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/*
* user.c: Part of GNU CSSC.
*
*
* Copyright (C) 1997, Free Software Foundation, Inc.
*
* This program is free software; you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation; either version 2 of the License, or
* (at your option) any later version.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with this program; if not, write to the Free Software
* Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111, USA.
*
* Program for getting the user's login name.
*/
#ifdef HAVE_UNISTD_H
#include <unistd.h>
#endif
#include <sys/types.h>
#include <pwd.h>
#ifdef STDC_HEADERS
#include <stdio.h>
#include <string.h>
#endif
const char usage_str[] = "usage: \"user name\" or \"user group\"\n";
static int duplicate_group(gid_t g, const gid_t *vec, int len)
{
while (len--)
{
if (*vec == g)
return 1;
}
return 0;
}
/* do_groups
*
* Emits a list of groups associated with the current
* process. The effectve group ID is also returned,
* and this may be a suplicate entry.
*/
static gid_t *get_group_list(int *ngroups)
{
int len;
gid_t *grouplist;
len = getgroups(0, NULL);
if (len < 0)
{
perror("getgroups");
return NULL;
}
else
{
grouplist = malloc((1+len) * sizeof(*grouplist));
if (grouplist)
{
/* We don't know if the effectve group ID is in
* the list returned by grouplist, so find out
* and return a list with it included, but only once
*/
gid_t egid = getegid();
if (getgroups(len, &grouplist[1]))
{
if (duplicate_group(egid, grouplist+1, len))
{
*ngroups = len;
return &grouplist[1];
}
else
{
grouplist[0] = egid;
*ngroups = len+1;
return &grouplist[0];
}
}
else
{
perror("getgroups");
return NULL;
}
}
else
{
perror("malloc");
return NULL;
}
}
}
static void do_groups()
{
int ngroups, i, duplicates;
gid_t *list = get_group_list(&ngroups);
if (list)
{
for (i=0; i<ngroups; ++i)
{
fprintf(stdout, "%ld\n", (long) list[i]);
}
}
else
{
/* fallback. */
fprintf(stdout, "%ld\n", (long) getegid());
}
}
static int compare_groups(const void *pv1, const void *pv2)
{
const gid_t *p1 = (const gid_t*) pv1;
const gid_t *p2 = (const gid_t*) pv2;
if (*p1 < *p2)
return -1;
else if (*p1 > *p2)
return 1;
else
return 0;
}
/* Find and print the Id of a group of which we are not a member.
* This group will (most likely) not have a name
*/
static gid_t foreign_group(void)
{
int ngroups, i, duplicates;
gid_t *list = get_group_list(&ngroups);
qsort(list, ngroups, sizeof(*list), compare_groups);
for (i=1; i<ngroups; ++i)
{
/* nextval is a gid_t value 1 greater than the last gid we saw */
int nextval = 1+list[i-1];
if (nextval < list[i] )
{
/* we have a gap. */
return nextval;
}
}
/* We can't just add 1 to the value of the last entry in the list
* because of the possibility of overflow.
*/
if (ngroups)
{
if (list[0] > 0)
return 0;
else
return 1+list[ngroups-1];
}
else /* not a member of any groups? */
{
gid_t last_resort = getegid();
if (last_resort > 0)
return 0;
else
return 1+last_resort;
}
}
int main(int argc, char *argv[])
{
if (2 == argc)
{
if (0 == strcmp(argv[1], "name"))
{
struct passwd *p;
const char *pn = "unknown";
p = getpwuid(getuid());
if (p)
pn = p->pw_name;
fprintf(stdout, "%s\n", pn);
return 0;
}
else if (0 == strcmp(argv[1], "groups"))
{
do_groups();
return 0;
}
else if (0 == strcmp(argv[1], "foreigngroup"))
{
fprintf(stdout, "%ld\n", (long)foreign_group());
return 0;
}
else if (0 == strcmp(argv[1], "group"))
{
fprintf(stdout, "%ld\n", (long)getgid());
return 0;
}
else
{
fprintf(stderr, "%s", usage_str);
return 1;
}
}
else
{
fprintf(stderr, "%s", usage_str);
return 1;
}
}
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