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/** @file exam_misc.cpp
*
*/
/*
* GiNaC Copyright (C) 1999-2002 Johannes Gutenberg University Mainz, Germany
*
* This program is free software; you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation; either version 2 of the License, or
* (at your option) any later version.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with this program; if not, write to the Free Software
* Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
*/
#include "exams.h"
#define VECSIZE 30
static unsigned exam_expand_subs(void)
{
unsigned result = 0;
symbol a[VECSIZE];
ex e, aux;
for (unsigned i=0; i<VECSIZE; ++i)
e = e + a[i];
// prepare aux so it will swallow anything but a1^2:
aux = -e + a[0] + a[1];
e = expand(subs(expand(pow(e, 2)), a[0] == aux));
if (e != pow(a[1],2)) {
clog << "Denny Fliegner's quick consistency check erroneously returned "
<< e << "." << endl;
++result;
}
return result;
}
/* A simple modification of Denny Fliegner's three step consistency test:
* 1) e = (a0 + a1)^200
* 2) expand e
* 3) substitute a0 by -a1 in e
* after which e should return 0 (without expanding). */
static unsigned exam_expand_subs2(void)
{
unsigned result = 0;
symbol a("a"), b("b");
ex e, f;
e = pow(a+b,200).expand();
f = e.subs(a == -b);
if (f != 0) {
clog << "e = pow(a+b,200).expand(); f = e.subs(a == -b); erroneously returned "
<< f << " instead of simplifying to 0." << endl;
++result;
}
return result;
}
static unsigned exam_expand_power(void)
{
unsigned result = 0;
symbol x("x"), a("a"), b("b");
ex e;
e = pow(x,pow(a+b,2)-pow(a,2)-pow(b,2)-a*b*2).expand();
if (e != 1) {
clog << "e = pow(x,pow(a+b,2)-pow(a,2)-pow(b,2)-a*b*2).expand(); erroneously returned "
<< e << " instead of simplifying to 1." << endl;
++result;
}
return result;
}
static unsigned exam_sqrfree(void)
{
unsigned result = 0;
symbol x("x"), y("y");
ex e1, e2;
e1 = (1+x)*pow((2+x),2)*pow((3+x),3)*pow((4+x),4);
e2 = sqrfree(expand(e1),lst(x));
if (e1 != e2) {
clog << "sqrfree(expand(" << e1 << ")) erroneously returned "
<< e2 << endl;
++result;
}
e1 = (x+y)*pow((x+2*y),2)*pow((x+3*y),3)*pow((x+4*y),4);
e2 = sqrfree(expand(e1));
if (e1 != e2) {
clog << "sqrfree(expand(" << e1 << ")) erroneously returned "
<< e2 << endl;
++result;
}
e2 = sqrfree(expand(e1),lst(x));
if (e1 != e2) {
clog << "sqrfree(expand(" << e1 << "),[x]) erroneously returned "
<< e2 << endl;
++result;
}
e2 = sqrfree(expand(e1),lst(y));
if (e1 != e2) {
clog << "sqrfree(expand(" << e1 << "),[y]) erroneously returned "
<< e2 << endl;
++result;
}
e2 = sqrfree(expand(e1),lst(x,y));
if (e1 != e2) {
clog << "sqrfree(expand(" << e1 << "),[x,y]) erroneously returned "
<< e2 << endl;
++result;
}
return result;
}
/* Arithmetic Operators should behave just as one expects from built-in types.
* When somebody screws up the operators this routine will most probably fail
* to compile. Unfortunately we can only test the stuff that is allowed, not
* what is forbidden (e.g. e1+e2 = 42) since that must not compile. :-( */
static unsigned exam_operator_semantics(void)
{
unsigned result = 0;
ex e1, e2;
int i1, i2;
// Assignment should not return const ex though it may be obfuscated:
e1 = 7; e2 = 4;
i1 = 7; i2 = 4;
(e1 = e2) = 2;
(i1 = i2) = 2;
if (e1!=i1 || e2!=i2) {
clog << "Semantics of ex::operator=() screwed." << endl;
++result;
}
(e1 += e2) = 2;
(i1 += i2) = 2;
if (e1!=i1 || e2!=i2) {
clog << "Semantics of ex::operator=() screwed." << endl;
++result;
}
(e1 -= e2) = 2;
(i1 -= i2) = 2;
if (e1!=i1 || e2!=i2) {
clog << "Semantics of ex::operator=() screwed." << endl;
++result;
}
// Prefix/postfix increment/decrement behaviour:
e1 = 7; e2 = 4;
i1 = 7; i2 = 4;
e1 = (--e2 = 2)++;
i1 = (--i2 = 2)++;
if (e1!=i1 || e2!=i2) {
clog << "Semantics of increment/decrement operators screwed." << endl;
++result;
}
e1 = (++e2 = 2)--;
i1 = (++i2 = 2)--;
if (e1!=i1 || e2!=i2) {
clog << "Semantics of increment/decrement operators screwed." << endl;
++result;
}
// prefix increment/decrement must return an lvalue (contrary to postfix):
e1 = 7; e2 = 4;
i1 = 7; i2 = 4;
--++----e1; ++(++++++++(++++e2));
--++----i1; ++(++++++++(++++i2));
if (e1!=i1 || e2!=i2) {
clog << "Semantics of prefix increment/decrement operators screwed." << endl;
++result;
}
// This one has a good chance of detecting problems in self-assignment:
// (which incidentally was severely broken from version 0.7.3 to 0.8.2).
ex selfprobe = numeric("65536");
selfprobe = selfprobe;
if (!is_exactly_a<numeric>(selfprobe)) {
clog << "ex (of numeric) after self-assignment became " << selfprobe << endl;
++result;
}
return result;
}
/* This checks whether subs() works as intended in some special cases. */
static unsigned exam_subs(void)
{
unsigned result = 0;
symbol x("x");
ex e1, e2;
// This used to fail in GiNaC 1.0.5 because it first substituted
// x+1 -> (x-1)+1 -> x, and then substituted again x -> x-1, giving
// the wrong result
e1 = x+1;
e2 = e1.subs(x == x-1);
if (!e2.is_equal(x)) {
clog << "(x+1).subs(x==x-1) erroneously returned " << e2 << " instead of x" << endl;
++result;
}
e1 = sin(1+sin(x));
e2 = e1.subs(sin(wild()) == cos(wild()));
if (!e2.is_equal(cos(1+cos(x)))) {
clog << "sin(1+sin(x)).subs(sin($1)==cos($1)) erroneously returned " << e2 << " instead of cos(1+cos(x))" << endl;
++result;
}
return result;
}
unsigned exam_misc(void)
{
unsigned result = 0;
cout << "examining miscellaneous other things" << flush;
clog << "----------miscellaneous other things:" << endl;
result += exam_expand_subs(); cout << '.' << flush;
result += exam_expand_subs2(); cout << '.' << flush;
result += exam_expand_power(); cout << '.' << flush;
result += exam_sqrfree(); cout << '.' << flush;
result += exam_operator_semantics(); cout << '.' << flush;
result += exam_subs(); cout << '.' << flush;
if (!result) {
cout << " passed " << endl;
clog << "(no output)" << endl;
} else {
cout << " failed " << endl;
}
return result;
}
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