1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300 301 302 303 304 305 306 307 308 309 310 311 312 313 314 315 316 317 318 319 320 321 322 323 324 325 326 327 328 329 330 331 332 333 334 335 336 337 338 339 340 341 342 343 344 345 346 347 348 349 350 351 352 353 354 355 356 357 358 359 360 361 362 363 364 365 366 367 368 369 370 371 372 373 374 375 376 377 378 379 380 381 382 383 384 385 386 387 388 389 390 391 392 393 394 395 396 397 398 399 400 401 402 403 404 405 406 407 408 409 410 411 412 413 414 415 416 417 418 419 420 421 422 423 424 425 426 427 428 429 430 431 432 433 434 435 436 437 438 439 440 441 442 443 444 445 446 447 448 449 450 451 452 453 454 455 456 457 458 459 460 461 462 463 464 465 466 467 468 469 470 471 472 473 474 475 476 477 478 479 480 481 482 483 484 485 486 487 488 489 490 491 492 493 494 495 496 497 498 499 500 501 502 503 504 505 506 507 508 509 510 511 512 513 514 515 516 517 518 519 520 521 522 523 524 525 526 527 528 529 530 531 532 533 534 535 536 537 538 539 540 541 542 543 544 545 546 547 548 549 550 551 552 553 554 555 556 557 558 559 560 561 562 563 564 565 566 567 568 569 570 571 572 573 574 575 576 577 578 579 580 581 582 583 584
|
/***************************************************/
/* Linear Simultaeous equation solver */
/***************************************************/
/* General simultaneous equation solver. */
/* Code was inspired by the algorithm decsribed in section 2.3 */
/* of "Numerical Recipes in C", by W.H.Press, B.P.Flannery, */
/* S.A.Teukolsky & W.T.Vetterling. */
/*
* Copyright 2000 Graeme W. Gill
* All rights reserved.
*
* This material is licenced under the GNU AFFERO GENERAL PUBLIC LICENSE Version 3 :-
* see the License.txt file for licencing details.
*/
#include "numsup.h"
#include "ludecomp.h"
#undef DO_POLISH
#undef DO_CHECK
/* Solve the simultaneous linear equations A.X = B */
/* Return 1 if the matrix is singular, 0 if OK */
int
solve_se(
double **a, /* A[][] input matrix, returns LU decomposition of A */
double *b, /* B[] input array, returns solution X[] */
int n /* Dimensionality */
) {
double rip; /* Row interchange parity */
int *pivx, PIVX[10];
#if defined(DO_POLISH) || defined(DO_CHECK)
double **sa; /* save input matrix values */
double *sb; /* save input vector values */
int i, j;
#endif
if (n <= 10)
pivx = PIVX;
else
pivx = ivector(0, n-1);
#if defined(DO_POLISH) || defined(DO_CHECK)
sa = dmatrix(0, n-1, 0, n-1);
sb = dvector(0, n-1);
/* Copy input matrix and vector values */
for (i = 0; i < n; i++) {
sb[i] = b[i];
for (j = 0; j < n; j++)
sa[i][j] = a[i][j];
}
#endif
if (lu_decomp(a, n, pivx, &rip)) {
#if defined(DO_POLISH) || defined(DO_CHECK)
free_dvector(sb, 0, n-1);
free_dmatrix(sa, 0, n-1, 0, n-1);
#endif
if (pivx != PIVX)
free_ivector(pivx, 0, n-1);
return 1;
}
lu_backsub(a, n, pivx, b);
#ifdef DO_POLISH
lu_polish(sa, a, n, sb, b, pivx); /* Improve the solution */
#endif
#ifdef DO_CHECK
/* Check that the solution is correct */
for (i = 0; i < n; i++) {
double sum, temp;
sum = 0.0;
for (j = 0; j < n; j++)
sum += sa[i][j] * b[j];
temp = fabs(sum - sb[i]);
if (temp > 1e-6) {
free_dvector(sb, 0, n-1);
free_dmatrix(sa, 0, n-1, 0, n-1);
if (pivx != PIVX)
free_ivector(pivx, 0, n-1);
return 2;
}
}
#endif
#if defined(DO_POLISH) || defined(DO_CHECK)
free_dvector(sb, 0, n-1);
free_dmatrix(sa, 0, n-1, 0, n-1);
#endif
if (pivx != PIVX)
free_ivector(pivx, 0, n-1);
return 0;
}
/* Solve the simultaneous linear equations A.X = B, with polishing */
/* Return 1 if the matrix is singular, 0 if OK */
int
polished_solve_se(
double **a, /* A[][] input matrix, returns LU decomposition of A */
double *b, /* B[] input array, returns solution X[] */
int n /* Dimensionality */
) {
double rip; /* Row interchange parity */
int *pivx, PIVX[10];
double **sa; /* save input matrix values */
double *sb; /* save input vector values */
int i, j;
if (n <= 10)
pivx = PIVX;
else
pivx = ivector(0, n-1);
sa = dmatrix(0, n-1, 0, n-1);
sb = dvector(0, n-1);
/* Copy source input matrix and vector values */
for (i = 0; i < n; i++) {
sb[i] = b[i];
for (j = 0; j < n; j++)
sa[i][j] = a[i][j];
}
if (lu_decomp(a, n, pivx, &rip)) {
free_dvector(sb, 0, n-1);
free_dmatrix(sa, 0, n-1, 0, n-1);
if (pivx != PIVX)
free_ivector(pivx, 0, n-1);
return 1;
}
lu_backsub(a, n, pivx, b);
lu_polish(sa, a, n, sb, b, pivx); /* Improve the solution */
#ifdef DO_CHECK
/* Check that the solution is correct */
for (i = 0; i < n; i++) {
double sum, temp;
sum = 0.0;
for (j = 0; j < n; j++)
sum += sa[i][j] * b[j];
temp = fabs(sum - sb[i]);
if (temp > 1e-6) {
free_dvector(sb, 0, n-1);
free_dmatrix(sa, 0, n-1, 0, n-1);
if (pivx != PIVX)
free_ivector(pivx, 0, n-1);
return 2;
}
}
#endif
free_dvector(sb, 0, n-1);
free_dmatrix(sa, 0, n-1, 0, n-1);
if (pivx != PIVX)
free_ivector(pivx, 0, n-1);
return 0;
}
/* Decompose the square matrix A[][] into lower and upper triangles */
/* NOTE that it returns transposed inverse by normal convention. */
/* NOTE that rows get swaped by swapping matrix pointers! */
/* Use sym_matrix_trans() to fix this. */
/* Return 1 if the matrix is singular. */
int
lu_decomp(
double **a, /* A input array, output upper and lower triangles. */
int n, /* Dimensionality */
int *pivx, /* Return pivoting row permutations record */
double *rip /* Row interchange parity, +/- 1.0, used for determinant */
) {
int i, j;
double *rscale, RSCALE[10]; /* Implicit scaling of each row */
if (n <= 10)
rscale = RSCALE;
else
rscale = dvector(0, n-1);
/* For each row */
for (i = 0; i < n; i++) {
double big;
/* For each column in row */
for (big = 0.0, j=0; j < n; j++) {
double temp;
temp = fabs(a[i][j]);
if (temp > big)
big = temp;
}
if (fabs(big) <= DBL_MIN) {
if (rscale != RSCALE)
free_dvector(rscale, 0, n-1);
return 1; /* singular matrix */
}
rscale[i] = 1.0/big; /* Save the scaling */
}
/* For each column (Crout's method) */
for (*rip = 1.0, j = 0; j < n; j++) {
double big;
int k, bigi = 0;
/* For each row */
for (i = 0; i < j; i++) {
double sum;
sum = a[i][j];
for (k = 0; k < i; k++)
sum -= a[i][k] * a[k][j];
a[i][j] = sum;
}
/* Find largest pivot element */
for (big = 0.0, i = j; i < n; i++) {
double sum, temp;
sum = a[i][j];
for (k = 0; k < j; k++)
sum -= a[i][k] * a[k][j];
a[i][j] = sum;
temp = rscale[i] * fabs(sum); /* Figure of merit */
if (temp >= big) {
big = temp; /* Best so far */
bigi = i; /* Remember index */
}
}
/* If we need to interchange rows */
if (j != bigi) {
{ /* Take advantage of matrix storage to swap pointers to rows */
double *temp;
temp = a[bigi];
a[bigi] = a[j];
a[j] = temp;
}
*rip = -(*rip); /* Another row interchange */
rscale[bigi] = rscale[j]; /* Interchange scale factor */
}
pivx[j] = bigi; /* Record pivot */
if (fabs(a[j][j]) <= DBL_MIN) {
if (rscale != RSCALE)
free_dvector(rscale, 0, n-1);
return 1; /* Pivot element is zero, so matrix is singular */
}
/* Divide by the pivot element */
if (j != (n-1)) {
double temp;
temp = 1.0/a[j][j];
for (i = j+1; i < n; i++)
a[i][j] *= temp;
}
}
if (rscale != RSCALE)
free_dvector(rscale, 0, n-1);
return 0;
}
/* Solve a set of simultaneous equations A.x = b from the */
/* LU decomposition, by back substitution. */
void
lu_backsub(
double **a, /* A[][] LU decomposed matrix */
int n, /* Dimensionality */
int *pivx, /* Pivoting row permutations record */
double *b /* Input B[] vector, return X[] */
) {
int i, j;
int nvi; /* When >= 0, indicates non-vanishing B[] index */
/* Forward substitution, undo pivoting on the fly */
for (nvi = -1, i = 0; i < n; i++) {
int px;
double sum;
px = pivx[i];
sum = b[px];
b[px] = b[i];
if (nvi >= 0) {
for (j = nvi; j < i; j++)
sum -= a[i][j] * b[j];
} else {
if (sum != 0.0)
nvi = i; /* Found non-vanishing element */
}
b[i] = sum;
}
/* Back substitution */
for (i = (n-1); i >= 0; i--) {
double sum;
sum = b[i];
for (j = i+1; j < n; j++)
sum -= a[i][j] * b[j];
b[i] = sum/a[i][i];
}
}
/* Improve a solution of equations */
void
lu_polish(
double **a, /* Original A[][] matrix */
double **lua, /* LU decomposition of A[][] */
int n, /* Dimensionality */
double *b, /* B[] vector of equation */
double *x, /* X[] solution to be polished */
int *pivx /* Pivoting row permutations record */
) {
int i, j;
double *r, R[10]; /* Residuals */
if (n <= 10)
r = R;
else
r = dvector(0, n-1);
/* Accumulate the residual error */
for (i = 0; i < n; i++) {
double sum;
sum = -b[i];
for (j = 0; j < n; j++)
sum += a[i][j] * x[j];
r[i] = sum;
}
/* Solve for the error */
lu_backsub(lua, n, pivx, r);
/* Subtract error from the old solution */
for (i = 0; i < n; i++)
x[i] -= r[i];
if (r != R)
free_dvector(r, 0, n-1);
}
/* Invert a matrix A using lu decomposition */
/* NOTE that it returns transposed inverse by normal convention. */
/* Use sym_matrix_trans() to fix this, or use matrix_trans_mult() */
/* Return 1 if the matrix is singular, 0 if OK */
int
lu_invert(
double **a, /* A[][] input matrix, returns inversion of A transposed*/
int n /* Dimensionality */
) {
int i, j;
double rip; /* Row interchange parity */
int *pivx, PIVX[10];
double **y;
if (n <= 10)
pivx = PIVX;
else
pivx = ivector(0, n-1);
if (lu_decomp(a, n, pivx, &rip)) {
if (pivx != PIVX)
free_ivector(pivx, 0, n-1);
return 1;
}
/* Copy lu decomp. to y[][] */
y = dmatrix(0, n-1, 0, n-1);
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
y[i][j] = a[i][j];
}
}
/* Find inverse by columns */
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++)
a[i][j] = 0.0;
a[i][i] = 1.0;
lu_backsub(y, n, pivx, a[i]);
}
/* Clean up */
free_dmatrix(y, 0, n-1, 0, n-1);
if (pivx != PIVX)
free_ivector(pivx, 0, n-1);
return 0;
}
/* Invert a matrix A using lu decomposition */
/* The normal convention (NOT transpose) inverse is returned */
/* Return 1 if the matrix is singular, 0 if OK */
int
lu_invert_normal(
double **a, /* A[][] input matrix, returns inversion of A */
int n /* Dimensionality */
) {
int rv;
if ((rv = lu_invert(a, n)) != 0)
return rv;
sym_matrix_trans(a, n);
return rv;
}
/* Invert a matrix A using lu decomposition, and polish it. */
/* NOTE that it returns transposed inverse by normal convention. */
/* Use sym_matrix_trans() to fix this, or use matrix_trans_mult() */
/* Return 1 if the matrix is singular, 0 if OK */
int
lu_polished_invert(
double **a, /* A[][] input matrix, returns inversion of A */
int n /* Dimensionality */
) {
int i, j, k;
double **aa; /* saved a */
double **t1, **t2;
aa = dmatrix(0, n-1, 0, n-1);
t1 = dmatrix(0, n-1, 0, n-1);
t2 = dmatrix(0, n-1, 0, n-1);
/* Copy a to aa */
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++)
aa[i][j] = a[i][j];
}
/* Invert a */
if ((i = lu_invert(a, n)) != 0) {
free_dmatrix(aa, 0, n-1, 0, n-1);
free_dmatrix(t1, 0, n-1, 0, n-1);
free_dmatrix(t2, 0, n-1, 0, n-1);
return i;
}
for (k = 0; k < 20; k++) {
matrix_trans_mult(t1, n, n, aa, n, n, a, n, n);
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
t2[i][j] = a[i][j];
if (i == j)
t1[i][j] = 2.0 - t1[i][j];
else
t1[i][j] = 0.0 - t1[i][j];
}
}
matrix_mult(a, n, n, t2, n, n, t1, n, n);
}
free_dmatrix(aa, 0, n-1, 0, n-1);
free_dmatrix(t1, 0, n-1, 0, n-1);
free_dmatrix(t2, 0, n-1, 0, n-1);
return 0;
}
/* Pseudo-Invert matrix A using lu decomposition */
/* Return 1 if the matrix is singular, 0 if OK */
int
lu_psinvert(
double **out, /* Output[0..N-1][0..M-1] */
double **in, /* Input[0..M-1][0..N-1] input matrix */
int m, /* In Rows */
int n /* In Columns */
) {
int rv = 0;
double **tr; /* Transpose */
double **sq; /* Square matrix */
tr = dmatrix(0, n-1, 0, m-1);
matrix_trans(tr, in, m, n);
/* Use left inverse */
if (m > n) {
sq = dmatrix(0, n-1, 0, n-1);
/* Multiply transpose by input */
if ((rv = matrix_mult(sq, n, n, tr, n, m, in, m, n)) == 0) {
/* Invert the square matrix */
if ((rv = lu_invert(sq, n)) == 0) {
/* Multiply inverted square by transpose */
rv = matrix_mult(out, n, m, sq, n, n, tr, n, m);
}
}
free_dmatrix(sq, 0, n-1, 0, n-1);
/* Use right inverse */
} else {
sq = dmatrix(0, m-1, 0, m-1);
/* Multiply input by transpose */
if ((rv = matrix_mult(sq, m, m, in, m, n, tr, n, m)) == 0) {
/* Invert the square matrix */
if ((rv = lu_invert(sq, m)) == 0) {
/* Multiply transpose by inverted square */
rv = matrix_mult(out, n, m, tr, n, m, sq, m, m);
}
}
free_dmatrix(sq, 0, m-1, 0, m-1);
}
free_dmatrix(tr, 0, n-1, 0, m-1);
return rv;
}
/* ----------------------------------------------------------------- */
// ~~~ Hmm. Need to verify this code is correct...
/* Use Cholesky decomposition on a symetric positive-definite matrix. */
/* Only the upper triangle of the matrix A is accessed. */
/* L returns the decomposition */
/* Return nz if A is not positive-definite */
int llt_decomp(double **L, double **A, int n) {
int i, j, k;
double sum;
/* Scan though upper triangle */
for (i = 0; i < n; i++) {
for (j = i; j < n; j++) {
sum = A[i][j];
for (k = i-1; k >= 0; k--) {
sum -= A[i][k] * A[j][k];
}
if (i != j) {
L[j][i] = sum/L[i][i];
} else {
if (sum <= 0.0)
return 1;
L[i][i] = sqrt(sum);
}
}
}
return 0;
}
/* Solve a set of simultaneous equations A.x = b from the */
/* LLt decomposition, by back substitution. */
void llt_backsub(
double **L, /* A[][] LLt decomposition in lower triangle */
int n, /* Dimensionality */
double *b, /* Input B[] */
double *x /* Return X[] (may be same as B[]) */
) {
int i, k;
double sum;
/* Solve L.y = b, storing y in x. */
for (i = 0; i < n; i++) {
sum = b[i];
for (k = i-1; k >= 0; k--)
sum -= L[i][k] * x[k];
x[i] = sum/L[i][i];
}
/* Solve Lt.x = y */
for (i = n; i >= 0; i--) {
sum = x[i];
for (k = i+1 ; k < n; k++)
sum -= L[k][i] * x[k];
x[i] = sum/L[i][i];
}
}
|