1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120
|
package merkletree
import (
"bytes"
"hash"
)
// VerifyProof takes a Merkle root, a proofSet, and a proofIndex and returns
// true if the first element of the proof set is a leaf of data in the Merkle
// root. False is returned if the proof set or Merkle root is nil, and if
// 'numLeaves' equals 0.
func VerifyProof(h hash.Hash, merkleRoot []byte, proofSet [][]byte, proofIndex uint64, numLeaves uint64) bool {
// Return false for nonsense input. A switch statement is used so that the
// cover tool will reveal if a case is not covered by the test suite. This
// would not be possible using a single if statement due to the limitations
// of the cover tool.
if merkleRoot == nil {
return false
}
if proofIndex >= numLeaves {
return false
}
// In a Merkle tree, every node except the root node has a sibling.
// Combining the two siblings in the correct order will create the parent
// node. Each of the remaining hashes in the proof set is a sibling to a
// node that can be built from all of the previous elements of the proof
// set. The next node is built by taking:
//
// H(0x01 || sibling A || sibling B)
//
// The difficulty of the algorithm lies in determining whether the supplied
// hash is sibling A or sibling B. This information can be determined by
// using the proof index and the total number of leaves in the tree.
//
// A pair of two siblings forms a subtree. The subtree is complete if it
// has 1 << height total leaves. When the subtree is complete, the position
// of the proof index within the subtree can be determined by looking at
// the bounds of the subtree and determining if the proof index is in the
// first or second half of the subtree.
//
// When the subtree is not complete, either 1 or 0 of the remaining hashes
// will be sibling B. All remaining hashes after that will be sibling A.
// This is true because of the way that orphans are merged into the Merkle
// tree - an orphan at height n is elevated to height n + 1, and only
// hashed when it is no longer an orphan. Each subtree will therefore merge
// with at most 1 orphan to the right before becoming an orphan itself.
// Orphan nodes are always merged with larger subtrees to the left.
//
// One vulnerability with the proof verification is that the proofSet may
// not be long enough. Before looking at an element of proofSet, a check
// needs to be made that the element exists.
// The first element of the set is the original data. A sibling at height 1
// is created by getting the leafSum of the original data.
height := 0
if len(proofSet) <= height {
return false
}
sum := leafSum(h, proofSet[height])
height++
// While the current subtree (of height 'height') is complete, determine
// the position of the next sibling using the complete subtree algorithm.
// 'stableEnd' tells us the ending index of the last full subtree. It gets
// initialized to 'proofIndex' because the first full subtree was the
// subtree of height 1, created above (and had an ending index of
// 'proofIndex').
stableEnd := proofIndex
for {
// Determine if the subtree is complete. This is accomplished by
// rounding down the proofIndex to the nearest 1 << 'height', adding 1
// << 'height', and comparing the result to the number of leaves in the
// Merkle tree.
subTreeStartIndex := (proofIndex / (1 << uint(height))) * (1 << uint(height)) // round down to the nearest 1 << height
subTreeEndIndex := subTreeStartIndex + (1 << (uint(height))) - 1 // subtract 1 because the start index is inclusive
if subTreeEndIndex >= numLeaves {
// If the Merkle tree does not have a leaf at index
// 'subTreeEndIndex', then the subtree of the current height is not
// a complete subtree.
break
}
stableEnd = subTreeEndIndex
// Determine if the proofIndex is in the first or the second half of
// the subtree.
if len(proofSet) <= height {
return false
}
if proofIndex-subTreeStartIndex < 1<<uint(height-1) {
sum = nodeSum(h, sum, proofSet[height])
} else {
sum = nodeSum(h, proofSet[height], sum)
}
height++
}
// Determine if the next hash belongs to an orphan that was elevated. This
// is the case IFF 'stableEnd' (the last index of the largest full subtree)
// is equal to the number of leaves in the Merkle tree.
if stableEnd != numLeaves-1 {
if len(proofSet) <= height {
return false
}
sum = nodeSum(h, sum, proofSet[height])
height++
}
// All remaining elements in the proof set will belong to a left sibling.
for height < len(proofSet) {
sum = nodeSum(h, proofSet[height], sum)
height++
}
// Compare our calculated Merkle root to the desired Merkle root.
if bytes.Compare(sum, merkleRoot) == 0 {
return true
}
return false
}
|