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# Copyright 2016 Hardcoded Software (http://www.hardcoded.net)
#
# This software is licensed under the "GPLv3" License as described in the "LICENSE" file,
# which should be included with this package. The terms are also available at
# http://www.gnu.org/licenses/gpl-3.0.html
import sys
from hscommon.jobprogress import job
from hscommon.util import first
from hscommon.testutil import eq_, log_calls
from core.tests.base import NamedObject
from core import engine
from core.engine import (
get_match,
getwords,
Group,
getfields,
unpack_fields,
compare_fields,
compare,
WEIGHT_WORDS,
MATCH_SIMILAR_WORDS,
NO_FIELD_ORDER,
build_word_dict,
get_groups,
getmatches,
Match,
getmatches_by_contents,
merge_similar_words,
reduce_common_words,
)
no = NamedObject
def get_match_triangle():
o1 = NamedObject(with_words=True)
o2 = NamedObject(with_words=True)
o3 = NamedObject(with_words=True)
m1 = get_match(o1, o2)
m2 = get_match(o1, o3)
m3 = get_match(o2, o3)
return [m1, m2, m3]
def get_test_group():
m1, m2, m3 = get_match_triangle()
result = Group()
result.add_match(m1)
result.add_match(m2)
result.add_match(m3)
return result
def assert_match(m, name1, name2):
# When testing matches, whether objects are in first or second position very often doesn't
# matter. This function makes this test more convenient.
if m.first.name == name1:
eq_(m.second.name, name2)
else:
eq_(m.first.name, name2)
eq_(m.second.name, name1)
class TestCasegetwords:
def test_spaces(self):
eq_(["a", "b", "c", "d"], getwords("a b c d"))
eq_(["a", "b", "c", "d"], getwords(" a b c d "))
def test_unicode(self):
eq_(["e", "c", "0", "a", "o", "u", "e", "u"], getwords("é ç 0 à ö û è ¤ ù"))
eq_(["02", "君のこころは輝いてるかい?", "国木田花丸", "solo", "ver"], getwords("02 君のこころは輝いてるかい? 国木田花丸 Solo Ver"))
def test_splitter_chars(self):
eq_(
[chr(i) for i in range(ord("a"), ord("z") + 1)],
getwords("a-b_c&d+e(f)g;h\\i[j]k{l}m:n.o,p<q>r/s?t~u!v@w#x$y*z"),
)
def test_joiner_chars(self):
eq_(["aec"], getwords("a'e\u0301c"))
def test_empty(self):
eq_([], getwords(""))
def test_returns_lowercase(self):
eq_(["foo", "bar"], getwords("FOO BAR"))
def test_decompose_unicode(self):
eq_(["fooebar"], getwords("foo\xe9bar"))
class TestCasegetfields:
def test_simple(self):
eq_([["a", "b"], ["c", "d", "e"]], getfields("a b - c d e"))
def test_empty(self):
eq_([], getfields(""))
def test_cleans_empty_fields(self):
expected = [["a", "bc", "def"]]
actual = getfields(" - a bc def")
eq_(expected, actual)
class TestCaseUnpackFields:
def test_with_fields(self):
expected = ["a", "b", "c", "d", "e", "f"]
actual = unpack_fields([["a"], ["b", "c"], ["d", "e", "f"]])
eq_(expected, actual)
def test_without_fields(self):
expected = ["a", "b", "c", "d", "e", "f"]
actual = unpack_fields(["a", "b", "c", "d", "e", "f"])
eq_(expected, actual)
def test_empty(self):
eq_([], unpack_fields([]))
class TestCaseWordCompare:
def test_list(self):
eq_(100, compare(["a", "b", "c", "d"], ["a", "b", "c", "d"]))
eq_(86, compare(["a", "b", "c", "d"], ["a", "b", "c"]))
def test_unordered(self):
# Sometimes, users don't want fuzzy matching too much When they set the slider
# to 100, they don't expect a filename with the same words, but not the same order, to match.
# Thus, we want to return 99 in that case.
eq_(99, compare(["a", "b", "c", "d"], ["d", "b", "c", "a"]))
def test_word_occurs_twice(self):
# if a word occurs twice in first, but once in second, we want the word to be only counted once
eq_(89, compare(["a", "b", "c", "d", "a"], ["d", "b", "c", "a"]))
def test_uses_copy_of_lists(self):
first = ["foo", "bar"]
second = ["bar", "bleh"]
compare(first, second)
eq_(["foo", "bar"], first)
eq_(["bar", "bleh"], second)
def test_word_weight(self):
eq_(
int((6.0 / 13.0) * 100),
compare(["foo", "bar"], ["bar", "bleh"], (WEIGHT_WORDS,)),
)
def test_similar_words(self):
eq_(
100,
compare(
["the", "white", "stripes"],
["the", "whites", "stripe"],
(MATCH_SIMILAR_WORDS,),
),
)
def test_empty(self):
eq_(0, compare([], []))
def test_with_fields(self):
eq_(67, compare([["a", "b"], ["c", "d", "e"]], [["a", "b"], ["c", "d", "f"]]))
def test_propagate_flags_with_fields(self, monkeypatch):
def mock_compare(first, second, flags):
eq_((0, 1, 2, 3, 5), flags)
monkeypatch.setattr(engine, "compare_fields", mock_compare)
compare([["a"]], [["a"]], (0, 1, 2, 3, 5))
class TestCaseWordCompareWithFields:
def test_simple(self):
eq_(
67,
compare_fields([["a", "b"], ["c", "d", "e"]], [["a", "b"], ["c", "d", "f"]]),
)
def test_empty(self):
eq_(0, compare_fields([], []))
def test_different_length(self):
eq_(0, compare_fields([["a"], ["b"]], [["a"], ["b"], ["c"]]))
def test_propagates_flags(self, monkeypatch):
def mock_compare(first, second, flags):
eq_((0, 1, 2, 3, 5), flags)
monkeypatch.setattr(engine, "compare_fields", mock_compare)
compare_fields([["a"]], [["a"]], (0, 1, 2, 3, 5))
def test_order(self):
first = [["a", "b"], ["c", "d", "e"]]
second = [["c", "d", "f"], ["a", "b"]]
eq_(0, compare_fields(first, second))
def test_no_order(self):
first = [["a", "b"], ["c", "d", "e"]]
second = [["c", "d", "f"], ["a", "b"]]
eq_(67, compare_fields(first, second, (NO_FIELD_ORDER,)))
first = [["a", "b"], ["a", "b"]] # a field can only be matched once.
second = [["c", "d", "f"], ["a", "b"]]
eq_(0, compare_fields(first, second, (NO_FIELD_ORDER,)))
first = [["a", "b"], ["a", "b", "c"]]
second = [["c", "d", "f"], ["a", "b"]]
eq_(33, compare_fields(first, second, (NO_FIELD_ORDER,)))
def test_compare_fields_without_order_doesnt_alter_fields(self):
# The NO_ORDER comp type altered the fields!
first = [["a", "b"], ["c", "d", "e"]]
second = [["c", "d", "f"], ["a", "b"]]
eq_(67, compare_fields(first, second, (NO_FIELD_ORDER,)))
eq_([["a", "b"], ["c", "d", "e"]], first)
eq_([["c", "d", "f"], ["a", "b"]], second)
class TestCaseBuildWordDict:
def test_with_standard_words(self):
item_list = [NamedObject("foo bar", True)]
item_list.append(NamedObject("bar baz", True))
item_list.append(NamedObject("baz bleh foo", True))
d = build_word_dict(item_list)
eq_(4, len(d))
eq_(2, len(d["foo"]))
assert item_list[0] in d["foo"]
assert item_list[2] in d["foo"]
eq_(2, len(d["bar"]))
assert item_list[0] in d["bar"]
assert item_list[1] in d["bar"]
eq_(2, len(d["baz"]))
assert item_list[1] in d["baz"]
assert item_list[2] in d["baz"]
eq_(1, len(d["bleh"]))
assert item_list[2] in d["bleh"]
def test_unpack_fields(self):
o = NamedObject("")
o.words = [["foo", "bar"], ["baz"]]
d = build_word_dict([o])
eq_(3, len(d))
eq_(1, len(d["foo"]))
def test_words_are_unaltered(self):
o = NamedObject("")
o.words = [["foo", "bar"], ["baz"]]
build_word_dict([o])
eq_([["foo", "bar"], ["baz"]], o.words)
def test_object_instances_can_only_be_once_in_words_object_list(self):
o = NamedObject("foo foo", True)
d = build_word_dict([o])
eq_(1, len(d["foo"]))
def test_job(self):
def do_progress(p, d=""):
self.log.append(p)
return True
j = job.Job(1, do_progress)
self.log = []
s = "foo bar"
build_word_dict([NamedObject(s, True), NamedObject(s, True), NamedObject(s, True)], j)
# We don't have intermediate log because iter_with_progress is called with every > 1
eq_(0, self.log[0])
eq_(100, self.log[1])
class TestCaseMergeSimilarWords:
def test_some_similar_words(self):
d = {
"foobar": {1},
"foobar1": {2},
"foobar2": {3},
}
merge_similar_words(d)
eq_(1, len(d))
eq_(3, len(d["foobar"]))
class TestCaseReduceCommonWords:
def test_typical(self):
d = {
"foo": {NamedObject("foo bar", True) for _ in range(50)},
"bar": {NamedObject("foo bar", True) for _ in range(49)},
}
reduce_common_words(d, 50)
assert "foo" not in d
eq_(49, len(d["bar"]))
def test_dont_remove_objects_with_only_common_words(self):
d = {
"common": set([NamedObject("common uncommon", True) for _ in range(50)] + [NamedObject("common", True)]),
"uncommon": {NamedObject("common uncommon", True)},
}
reduce_common_words(d, 50)
eq_(1, len(d["common"]))
eq_(1, len(d["uncommon"]))
def test_values_still_are_set_instances(self):
d = {
"common": set([NamedObject("common uncommon", True) for _ in range(50)] + [NamedObject("common", True)]),
"uncommon": {NamedObject("common uncommon", True)},
}
reduce_common_words(d, 50)
assert isinstance(d["common"], set)
assert isinstance(d["uncommon"], set)
def test_dont_raise_keyerror_when_a_word_has_been_removed(self):
# If a word has been removed by the reduce, an object in a subsequent common word that
# contains the word that has been removed would cause a KeyError.
d = {
"foo": {NamedObject("foo bar baz", True) for _ in range(50)},
"bar": {NamedObject("foo bar baz", True) for _ in range(50)},
"baz": {NamedObject("foo bar baz", True) for _ in range(49)},
}
try:
reduce_common_words(d, 50)
except KeyError:
self.fail()
def test_unpack_fields(self):
# object.words may be fields.
def create_it():
o = NamedObject("")
o.words = [["foo", "bar"], ["baz"]]
return o
d = {"foo": {create_it() for _ in range(50)}}
try:
reduce_common_words(d, 50)
except TypeError:
self.fail("must support fields.")
def test_consider_a_reduced_common_word_common_even_after_reduction(self):
# There was a bug in the code that causeda word that has already been reduced not to
# be counted as a common word for subsequent words. For example, if 'foo' is processed
# as a common word, keeping a "foo bar" file in it, and the 'bar' is processed, "foo bar"
# would not stay in 'bar' because 'foo' is not a common word anymore.
only_common = NamedObject("foo bar", True)
d = {
"foo": set([NamedObject("foo bar baz", True) for _ in range(49)] + [only_common]),
"bar": set([NamedObject("foo bar baz", True) for _ in range(49)] + [only_common]),
"baz": {NamedObject("foo bar baz", True) for _ in range(49)},
}
reduce_common_words(d, 50)
eq_(1, len(d["foo"]))
eq_(1, len(d["bar"]))
eq_(49, len(d["baz"]))
class TestCaseGetMatch:
def test_simple(self):
o1 = NamedObject("foo bar", True)
o2 = NamedObject("bar bleh", True)
m = get_match(o1, o2)
eq_(50, m.percentage)
eq_(["foo", "bar"], m.first.words)
eq_(["bar", "bleh"], m.second.words)
assert m.first is o1
assert m.second is o2
def test_in(self):
o1 = NamedObject("foo", True)
o2 = NamedObject("bar", True)
m = get_match(o1, o2)
assert o1 in m
assert o2 in m
assert object() not in m
def test_word_weight(self):
m = get_match(NamedObject("foo bar", True), NamedObject("bar bleh", True), (WEIGHT_WORDS,))
eq_(m.percentage, int((6.0 / 13.0) * 100))
class TestCaseGetMatches:
def test_empty(self):
eq_(getmatches([]), [])
def test_simple(self):
item_list = [
NamedObject("foo bar"),
NamedObject("bar bleh"),
NamedObject("a b c foo"),
]
r = getmatches(item_list)
eq_(2, len(r))
m = first(m for m in r if m.percentage == 50) # "foo bar" and "bar bleh"
assert_match(m, "foo bar", "bar bleh")
m = first(m for m in r if m.percentage == 33) # "foo bar" and "a b c foo"
assert_match(m, "foo bar", "a b c foo")
def test_null_and_unrelated_objects(self):
item_list = [
NamedObject("foo bar"),
NamedObject("bar bleh"),
NamedObject(""),
NamedObject("unrelated object"),
]
r = getmatches(item_list)
eq_(len(r), 1)
m = r[0]
eq_(m.percentage, 50)
assert_match(m, "foo bar", "bar bleh")
def test_twice_the_same_word(self):
item_list = [NamedObject("foo foo bar"), NamedObject("bar bleh")]
r = getmatches(item_list)
eq_(1, len(r))
def test_twice_the_same_word_when_preworded(self):
item_list = [NamedObject("foo foo bar", True), NamedObject("bar bleh", True)]
r = getmatches(item_list)
eq_(1, len(r))
def test_two_words_match(self):
item_list = [NamedObject("foo bar"), NamedObject("foo bar bleh")]
r = getmatches(item_list)
eq_(1, len(r))
def test_match_files_with_only_common_words(self):
# If a word occurs more than 50 times, it is excluded from the matching process
# The problem with the common_word_threshold is that the files containing only common
# words will never be matched together. We *should* match them.
# This test assumes that the common word threshold const is 50
item_list = [NamedObject("foo") for _ in range(50)]
r = getmatches(item_list)
eq_(1225, len(r))
def test_use_words_already_there_if_there(self):
o1 = NamedObject("foo")
o2 = NamedObject("bar")
o2.words = ["foo"]
eq_(1, len(getmatches([o1, o2])))
def test_job(self):
def do_progress(p, d=""):
self.log.append(p)
return True
j = job.Job(1, do_progress)
self.log = []
s = "foo bar"
getmatches([NamedObject(s), NamedObject(s), NamedObject(s)], j=j)
assert len(self.log) > 2
eq_(0, self.log[0])
eq_(100, self.log[-1])
def test_weight_words(self):
item_list = [NamedObject("foo bar"), NamedObject("bar bleh")]
m = getmatches(item_list, weight_words=True)[0]
eq_(int((6.0 / 13.0) * 100), m.percentage)
def test_similar_word(self):
item_list = [NamedObject("foobar"), NamedObject("foobars")]
eq_(len(getmatches(item_list, match_similar_words=True)), 1)
eq_(getmatches(item_list, match_similar_words=True)[0].percentage, 100)
item_list = [NamedObject("foobar"), NamedObject("foo")]
eq_(len(getmatches(item_list, match_similar_words=True)), 0) # too far
item_list = [NamedObject("bizkit"), NamedObject("bizket")]
eq_(len(getmatches(item_list, match_similar_words=True)), 1)
item_list = [NamedObject("foobar"), NamedObject("foosbar")]
eq_(len(getmatches(item_list, match_similar_words=True)), 1)
def test_single_object_with_similar_words(self):
item_list = [NamedObject("foo foos")]
eq_(len(getmatches(item_list, match_similar_words=True)), 0)
def test_double_words_get_counted_only_once(self):
item_list = [NamedObject("foo bar foo bleh"), NamedObject("foo bar bleh bar")]
m = getmatches(item_list)[0]
eq_(75, m.percentage)
def test_with_fields(self):
o1 = NamedObject("foo bar - foo bleh")
o2 = NamedObject("foo bar - bleh bar")
o1.words = getfields(o1.name)
o2.words = getfields(o2.name)
m = getmatches([o1, o2])[0]
eq_(50, m.percentage)
def test_with_fields_no_order(self):
o1 = NamedObject("foo bar - foo bleh")
o2 = NamedObject("bleh bang - foo bar")
o1.words = getfields(o1.name)
o2.words = getfields(o2.name)
m = getmatches([o1, o2], no_field_order=True)[0]
eq_(m.percentage, 50)
def test_only_match_similar_when_the_option_is_set(self):
item_list = [NamedObject("foobar"), NamedObject("foobars")]
eq_(len(getmatches(item_list, match_similar_words=False)), 0)
def test_dont_recurse_do_match(self):
# with nosetests, the stack is increased. The number has to be high enough not to be failing falsely
sys.setrecursionlimit(200)
files = [NamedObject("foo bar") for _ in range(201)]
try:
getmatches(files)
except RuntimeError:
self.fail()
finally:
sys.setrecursionlimit(1000)
def test_min_match_percentage(self):
item_list = [
NamedObject("foo bar"),
NamedObject("bar bleh"),
NamedObject("a b c foo"),
]
r = getmatches(item_list, min_match_percentage=50)
eq_(1, len(r)) # Only "foo bar" / "bar bleh" should match
def test_memory_error(self, monkeypatch):
@log_calls
def mocked_match(first, second, flags):
if len(mocked_match.calls) > 42:
raise MemoryError()
return Match(first, second, 0)
objects = [NamedObject() for _ in range(10)] # results in 45 matches
monkeypatch.setattr(engine, "get_match", mocked_match)
try:
r = getmatches(objects)
except MemoryError:
self.fail("MemoryError must be handled")
eq_(42, len(r))
class TestCaseGetMatchesByContents:
def test_big_file_partial_hashing(self):
smallsize = 1
bigsize = 100 * 1024 * 1024 # 100MB
f = [
no("bigfoo", size=bigsize),
no("bigbar", size=bigsize),
no("smallfoo", size=smallsize),
no("smallbar", size=smallsize),
]
f[0].digest = f[0].digest_partial = f[0].digest_samples = "foobar"
f[1].digest = f[1].digest_partial = f[1].digest_samples = "foobar"
f[2].digest = f[2].digest_partial = "bleh"
f[3].digest = f[3].digest_partial = "bleh"
r = getmatches_by_contents(f, bigsize=bigsize)
eq_(len(r), 2)
# User disabled optimization for big files, compute digests as usual
r = getmatches_by_contents(f, bigsize=0)
eq_(len(r), 2)
# Other file is now slightly different, digest_partial is still the same
f[1].digest = f[1].digest_samples = "foobardiff"
r = getmatches_by_contents(f, bigsize=bigsize)
# Successfully filter it out
eq_(len(r), 1)
r = getmatches_by_contents(f, bigsize=0)
eq_(len(r), 1)
class TestCaseGroup:
def test_empty(self):
g = Group()
eq_(None, g.ref)
eq_([], g.dupes)
eq_(0, len(g.matches))
def test_add_match(self):
g = Group()
m = get_match(NamedObject("foo", True), NamedObject("bar", True))
g.add_match(m)
assert g.ref is m.first
eq_([m.second], g.dupes)
eq_(1, len(g.matches))
assert m in g.matches
def test_multiple_add_match(self):
g = Group()
o1 = NamedObject("a", True)
o2 = NamedObject("b", True)
o3 = NamedObject("c", True)
o4 = NamedObject("d", True)
g.add_match(get_match(o1, o2))
assert g.ref is o1
eq_([o2], g.dupes)
eq_(1, len(g.matches))
g.add_match(get_match(o1, o3))
eq_([o2], g.dupes)
eq_(2, len(g.matches))
g.add_match(get_match(o2, o3))
eq_([o2, o3], g.dupes)
eq_(3, len(g.matches))
g.add_match(get_match(o1, o4))
eq_([o2, o3], g.dupes)
eq_(4, len(g.matches))
g.add_match(get_match(o2, o4))
eq_([o2, o3], g.dupes)
eq_(5, len(g.matches))
g.add_match(get_match(o3, o4))
eq_([o2, o3, o4], g.dupes)
eq_(6, len(g.matches))
def test_len(self):
g = Group()
eq_(0, len(g))
g.add_match(get_match(NamedObject("foo", True), NamedObject("bar", True)))
eq_(2, len(g))
def test_add_same_match_twice(self):
g = Group()
m = get_match(NamedObject("foo", True), NamedObject("foo", True))
g.add_match(m)
eq_(2, len(g))
eq_(1, len(g.matches))
g.add_match(m)
eq_(2, len(g))
eq_(1, len(g.matches))
def test_in(self):
g = Group()
o1 = NamedObject("foo", True)
o2 = NamedObject("bar", True)
assert o1 not in g
g.add_match(get_match(o1, o2))
assert o1 in g
assert o2 in g
def test_remove(self):
g = Group()
o1 = NamedObject("foo", True)
o2 = NamedObject("bar", True)
o3 = NamedObject("bleh", True)
g.add_match(get_match(o1, o2))
g.add_match(get_match(o1, o3))
g.add_match(get_match(o2, o3))
eq_(3, len(g.matches))
eq_(3, len(g))
g.remove_dupe(o3)
eq_(1, len(g.matches))
eq_(2, len(g))
g.remove_dupe(o1)
eq_(0, len(g.matches))
eq_(0, len(g))
def test_remove_with_ref_dupes(self):
g = Group()
o1 = NamedObject("foo", True)
o2 = NamedObject("bar", True)
o3 = NamedObject("bleh", True)
g.add_match(get_match(o1, o2))
g.add_match(get_match(o1, o3))
g.add_match(get_match(o2, o3))
o1.is_ref = True
o2.is_ref = True
g.remove_dupe(o3)
eq_(0, len(g))
def test_switch_ref(self):
o1 = NamedObject(with_words=True)
o2 = NamedObject(with_words=True)
g = Group()
g.add_match(get_match(o1, o2))
assert o1 is g.ref
g.switch_ref(o2)
assert o2 is g.ref
eq_([o1], g.dupes)
g.switch_ref(o2)
assert o2 is g.ref
g.switch_ref(NamedObject("", True))
assert o2 is g.ref
def test_switch_ref_from_ref_dir(self):
# When the ref dupe is from a ref dir, switch_ref() does nothing
o1 = no(with_words=True)
o2 = no(with_words=True)
o1.is_ref = True
g = Group()
g.add_match(get_match(o1, o2))
g.switch_ref(o2)
assert o1 is g.ref
def test_get_match_of(self):
g = Group()
for m in get_match_triangle():
g.add_match(m)
o = g.dupes[0]
m = g.get_match_of(o)
assert g.ref in m
assert o in m
assert g.get_match_of(NamedObject("", True)) is None
assert g.get_match_of(g.ref) is None
def test_percentage(self):
# percentage should return the avg percentage in relation to the ref
m1, m2, m3 = get_match_triangle()
m1 = Match(m1[0], m1[1], 100)
m2 = Match(m2[0], m2[1], 50)
m3 = Match(m3[0], m3[1], 33)
g = Group()
g.add_match(m1)
g.add_match(m2)
g.add_match(m3)
eq_(75, g.percentage)
g.switch_ref(g.dupes[0])
eq_(66, g.percentage)
g.remove_dupe(g.dupes[0])
eq_(33, g.percentage)
g.add_match(m1)
g.add_match(m2)
eq_(66, g.percentage)
def test_percentage_on_empty_group(self):
g = Group()
eq_(0, g.percentage)
def test_prioritize(self):
m1, m2, m3 = get_match_triangle()
o1 = m1.first
o2 = m1.second
o3 = m2.second
o1.name = "c"
o2.name = "b"
o3.name = "a"
g = Group()
g.add_match(m1)
g.add_match(m2)
g.add_match(m3)
assert o1 is g.ref
assert g.prioritize(lambda x: x.name)
assert o3 is g.ref
def test_prioritize_with_tie_breaker(self):
# if the ref has the same key as one or more of the dupe, run the tie_breaker func among them
g = get_test_group()
o1, o2, o3 = g.ordered
g.prioritize(lambda x: 0, lambda ref, dupe: dupe is o3)
assert g.ref is o3
def test_prioritize_with_tie_breaker_runs_on_all_dupes(self):
# Even if a dupe is chosen to switch with ref with a tie breaker, we still run the tie breaker
# with other dupes and the newly chosen ref
g = get_test_group()
o1, o2, o3 = g.ordered
o1.foo = 1
o2.foo = 2
o3.foo = 3
g.prioritize(lambda x: 0, lambda ref, dupe: dupe.foo > ref.foo)
assert g.ref is o3
def test_prioritize_with_tie_breaker_runs_only_on_tie_dupes(self):
# The tie breaker only runs on dupes that had the same value for the key_func
g = get_test_group()
o1, o2, o3 = g.ordered
o1.foo = 2
o2.foo = 2
o3.foo = 1
o1.bar = 1
o2.bar = 2
o3.bar = 3
g.prioritize(lambda x: -x.foo, lambda ref, dupe: dupe.bar > ref.bar)
assert g.ref is o2
def test_prioritize_with_ref_dupe(self):
# when the ref dupe of a group is from a ref dir, make it stay on top.
g = get_test_group()
o1, o2, o3 = g
o1.is_ref = True
o2.size = 2
g.prioritize(lambda x: -x.size)
assert g.ref is o1
def test_prioritize_nothing_changes(self):
# prioritize() returns False when nothing changes in the group.
g = get_test_group()
g[0].name = "a"
g[1].name = "b"
g[2].name = "c"
assert not g.prioritize(lambda x: x.name)
def test_list_like(self):
g = Group()
o1, o2 = (NamedObject("foo", True), NamedObject("bar", True))
g.add_match(get_match(o1, o2))
assert g[0] is o1
assert g[1] is o2
def test_discard_matches(self):
g = Group()
o1, o2, o3 = (
NamedObject("foo", True),
NamedObject("bar", True),
NamedObject("baz", True),
)
g.add_match(get_match(o1, o2))
g.add_match(get_match(o1, o3))
g.discard_matches()
eq_(1, len(g.matches))
eq_(0, len(g.candidates))
class TestCaseGetGroups:
def test_empty(self):
r = get_groups([])
eq_([], r)
def test_simple(self):
item_list = [NamedObject("foo bar"), NamedObject("bar bleh")]
matches = getmatches(item_list)
m = matches[0]
r = get_groups(matches)
eq_(1, len(r))
g = r[0]
assert g.ref is m.first
eq_([m.second], g.dupes)
def test_group_with_multiple_matches(self):
# This results in 3 matches
item_list = [NamedObject("foo"), NamedObject("foo"), NamedObject("foo")]
matches = getmatches(item_list)
r = get_groups(matches)
eq_(1, len(r))
g = r[0]
eq_(3, len(g))
def test_must_choose_a_group(self):
item_list = [
NamedObject("a b"),
NamedObject("a b"),
NamedObject("b c"),
NamedObject("c d"),
NamedObject("c d"),
]
# There will be 2 groups here: group "a b" and group "c d"
# "b c" can go either of them, but not both.
matches = getmatches(item_list)
r = get_groups(matches)
eq_(2, len(r))
eq_(5, len(r[0]) + len(r[1]))
def test_should_all_go_in_the_same_group(self):
item_list = [
NamedObject("a b"),
NamedObject("a b"),
NamedObject("a b"),
NamedObject("a b"),
]
# There will be 2 groups here: group "a b" and group "c d"
# "b c" can fit in both, but it must be in only one of them
matches = getmatches(item_list)
r = get_groups(matches)
eq_(1, len(r))
def test_give_priority_to_matches_with_higher_percentage(self):
o1 = NamedObject(with_words=True)
o2 = NamedObject(with_words=True)
o3 = NamedObject(with_words=True)
m1 = Match(o1, o2, 1)
m2 = Match(o2, o3, 2)
r = get_groups([m1, m2])
eq_(1, len(r))
g = r[0]
eq_(2, len(g))
assert o1 not in g
assert o2 in g
assert o3 in g
def test_four_sized_group(self):
item_list = [NamedObject("foobar") for _ in range(4)]
m = getmatches(item_list)
r = get_groups(m)
eq_(1, len(r))
eq_(4, len(r[0]))
def test_referenced_by_ref2(self):
o1 = NamedObject(with_words=True)
o2 = NamedObject(with_words=True)
o3 = NamedObject(with_words=True)
m1 = get_match(o1, o2)
m2 = get_match(o3, o1)
m3 = get_match(o3, o2)
r = get_groups([m1, m2, m3])
eq_(3, len(r[0]))
def test_group_admissible_discarded_dupes(self):
# If, with a (A, B, C, D) set, all match with A, but C and D don't match with B and that the
# (A, B) match is the highest (thus resulting in an (A, B) group), still match C and D
# in a separate group instead of discarding them.
A, B, C, D = (NamedObject() for _ in range(4))
m1 = Match(A, B, 90) # This is the strongest "A" match
m2 = Match(A, C, 80) # Because C doesn't match with B, it won't be in the group
m3 = Match(A, D, 80) # Same thing for D
m4 = Match(C, D, 70) # However, because C and D match, they should have their own group.
groups = get_groups([m1, m2, m3, m4])
eq_(len(groups), 2)
g1, g2 = groups
assert A in g1
assert B in g1
assert C in g2
assert D in g2
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