1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
|
# name: test/optimizer/join_elimination.test
# description: test join elimination
# group: [optimizer]
statement ok
PRAGMA enable_verification;
statement ok
create table a(ida int, valuea int);
statement ok
create table b(idb int, valueb int);
statement ok
create table c(idc int, valuec int);
statement ok
insert into a values (1,1), (2,2), (1,1),(NUll, NULL),(3, NULL),(NULL,4);
statement ok
insert into b values (1,1), (2,2), (3,3),(4,4),(3,3),(NUll, NULL),(3, NULL),(NULL,4);
statement ok
insert into c values (1,1), (2,2), (3,3),(4,4),(3,3),(NUll, NULL),(3, NULL),(NULL,4);
query II
explain select distinct b.* from b left join a on a.ida=b.idb;
----
physical_plan <!REGEX>:.*JOIN.*
query II
explain select distinct b.* from b left join a on a.ida=b.idb where b.valueb=1;
----
physical_plan <!REGEX>:.*JOIN.*
query II
explain select distinct b.* from b left join a on a.ida=b.idb where a.valuea=1;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select b.* from b left join (select distinct ida as ida from a) as a1 on a1.ida=b.idb;
----
physical_plan <!REGEX>:.*JOIN.*
query II
explain select b.* from b left join (select * from a group by all) as a1 on b.idb=a1.ida;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select b.* from b left join (select a.ida from a group by ida) as a1 on b.idb=a1.ida;
----
physical_plan <!REGEX>:.*JOIN.*
query II
explain select b.idb,sum(b.valueb) from b left join a on b.idb=a.ida group by b.idb;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select b.idb,sum(a.valuea) from b left join a on b.idb=a.ida group by b.idb;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select b.* from b left join (select distinct ida as ida from a) as a1 on a1.ida=b.idb and a1.ida = 1;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select b.* from b left join (select distinct ida as ida from a) as a1 on a1.ida=b.idb and a1.ida = b.valueb ;
----
physical_plan <!REGEX>:.*JOIN.*
query II
explain select b.* from b left join (select distinct ida as ida, valuea as valuea from a) as a1 on a1.ida=b.idb and a1.ida = b.valueb and a1.valuea = b.idb;
----
physical_plan <!REGEX>:.*JOIN.*
query II
explain select b.* from b left join (select distinct ida as ida, valuea as valuea from a) as a1 on a1.ida=b.idb;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select b.* from b left join (select distinct ida as ida from a) as a1 on a1.ida=b.idb or a1.ida = 1 ;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select b.*, a.* from b left join a on a.ida=b.idb;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select b.* from b left join a on a.ida=b.idb+1;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select tan(b.idb) from b left join a on a.ida=b.idb;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select b.valueb from b left join a on a.ida=b.idb;
----
physical_plan <REGEX>:.*JOIN.*
query II
explain select b.*, tan(a.ida) from b left join a on a.ida=b.idb;
----
physical_plan <REGEX>:.*JOIN.*
# this should eliminate inner join but keep outer one
query II
explain SELECT c.*
FROM c
LEFT JOIN (
SELECT DISTINCT b.*
FROM b
LEFT JOIN a ON a.ida = b.idb
) AS ab ON c.idc = ab.idb;
----
physical_plan <REGEX>:.*JOIN.*
# this should eliminate all join
query II
explain SELECT c.*
FROM c
LEFT JOIN (
SELECT DISTINCT b.*
FROM b
LEFT JOIN a ON a.ida = b.idb
) AS ab ON c.idc = ab.idb and c.valuec = ab.valueb;
----
physical_plan <!REGEX>:.*JOIN.*
query II
explain select b.*, tan(a.ida) from b left join a on a.ida=b.idb;
----
physical_plan <REGEX>:.*JOIN.*
# just verify results are same that optimized plan compare to original.
statement ok
select distinct b.* from b left join a on a.ida=b.idb;
statement ok
select distinct b.* from b left join a on a.ida=b.idb where b.valueb=1;
statement ok
select distinct b.* from b left join a on a.ida=b.idb where a.valuea=1;
statement ok
select b.* from b left join (select distinct ida as ida from a) as a1 on a1.ida=b.idb;
statement ok
select b.* from b left join (select * from a group by all) as a1 on b.idb=a1.ida;
statement ok
select b.* from b left join (select a.ida from a group by ida) as a1 on b.idb=a1.ida;
statement ok
select b.idb,sum(b.valueb) from b left join a on b.idb=a.ida group by b.idb;
statement ok
select b.idb,sum(a.valuea) from b left join a on b.idb=a.ida group by b.idb;
statement ok
select b.* from b left join (select distinct ida as ida from a) as a1 on a1.ida=b.idb and a1.ida = 1;
statement ok
select b.* from b left join (select distinct ida as ida from a) as a1 on a1.ida=b.idb and a1.ida = b.valueb ;
statement ok
select b.* from b left join (select distinct ida as ida, valuea as valuea from a) as a1 on a1.ida=b.idb and a1.ida = b.valueb and a1.valuea = b.idb;
statement ok
select b.* from b left join (select distinct ida as ida, valuea as valuea from a) as a1 on a1.ida=b.idb;
statement ok
select b.* from b left join (select distinct ida as ida from a) as a1 on a1.ida=b.idb or a1.ida = 1 ;
statement ok
select b.*, a.* from b left join a on a.ida=b.idb;
statement ok
select b.* from b left join a on a.ida=b.idb+1;
statement ok
select tan(b.idb) from b left join a on a.ida=b.idb;
statement ok
select b.valueb from b left join a on a.ida=b.idb;
statement ok
select b.*, tan(a.ida) from b left join a on a.ida=b.idb;
statement ok
SELECT c.*
FROM c
LEFT JOIN (
SELECT DISTINCT b.*
FROM b
LEFT JOIN a ON a.ida = b.idb
) AS ab ON c.idc = ab.idb;
statement ok
SELECT c.*
FROM c
LEFT JOIN (
SELECT DISTINCT b.*
FROM b
LEFT JOIN a ON a.ida = b.idb
) AS ab ON c.idc = ab.idb and c.valuec = ab.valueb;
statement ok
select b.*, tan(a.ida) from b left join a on a.ida=b.idb;
# union intersect unnest, pivot, delim scan, inline cte, materialized
query II
explain
select b.* from b left join (select distinct a.ida from a ) as a on a.ida=b.idb union all select b.* from b left join (select distinct a.ida from a ) as a on a.ida=b.idb;
----
physical_plan <!REGEX>:.*JOIN.*
statement ok
select b.* from b left join (select distinct a.ida from a ) as a on a.ida=b.idb union all select b.* from b left join (select distinct a.ida from a ) as a on a.ida=b.idb;
# we cannot use distinct statistics from outer child
statement ok
select a.ida from (select ida from a group by ida) as a left join b on ida < idb;
query II
explain select a.ida from (select ida from a group by ida) as a left join b on ida < idb;
----
physical_plan <REGEX>:.*JOIN.*
statement ok
select a.ida from b right join (select ida from a group by ida) as a on ida < idb;
query II
explain select a.ida from b right join (select ida from a group by ida) as a on ida < idb;
----
physical_plan <REGEX>:.*JOIN.*
|
