File: inference.out

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coq 8.16.1%2Bdfsg-1
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P = 
fun e : option L => match e with
                    | Some cl => Some cl
                    | None => None
                    end
     : option L -> option L

Arguments P e
fun n : nat => let y : T n := A n in ?t ?x : T n
     : forall n : nat, T n
where
?t : [n : nat  y := A n : T n |- ?T -> T n]
?x : [n : nat  y := A n : T n |- ?T]
fun n : nat => ?t ?x : T n
     : forall n : nat, T n
where
?t : [n : nat |- ?T -> T n]
?x : [n : nat |- ?T]