File: bin2intelhex.c.simple

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/* 

  Quick and dirty program to make intel-hex from a binary.

  Written by R.E.Wolff@BitWizard.nl
  This file is in the public domain

  Typing started:

  Mon Jun 16 00:24:15 MET DST 1997

  programming stopped:

  Mon Jun 16 00:31:27 MET DST 1997

  debugging finished (2 bugs found):
  Mon Jun 16 00:32:52 MET DST 1997

--------------------------------------------------------- 

  Doc written in timeout. Everything else in this file was done while
  the timer was running.

  I promised "Mark Kopecki" that writing the bin-to-intel-hex
  converter would cost less than 15 minutes, and that it would be more
  trouble to find a converter on the net than to write the converter
  myself.  I ended up spending over half an hour searching for
  spec/converter/docs because of unreachable hosts on the internet. I
  got a file with docs, after that it was 8 minutes.....

--------------------------------------------------------- 

*/


#include <stdio.h>
#include <unistd.h>

/* Intel Hex format:
   
   ll aaaa tt dd....dd cc
 
   ll = length
   aaaa = address
   tt = type
   dd....dd = data
   cc = checksum.
*/


int main (int argc, char **argv)
{
  unsigned char buf[32];
  int addr = 0;
  int n,i;

  while ((n = read (0, buf+4, 16)) > 0) {
    buf[0] = n;
    buf[1] = addr >> 8;
    buf[2] = addr & 0xff;
    buf[3] = 0x00;
    buf[4+n] = 0x00;

    for (i=0;i<4+n;i++)
      buf[4+n] -= buf[i];
    printf (":");
    for (i=0;i<= 4+n;i++)
      printf ("%02x", buf[i]);
    printf ("\n");
    addr += n;
  }
  printf (":0000000001ff\n");
  exit (0);
}