1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32
|
\DOC CONJ_ACI_RULE
\TYPE {CONJ_ACI_RULE : term -> thm}
\SYNOPSIS
Proves equivalence of two conjunctions containing same set of conjuncts.
\DESCRIBE
The call {CONJ_ACI_RULE `t1 /\ ... /\ tn <=> u1 /\ ... /\ um`}, where both
sides of the equation are conjunctions of exactly the same set of conjuncts,
(with arbitrary ordering, association, and repetitions), will return the
corresponding theorem {|- t1 /\ ... /\ tn <=> u1 /\ ... /\ um}.
\FAILURE
Fails if applied to a term that is not a Boolean equation or the two sets of
conjuncts are different.
\EXAMPLE
{
# CONJ_ACI_RULE `(a /\ b) /\ (a /\ c) <=> (a /\ (c /\ a)) /\ b`;;
val it : thm = |- (a /\ b) /\ a /\ c <=> (a /\ c /\ a) /\ b
}
\COMMENTS
The same effect can be had with the more general {AC} construct. However, for
the special case of conjunction, {CONJ_ACI_RULE} is substantially more
efficient when there are many conjuncts involved.
\SEEALSO
AC, CONJ_CANON_CONV, DISJ_ACI_RULE.
\ENDDOC
|