)/BASEB;
a.v = alloc(a.len);
memcpy(a.v, ret.v, a.len*sizeof(HALF));
if (n % BASEB) {
a.v[a.len - 1] &= lowhalf[n % BASEB];
}
ztrim(&a);
/*
* switch depending on r == -1, 0 or 1
*/
switch (r) {
case -1: /* v mod h*2^h-1 */
/* if (h == 1) ... */
if (hisone) {
/* ret = a + b; */
zfree(ret);
zadd(a, b, &ret);
/* ... else ... */
} else {
/* quomod(b, h, tquo, tmod); */
(void) zdiv(b, h, &tquo, &tmod, 0);
/* ret = tmod<<n + a + tquo; */
zshift(tmod, n, &t);
zfree(tmod);
zadd(a, tquo, &t2);
zfree(tquo);
zfree(ret);
zadd(t, t2, &ret);
zfree(t);
zfree(t2);
}
break;
case 0: /* v mod h*2^h-1 */
/* if (h == 1) ... */
if (hisone) {
/* ret = a; */
zfree(ret);
zcopy(a, &ret);
/* ... else ... */
} else {
/* ret = (b%h)<<n + a; */
(void) zmod(b, h, &tmod, 0);
zshift(tmod, n, &t);
zfree(tmod);
zfree(ret);
zadd(t, a, &ret);
zfree(t);
}
break;
case 1: /* v mod h*2^h-1 */
/* if (h == 1) ... */
if (hisone) {
/* ret = a-b; */
zfree(ret);
zsub(a, b, &ret);
/* ... else ... */
} else {
/* quomod(b, h, tquo, tmod); */
(void) zdiv(b, h, &tquo, &tmod, 0);
/* tmod = tmod<<n + a; */
zshift(tmod, n, &t);
zfree(tmod);
zadd(t, a, &tmod);
zfree(t);
/* ret = tmod-tquo; */
zfree(ret);
zsub(tmod, tquo, &ret);
zfree(tquo);
zfree(tmod);
}
break;
}
zfree(a);
zfree(b);
/* ... while (abs(ret) > modulus); */
} while ((zrelval = zabsrel(ret, modulus)) > 0);
/* ret = ((ret < 0) ? ret+modlus : ((ret == modulus) ? 0 : ret)); */
if (ret.sign) {
zadd(ret, modulus, &t);
zfree(ret);
ret = t;
} else if (zrelval == 0) {
zfree(ret);
ret = _zero_;
}
zfree(modulus);
if (lbit > 0) {
zfree(h);
}
/*
* return ret
*/
*res = ret;
return;
}
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