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/* Diagnose invalid back-reference in the ERE '()|\1' (BZ #18986).
Copyright (C) 2018-2022 Free Software Foundation, Inc.
This file is part of the GNU C Library.
The GNU C Library is free software; you can redistribute it and/or
modify it under the terms of the GNU Lesser General Public
License as published by the Free Software Foundation; either
version 2.1 of the License, or (at your option) any later version.
The GNU C Library is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public
License along with the GNU C Library; if not, see
<https://www.gnu.org/licenses/>. */
#include <regex.h>
#include <support/check.h>
static int
do_test (void)
{
char const pattern[] = "0|()0|\\1|0";
regex_t r;
TEST_VERIFY_EXIT (regcomp (&r, pattern, REG_EXTENDED) == REG_ESUBREG);
return 0;
}
#include <support/test-driver.c>
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