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.. _views:
Class Based Views
=================
While :pypi:`django-polymorphic` provides full admin integration, you might want to build front-end
views that allow users to create polymorphic objects. Since a single URL cannot easily handle
different form fields for different models, the best approach is a two-step process:
1. **Step 1:** Let the user choose the desired type.
2. **Step 2:** Display the form for that specific type.
.. tip::
The code for this example can be found `here
<https://github.com/jazzband/django-polymorphic/tree/HEAD/src/polymorphic/tests/examples/views>`_.
This example uses model labels (e.g., ``app.ModelName``) to identify the selected type. Assume we
have the following models:
.. literalinclude:: ../src/polymorphic/tests/examples/views/models.py
:language: python
:linenos:
Step 1: Selecting the Type
--------------------------
Create a form that allows users select the desired model type. You can use a simple choice field
for this.
.. literalinclude:: ../src/polymorphic/tests/examples/views/views.py
:language: python
:lines: 1-45
:linenos:
Your template ``project_type_select.html``, might look like this:
.. literalinclude:: ../src/polymorphic/tests/examples/views/templates/project_type_select.html
:language: html
Step 2: Displaying the Form
---------------------------
The creation view needs to dynamically select the correct form class based on the chosen model label.
.. literalinclude:: ../src/polymorphic/tests/examples/views/views.py
:language: python
:lines: 47-
:linenos:
In your template ``project_form.html``, make sure to preserve the ``model`` parameter:
.. literalinclude:: ../src/polymorphic/tests/examples/views/templates/project_form.html
:language: html
And our urls might look like this:
.. literalinclude:: ../src/polymorphic/tests/examples/views/urls.py
:linenos:
Using ``extra_views``
---------------------
If you are using :pypi:`django-extra-views`, :pypi:`django-polymorphic` provides mixins to help with formsets.
See :mod:`polymorphic.contrib.extra_views` for more details.
|
