File: bitops.xml

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<!DOCTYPE KSpreadFunctions>
<KSpreadFunctions>

<Group>
    <GroupName>Bit Operations</GroupName>

    <Function>
        <Name>BITAND</Name>
        <Type>Int</Type>
        <Parameter>
            <Comment>First number</Comment>
            <Type>Int</Type>
        </Parameter>
        <Parameter>
            <Comment>Second number</Comment>
            <Type>Int</Type>
        </Parameter>
        <Help>
            <Text>The BITAND() function performs a bit-wise AND operation for the two integer parameters.</Text>
            <Syntax>BITAND(value; value)</Syntax>
            <Example>BITAND(12;10) returns 8 (because decimal 12 is binary 1100, and decimal 10 is binary 1010; and 1100 "anded" with 1010 is 1000, which is integer 8).</Example>
            <Related>BITOR</Related>
            <Related>BITXOR</Related>
        </Help>
    </Function>

    <Function>
        <Name>BITLSHIFT</Name>
        <Type>Int</Type>
        <Parameter>
            <Comment>First number</Comment>
            <Type>Int</Type>
        </Parameter>
        <Parameter>
            <Comment>Amount to left shift by</Comment>
            <Type>Int</Type>
        </Parameter>
        <Help>
            <Text>The BITLSHIFT() function performs a bit-wise left shift operation of the first parameter. The number of bits to shift by is specified by the second parameter. Note that a negative number of bits to left shift by becomes a right shift. </Text>
            <Syntax>BITLSHIFT(value; shift size)</Syntax>
            <Related>BITLSHIFT</Related>
        </Help>
    </Function>

    <Function>
        <Name>BITRSHIFT</Name>
        <Type>Int</Type>
        <Parameter>
            <Comment>First number</Comment>
            <Type>Int</Type>
        </Parameter>
        <Parameter>
            <Comment>Amount to right shift by</Comment>
            <Type>Int</Type>
        </Parameter>
        <Help>
            <Text>The BITRSHIFT() function performs a bit-wise right shift operation of the first parameter. The number of bits to shift by is specified by the second parameter. Note that a negative number of bits to right shift by becomes a left shift. </Text>
            <Syntax>BITRSHIFT(value; shift size)</Syntax>
            <Related>BITLSHIFT</Related>
        </Help>
    </Function>

    <Function>
        <Name>BITOR</Name>
        <Type>Int</Type>
        <Parameter>
            <Comment>First number</Comment>
            <Type>Int</Type>
        </Parameter>
        <Parameter>
            <Comment>Second number</Comment>
            <Type>Int</Type>
        </Parameter>
        <Help>
            <Text>The BITOR() function performs a bit-wise OR operation for the two integer parameters. </Text>
            <Syntax>BITOR(value; value)</Syntax>
            <Example>BITOR(12;10) returns 14 (because decimal 12 is binary 1100, and decimal 10 is binary 1010; and 1100 "ored" with 1010 is 1110, which is integer 14).</Example>
            <Related>BITAND</Related>
            <Related>BITXOR</Related>
        </Help>
    </Function>

    <Function>
        <Name>BITXOR</Name>
        <Type>Int</Type>
        <Parameter>
            <Comment>First number</Comment>
            <Type>Int</Type>
        </Parameter>
        <Parameter>
            <Comment>Second number</Comment>
            <Type>Int</Type>
        </Parameter>
        <Help>
            <Text>The BITXOR() function performs a bit-wise exclusive-OR operation for the two integer parameters. </Text>
            <Syntax>BITXOR(value; value)</Syntax>
            <Example>BITXOR(12;10) returns 6 (because decimal 12 is binary 1100, and decimal 10 is binary 1010; and 1100 "xored" with 1010 is 0110, which is integer 6).</Example>
            <Related>BITAND</Related>
            <Related>BITOR</Related>
        </Help>
    </Function>

</Group>

</KSpreadFunctions>