1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
|
/*************************************************************************
*
* Purpose: Demonstrate the increment and decrement operators.
*
* Author: M.J. Leslie.
*
* Date: 07-Apr-94
*
*************************************************************************/
main()
{
/*
* ++i - i incremented before i is used.
* --i - i decremented before i is used.
* j++ - j is incremented AFTER j has been used.
* j-- - j is decremented AFTER j has been used.
*/
int i=1,j=1;
puts("\tDemo 1");
printf("\t%d %d\n",++i, j++); /* O/P 2 1 */
printf("\t%d %d\n",i, j); /* O/P 2 2 */
i=1;j=1;
puts("\n\tDemo 2");
printf("\t%d \n",i=j++); /* O/P 1 */
printf("\t%d \n",i=++j); /* O/P 3 */
/************************************************************************
This is a GOT YA
*************************************************************************/
/* Consider this code */
i = 0; j = 0;
puts("\n\tDemo 3");
if ( (i++ == 1) && (j++ == 1)) puts("Some text");
/* Will i and j get incremented? The answer is NO! Because
* the expression in the left of '&&' resolves to false the
* compiler does NOT execute the expression on the right and
* so 'j' does not get executed!!!!! */
printf("\t%d %d\n",i, j); /* O/P 1 0 */
}
|
