1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300 301 302 303 304 305 306 307 308 309 310 311 312 313 314 315 316 317 318 319 320 321 322 323 324 325 326 327 328 329 330 331 332 333 334 335 336 337 338 339 340 341 342 343 344 345 346 347 348 349 350 351 352 353 354 355 356 357 358 359 360 361 362 363 364 365 366 367 368 369 370 371 372 373 374 375 376 377 378 379 380 381 382 383 384 385 386 387 388 389 390 391 392 393 394 395 396 397 398 399 400 401 402 403 404 405 406 407 408 409 410 411 412 413 414 415 416 417 418 419 420 421 422 423 424 425 426 427 428 429 430 431 432 433 434 435 436 437 438 439 440 441 442 443 444 445 446 447 448 449 450 451 452 453 454 455 456 457 458 459 460 461 462 463 464 465 466 467 468 469 470 471 472 473 474 475 476 477 478 479 480 481 482 483 484 485 486 487 488 489 490 491 492 493 494 495 496 497 498 499 500 501 502 503 504 505 506 507 508 509 510 511 512 513 514 515 516 517 518 519 520 521 522 523 524 525 526 527 528 529 530 531 532 533 534 535 536 537 538 539 540 541 542 543 544 545 546 547 548 549 550 551 552 553 554 555 556 557 558 559 560 561 562 563 564 565 566 567 568 569 570 571 572 573 574 575 576 577 578 579 580 581 582 583 584 585 586 587 588 589 590 591 592 593 594 595 596 597 598 599 600 601 602 603 604 605 606 607 608 609 610 611 612 613 614 615 616 617 618 619 620 621 622 623 624 625 626 627 628 629 630 631 632 633 634 635 636 637 638 639 640 641 642 643 644 645 646 647 648 649 650 651 652 653 654 655 656 657 658 659 660 661 662 663 664 665 666 667 668 669 670 671 672 673 674 675 676 677 678 679 680 681 682 683 684 685 686 687 688 689 690 691 692 693 694 695 696 697 698 699 700 701 702 703 704 705 706 707 708 709 710 711 712 713 714 715 716 717 718 719 720 721 722 723 724 725 726 727 728 729 730 731 732 733 734 735 736 737 738 739 740 741 742 743 744 745 746 747 748 749 750 751 752 753 754 755 756 757 758 759 760 761 762 763 764 765 766 767 768 769 770 771 772 773 774 775 776 777 778 779 780 781 782 783 784 785 786 787 788 789 790 791 792 793 794 795 796 797 798 799 800 801 802 803 804 805 806 807 808 809 810 811 812 813 814 815 816 817 818 819 820 821 822 823 824 825 826 827 828 829 830 831 832 833 834 835 836 837 838 839 840 841 842 843 844 845 846 847 848 849 850 851 852 853 854 855 856 857 858 859 860 861 862 863 864 865 866 867 868 869 870 871 872 873 874 875 876 877 878 879 880 881 882 883 884 885 886 887 888 889 890 891 892 893 894 895 896 897 898 899 900 901 902 903 904 905 906 907 908 909 910 911 912 913 914 915 916 917 918 919 920 921 922 923 924 925 926 927 928 929 930 931 932 933 934 935 936 937 938 939 940 941 942 943 944 945 946 947 948 949 950 951 952 953 954 955 956 957 958 959 960 961 962 963 964 965 966 967 968 969 970 971 972 973 974 975 976 977 978 979 980 981 982 983 984 985 986 987 988 989 990 991 992 993 994 995 996 997 998 999 1000 1001 1002 1003 1004 1005 1006 1007 1008 1009 1010 1011 1012 1013 1014 1015 1016 1017 1018 1019 1020 1021 1022 1023 1024 1025 1026 1027 1028 1029 1030 1031 1032 1033 1034 1035 1036 1037 1038 1039 1040 1041 1042 1043 1044 1045 1046 1047 1048 1049 1050 1051
|
%=============================================================================%
% HOL 88 Version 2.0 %
% %
% FILE NAME: mk_tree.ml %
% %
% DESCRIPTION: Creates the theory "tree.th" containing the %
% definition of a type of (bare) trees. %
% %
% AUTHOR: T. F. Melham (87.07.27) %
% %
% PARENTS: list.th %
% WRITES FILES: tree.th %
% %
% University of Cambridge %
% Hardware Verification Group %
% Computer Laboratory %
% New Museums Site %
% Pembroke Street %
% Cambridge CB2 3QG %
% England %
% %
% COPYRIGHT: T. F. Melham 1988 %
% %
% REVISION HISTORY: Mike Gordon and John Carroll (26 August 1989) %
%=============================================================================%
% Create the new theory "tree.th". %
new_theory `tree`;;
% The theory of lists is a parent theory. %
new_parent `list`;;
% fetch theorems from list.th %
let list_Axiom = theorem `list` `list_Axiom`
and list_INDUCT = theorem `list` `list_INDUCT`
and CONS_11 = theorem `list` `CONS_11`
and NULL = theorem `list` `NULL`
and NOT_CONS_NIL = theorem `list` `NOT_CONS_NIL`
and NOT_NIL_CONS = theorem `list` `NOT_NIL_CONS`
and ALL_EL_CONJ = theorem `list` `ALL_EL_CONJ`;;
% theorem changed to definition for HOL88 %
let ALL_EL = definition `list` `ALL_EL`
and MAP = definition `list` `MAP`
and HD = definition `list` `HD`
and TL = definition `list` `TL`;;
% Need arithmetic definitions. %
let LESS_OR_EQ = definition `arithmetic` `LESS_OR_EQ`;;
% theorem changed to definition for HOL88 %
let EXP = definition `arithmetic` `EXP`;;
% Need various arithmetic theorems. %
let LESS_ADD_1 = theorem `arithmetic` `LESS_ADD_1` and
ADD_SYM = theorem `arithmetic` `ADD_SYM` and
EXP_ADD = theorem `arithmetic` `EXP_ADD` and
MULT_ASSOC = theorem `arithmetic` `MULT_ASSOC` and
MULT_EXP_MONO = theorem `arithmetic` `MULT_EXP_MONO` and
MULT_CLAUSES = theorem `arithmetic` `MULT_CLAUSES` and
ADD_CLAUSES = theorem `arithmetic` `ADD_CLAUSES` and
NOT_ODD_EQ_EVEN = theorem `arithmetic` `NOT_ODD_EQ_EVEN` and
LESS_CASES = theorem `arithmetic` `LESS_CASES` and
WOP = theorem `arithmetic` `WOP` and
num_CASES = theorem `arithmetic` `num_CASES` and
NOT_LESS = theorem `arithmetic` `NOT_LESS` and
LESS_IMP_LESS_OR_EQ = theorem `arithmetic` `LESS_IMP_LESS_OR_EQ` and
LESS_EQ_TRANS = theorem `arithmetic` `LESS_EQ_TRANS` and
LESS_EQ_ADD = theorem `arithmetic` `LESS_EQ_ADD` and
LESS_TRANS = theorem `arithmetic` `LESS_TRANS` and
LESS_EQ_ANTISYM = theorem `arithmetic` `LESS_EQ_ANTISYM` and
LESS_EQ = theorem `arithmetic` `LESS_EQ`;;
% Need theorems from prim_rec.th %
let INV_SUC_EQ = theorem `prim_rec` `INV_SUC_EQ` and
PRIM_REC_THM = theorem `prim_rec` `PRIM_REC_THM` and
LESS_0 = theorem `prim_rec` `LESS_0` and
LESS_SUC_REFL = theorem `prim_rec` `LESS_SUC_REFL` and
LESS_THM = theorem `prim_rec` `LESS_THM` and
LESS_SUC = theorem `prim_rec` `LESS_SUC` and
NOT_LESS_0 = theorem `prim_rec` `NOT_LESS_0` and
LESS_REFL = theorem `prim_rec` `LESS_REFL`;;
% Need theorems from num.th %
let NOT_SUC = theorem `num` `NOT_SUC` and
INDUCTION = theorem `num` `INDUCTION`;;
% --------------------------------------------------------------------- %
% Load code needed %
% --------------------------------------------------------------------- %
% Load the axiom scheme for numerals (NB: uncompiled!). %
loadt (concat ml_dir_pathname `numconv.ml`);;
% We need to load in the induction tactic. It's in ml/ind.ml %
% but it is part of hol rather than basic hol, so it's loaded %
% in uncompiled. %
% %
% TFM 88.04.02 %
loadt (concat ml_dir_pathname `ind.ml`);;
% Note that prim_rec_ml.o must be recompiled if basic-hol has been. %
% So we just load prim_rec.ml uncompiled. %
% %
% TFM 88.04.02 %
loadt (concat ml_dir_pathname `prim_rec.ml`);;
% Create an induction tactic for :num %
let INDUCT_TAC = INDUCT_THEN (theorem `num` `INDUCTION`) ASSUME_TAC;;
% Create a tactic for list induction. %
let LIST_INDUCT_TAC = INDUCT_THEN list_INDUCT ASSUME_TAC;;
% --------------------------------------------------------------------- %
% Define a one-to-one coding function from (num)list -> num: %
% %
% The coding function used will be iteration of (2n + 1) (2 ^ p)... %
% --------------------------------------------------------------------- %
% First a few arithmetic lemmas: %
let arith_lemma =
TAC_PROOF(
([], "!p q n m.
p < q ==>
~(((SUC(n + n)) * (2 EXP p)) = ((SUC(m + m)) * (2 EXP q)))"),
REPEAT GEN_TAC THEN
DISCH_THEN (STRIP_THM_THEN SUBST1_TAC o MATCH_MP LESS_ADD_1) THEN
CONV_TAC (REDEPTH_CONV num_CONV) THEN
MAP_EVERY ONCE_REWRITE_TAC [[ADD_SYM];[EXP_ADD]] THEN
REWRITE_TAC [MULT_ASSOC;MULT_EXP_MONO] THEN
REWRITE_TAC [EXP_ADD;MULT_ASSOC;EXP] THEN
REWRITE_TAC [MULT_CLAUSES;ADD_CLAUSES] THEN
MATCH_ACCEPT_TAC NOT_ODD_EQ_EVEN);;
% The next two theorems state that the function (2n + 1)(2 ^ p) is 1-1 %
let fun_11_1 =
TAC_PROOF(
([], "!p q n m.
((SUC(n + n)) * (2 EXP p) = (SUC(m + m)) * (2 EXP q)) ==>
(p = q)"),
REPEAT STRIP_TAC THEN FIRST_ASSUM (ASSUME_TAC o SYM) THEN
IMP_RES_TAC (REWRITE_RULE []
((CONV_RULE CONTRAPOS_CONV) (SPEC_ALL arith_lemma))) THEN
STRIP_ASSUME_TAC
(REWRITE_RULE [LESS_OR_EQ] (SPECL ["q:num";"p:num"] LESS_CASES)) THEN
RES_TAC);;
let fun_11_2 =
TAC_PROOF(
([], "!p q n m. ((SUC(n + n)) * (2 EXP p) = (SUC(m + m)) * (2 EXP q)) ==>
(n = m)"),
REPEAT STRIP_TAC THEN
IMP_RES_THEN SUBST_ALL_TAC fun_11_1 THEN
POP_ASSUM (MP_TAC o (CONV_RULE (DEPTH_CONV num_CONV))) THEN
REWRITE_TAC [MULT_EXP_MONO;INV_SUC_EQ] THEN
MAP_EVERY SPEC_TAC ["m:num","m:num";"n:num","n:num"] THEN
REPEAT (INDUCT_TAC THEN REWRITE_TAC [ADD_CLAUSES]) THENL
[REWRITE_TAC [NOT_EQ_SYM(SPEC_ALL NOT_SUC)];
REWRITE_TAC [NOT_SUC];
ASM_REWRITE_TAC [INV_SUC_EQ]]);;
% --------------------------------------------------------------------- %
% Representation of trees ---- :num. %
% --------------------------------------------------------------------- %
% The representation type for trees is: ":num". %
let ty = ":num";;
% node_REP: makes a tree representation from a tree representation list.%
% The idea is that the term "node [t1;t2;t3;t4...]" represents the tree %
% with branches represented by t1, t2, ... etc. %
% node_REP is defined using the coding function above... %
let node_REP =
new_recursive_definition false list_Axiom `node_REP`
"(node_REP NIL = 0) /\
(node_REP (CONS h t) = ((SUC(h+h)) * (2 EXP (node_REP t))))";;
% Prove that node_REP is one-to-one: %
let node_REP_one_one =
TAC_PROOF(([], "!l1 l2. (node_REP l1 = node_REP l2) = (l1 = l2)"),
LIST_INDUCT_TAC THENL
[LIST_INDUCT_TAC THEN
REWRITE_TAC [node_REP;NOT_NIL_CONS] THEN
CONV_TAC (DEPTH_CONV num_CONV) THEN
REWRITE_TAC [REWRITE_RULE [MULT_CLAUSES]
(SPECL ["p:num";"q:num";"0"] MULT_EXP_MONO)] THEN
REWRITE_TAC [NOT_EQ_SYM (SPEC_ALL NOT_SUC)];
GEN_TAC THEN LIST_INDUCT_TAC THENL
[REWRITE_TAC [node_REP;NOT_CONS_NIL] THEN
CONV_TAC (DEPTH_CONV num_CONV) THEN
REWRITE_TAC [REWRITE_RULE [MULT_CLAUSES]
(SPECL ["p:num";"q:num";"n:num";"0"] MULT_EXP_MONO)] THEN
REWRITE_TAC [NOT_SUC];
REWRITE_TAC [node_REP;CONS_11] THEN
MAP_EVERY POP_ASSUM [K ALL_TAC;
SUBST1_TAC o SYM o SPEC_ALL] THEN
REPEAT (STRIP_TAC ORELSE EQ_TAC) THENL
[IMP_RES_TAC fun_11_2;
IMP_RES_TAC fun_11_1;
ASM_REWRITE_TAC []]]]);;
% --------------------------------------------------------------------- %
% DEFINITION of the subset of ":num" that will represent trees... %
% .... and related theorems. %
% --------------------------------------------------------------------- %
% Definition of valid tree representations. Is_tree_REP is true of %
% anything constructed by "node_REP". %
let Is_tree_REP =
new_definition
(`Is_tree_REP`,
"Is_tree_REP =
\t:^ty. !P. (!tl. ALL_EL P tl ==> P(node_REP tl)) ==> P t");;
% A little lemma about ALL_EL and Is_tree_REP. %
let ALL_EL_Is_tree_REP =
TAC_PROOF(
([], "!trl.
ALL_EL Is_tree_REP trl =
!P. ALL_EL (\t.(!tl. ALL_EL P tl ==> P(node_REP tl)) ==> P t) trl"),
REWRITE_TAC [Is_tree_REP] THEN
LIST_INDUCT_TAC THEN
ASM_REWRITE_TAC [ALL_EL] THEN
CONV_TAC (REDEPTH_CONV BETA_CONV) THEN
REPEAT (STRIP_TAC ORELSE EQ_TAC) THEN
RES_TAC THEN ASM_REWRITE_TAC[]);;
% Show that if ALL_EL Is_tree_REP trl then Is_tree_REP (node_REP v trl). %
let Is_tree_lemma1 =
TAC_PROOF
(([], "!trl. ALL_EL Is_tree_REP trl ==> Is_tree_REP (node_REP trl)"),
REWRITE_TAC [Is_tree_REP;ALL_EL_Is_tree_REP] THEN
CONV_TAC (REDEPTH_CONV BETA_CONV) THEN
GEN_TAC THEN
DISCH_THEN (\thm. REPEAT STRIP_TAC THEN MP_TAC (SPEC_ALL thm)) THEN
ASM_REWRITE_TAC [ETA_AX]);;
% A little propositional tautology: %
let taut1 =
TAC_PROOF(([], "!a b. ~(a ==> b) = (a /\ ~b)"),
REWRITE_TAC [IMP_DISJ_THM;DE_MORGAN_THM]);;
% Show that if t is a tree then it must be of the form "node_REP tl" for%
% some v:* and tl (where each object in tl staifies Is_tree_REP). %
let Is_tree_lemma2 =
TAC_PROOF(
([], "!t. Is_tree_REP t ==>
?trl. ALL_EL Is_tree_REP trl /\ (t = node_REP trl)"),
GEN_TAC THEN CONV_TAC CONTRAPOS_CONV THEN
SUBST1_TAC (RIGHT_BETA (AP_THM Is_tree_REP "t:^ty")) THEN
CONV_TAC (REDEPTH_CONV NOT_EXISTS_CONV) THEN
CONV_TAC (DEPTH_CONV NOT_FORALL_CONV) THEN
DISCH_TAC THEN
EXISTS_TAC "\x:^ty. ?tl. ALL_EL Is_tree_REP tl /\ (x = node_REP tl)" THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REWRITE_TAC [taut1] THEN
REPEAT STRIP_TAC THENL
[EXISTS_TAC "tl:^ty list" THEN
POP_ASSUM MP_TAC THEN POP_ASSUM (K ALL_TAC) THEN
SPEC_TAC ("tl:^ty list","tl:^ty list") THEN
LIST_INDUCT_TAC THEN
ASM_REWRITE_TAC [ALL_EL] THEN
CONV_TAC (REDEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THENL
[IMP_RES_TAC Is_tree_lemma1 THEN
RES_TAC THEN ASM_REWRITE_TAC[];
RES_TAC THEN FIRST_ASSUM ACCEPT_TAC];
RES_TAC]);;
% Show that Is_tree_REP(node_REP tl) ==> ALL_EL Is_tree_REP tl %
let Is_tree_lemma3 =
let spec = SPEC "node_REP tl" Is_tree_lemma2 in
let rew1 = REWRITE_RULE [node_REP_one_one] spec in
let [t1;t2] = CONJUNCTS (SELECT_RULE (UNDISCH rew1)) in
GEN_ALL(DISCH_ALL (SUBS [SYM t2] t1));;
% Main result... of the past few lemmas. %
% Show that !v tl. Is_tree_REP (node_REP v tl) = ALL_EL Is_tree_REP tl %
let Is_tree_lemma4 =
TAC_PROOF(([], "!tl. Is_tree_REP (node_REP tl) = ALL_EL Is_tree_REP tl"),
REPEAT (STRIP_TAC ORELSE EQ_TAC) THENL
[IMP_RES_TAC Is_tree_lemma3;
IMP_RES_TAC Is_tree_lemma1 THEN
POP_ASSUM MATCH_ACCEPT_TAC]);;
% Show that a tree representation exists. %
let Exists_tree_REP =
TAC_PROOF(([], "?t:^ty. Is_tree_REP t"),
EXISTS_TAC "node_REP NIL" THEN
REWRITE_TAC [Is_tree_REP] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
GEN_TAC THEN DISCH_THEN MATCH_MP_TAC THEN
REWRITE_TAC [ALL_EL]);;
% --------------------------------------------------------------------- %
% Introduction of the new type of trees. %
% --------------------------------------------------------------------- %
% Define the new type. %
let tree_TY_DEF =
new_type_definition
(`tree`,
rator(snd(dest_exists(concl Exists_tree_REP))),
Exists_tree_REP);;
% --------------------------------------------------------------------- %
% Define a representation function, REP_tree, from the type tree to %
% the representing type, and the inverse abstraction %
% function ABS_tree, and prove some trivial lemmas about them. %
% --------------------------------------------------------------------- %
let tree_ISO_DEF =
define_new_type_bijections
`tree_ISO_DEF` `ABS_tree` `REP_tree` tree_TY_DEF;;
let R_11 = prove_rep_fn_one_one tree_ISO_DEF and
R_ONTO = prove_rep_fn_onto tree_ISO_DEF and
A_11 = prove_abs_fn_one_one tree_ISO_DEF and
A_ONTO = prove_abs_fn_onto tree_ISO_DEF and
A_R = CONJUNCT1 tree_ISO_DEF and
R_A = CONJUNCT2 tree_ISO_DEF;;
% Definition of node -- the constructor for trees. %
let node =
new_definition
(`node`,
"node tl = (ABS_tree (node_REP (MAP REP_tree tl)))");;
% Definition of dest_node: inverse of node. %
let dest_node =
new_definition
(`dest_node`, "!t. dest_node t = @p. t = node p");;
% --------------------------------------------------------------------- %
% Several lemmas about ABS and REP follow... %
% --------------------------------------------------------------------- %
let IS_REP_lemma =
TAC_PROOF(([], "!tl.ALL_EL Is_tree_REP (MAP REP_tree (tl:(tree)list))"),
LIST_INDUCT_TAC THEN
ASM_REWRITE_TAC [MAP;ALL_EL;R_ONTO] THEN
STRIP_TAC THEN EXISTS_TAC "h:tree" THEN REFL_TAC);;
% Prove that REP(ABS x) = x. %
let REP_ABS_lemma =
TAC_PROOF(
([], "!tl. REP_tree(node tl) = (node_REP (MAP REP_tree tl))"),
REWRITE_TAC [node;SYM(SPEC_ALL R_A)] THEN
REPEAT GEN_TAC THEN
REWRITE_TAC [Is_tree_lemma4] THEN
SPEC_TAC ("tl:(tree)list","tl:(tree)list") THEN
LIST_INDUCT_TAC THEN
ASM_REWRITE_TAC [MAP;ALL_EL;R_ONTO] THEN
GEN_TAC THEN EXISTS_TAC "h:tree" THEN REFL_TAC);;
let ABS_REP =
TAC_PROOF(
([], "!tl. Is_tree_REP (node_REP (MAP REP_tree tl))"),
REWRITE_TAC [Is_tree_lemma4] THEN
MATCH_ACCEPT_TAC IS_REP_lemma);;
let ABS_11_lemma =
let a11 = SPECL ["node_REP (MAP REP_tree tl1)";
"node_REP (MAP REP_tree tl2)"] A_11 in
REWRITE_RULE [ABS_REP] a11;;
% Prove that node is one-to-one... save this theorem. %
let node_11 =
prove_thm
(`node_11`,
"!tl1 tl2. (node tl1 = node tl2) = (tl1 = tl2)",
REWRITE_TAC [node;ABS_11_lemma;node_REP_one_one] THEN
REPEAT (STRIP_TAC ORELSE EQ_TAC) THEN
ASM_REWRITE_TAC [] THEN
POP_ASSUM MP_TAC THEN
MAP_EVERY SPEC_TAC [("tl1:(tree)list","tl1:(tree)list");
("tl2:(tree)list","tl2:(tree)list")] THEN
LIST_INDUCT_TAC THENL
[LIST_INDUCT_TAC THEN REWRITE_TAC [MAP;NOT_CONS_NIL];
GEN_TAC THEN LIST_INDUCT_TAC THENL
[REWRITE_TAC [MAP;NOT_EQ_SYM(SPEC_ALL NOT_CONS_NIL)];
ASM_REWRITE_TAC [MAP;CONS_11;R_11] THEN
REPEAT STRIP_TAC THEN RES_TAC THEN
FIRST_ASSUM ACCEPT_TAC]]);;
% Some more lemmas about ABS and REP.... %
let A_R_list =
TAC_PROOF(([], "!tl:(tree)list. tl = MAP ABS_tree (MAP REP_tree tl)"),
LIST_INDUCT_TAC THEN
REWRITE_TAC [MAP;A_R;CONS_11] THEN
POP_ASSUM ACCEPT_TAC);;
let R_A_R =
TAC_PROOF(([], "REP_tree(ABS_tree(REP_tree (t:tree))) = (REP_tree t)"),
REWRITE_TAC [SYM(SPEC_ALL R_A)] THEN
REWRITE_TAC [R_ONTO] THEN
EXISTS_TAC "t:tree" THEN REFL_TAC);;
let Is_R =
TAC_PROOF(([], "Is_tree_REP (REP_tree (t:tree))"),
REWRITE_TAC [R_ONTO] THEN
EXISTS_TAC "t:tree" THEN REFL_TAC);;
let R_A_R_list =
TAC_PROOF(
([], "!tl:(tree)list.
MAP REP_tree (MAP ABS_tree (MAP REP_tree tl)) = (MAP REP_tree tl)"),
LIST_INDUCT_TAC THEN ASM_REWRITE_TAC [MAP;R_A_R]);;
let A_ONTO_list =
TAC_PROOF(([], "!tl:(tree)list. ?trl.
((tl = MAP ABS_tree trl) /\ (ALL_EL Is_tree_REP trl))"),
LIST_INDUCT_TAC THENL
[EXISTS_TAC "NIL:(^ty)list" THEN REWRITE_TAC [MAP;ALL_EL];
POP_ASSUM STRIP_ASSUME_TAC THEN
STRIP_TAC THEN
STRIP_ASSUME_TAC (SPEC "h:tree" A_ONTO) THEN
EXISTS_TAC "CONS (r:^ty) trl" THEN
ASM_REWRITE_TAC [CONS_11;MAP;ALL_EL]]);;
let R_ONTO_list =
TAC_PROOF(
([], "!trl:(^ty)list.
ALL_EL Is_tree_REP trl ==> ?tl. trl = MAP REP_tree tl"),
LIST_INDUCT_TAC THENL
[DISCH_TAC THEN EXISTS_TAC "NIL:(tree)list" THEN REWRITE_TAC [MAP];
REWRITE_TAC [ALL_EL;R_ONTO] THEN
REPEAT STRIP_TAC THEN
RES_THEN STRIP_ASSUME_TAC THEN
EXISTS_TAC "CONS (a:tree) tl" THEN
ASM_REWRITE_TAC [MAP]]);;
let R_A_list =
TAC_PROOF(
([], "!trl. ALL_EL Is_tree_REP (trl:(^ty)list) ==>
(MAP REP_tree (MAP ABS_tree trl) = trl)"),
LIST_INDUCT_TAC THEN ASM_REWRITE_TAC [ALL_EL;MAP;R_A] THEN
REPEAT STRIP_TAC THEN
RES_TAC THEN ASM_REWRITE_TAC[]);;
% Two lemmas showing how induction on trees relates to induction on %
% tree representations.... %
let induct_lemma1 =
TAC_PROOF(
([], "(!tl. ALL_EL P tl ==> (P(node tl))) =
(!trl. ALL_EL Is_tree_REP trl ==>
ALL_EL (\x.P(ABS_tree x)) trl ==>
((\x.P(ABS_tree x)) (node_REP trl)))"),
let ALL_EL_MAP = TAC_PROOF(([],
"!l P f.ALL_EL P (MAP (f:*->**) (l:(*)list)) = ALL_EL (\x.P(f x)) l"),
LIST_INDUCT_TAC THEN ASM_REWRITE_TAC [MAP;ALL_EL] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN REPEAT GEN_TAC THEN REFL_TAC) in
EQ_TAC THENL
[DISCH_TAC THEN GEN_TAC THEN
DISCH_THEN ((STRIP_THM_THEN SUBST1_TAC) o (MATCH_MP R_ONTO_list)) THEN
CONV_TAC (ONCE_DEPTH_CONV BETA_CONV) THEN
REWRITE_TAC [SYM(SPEC_ALL ALL_EL_MAP);SYM(SPEC_ALL A_R_list)] THEN
ASM_REWRITE_TAC [SYM(SPEC_ALL node)];
DISCH_TAC THEN GEN_TAC THEN
STRIP_ASSUME_TAC (SPEC_ALL A_ONTO_list) THEN
FIRST_ASSUM SUBST_ALL_TAC THEN
REWRITE_TAC [node;ALL_EL_MAP] THEN
IMP_RES_TAC R_A_list THEN
REPEAT STRIP_TAC THEN RES_TAC THEN
POP_ASSUM (MP_TAC o CONV_RULE BETA_CONV) THEN
ASM_REWRITE_TAC []]);;
let induct_lemma2 =
TAC_PROOF(
([], "(!t:tree. P t:bool) =
(!rep. Is_tree_REP rep ==>
(\r. Is_tree_REP r /\ ((\x.P(ABS_tree x)) r)) rep)"),
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
EQ_TAC THENL
[CONV_TAC (ONCE_DEPTH_CONV BETA_CONV) THEN
REWRITE_TAC [R_ONTO] THEN
REPEAT STRIP_TAC THENL
[EXISTS_TAC "a:tree" THEN FIRST_ASSUM ACCEPT_TAC;
ASM_REWRITE_TAC [A_R]];
CONV_TAC (ONCE_DEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THEN
STRIP_ASSUME_TAC (SPEC "t:tree" A_ONTO) THEN
RES_TAC THEN ASM_REWRITE_TAC[]]);;
% Induction on trees. %
let tree_Induct =
prove_thm
(`tree_Induct`,
"!P. (!tl. ALL_EL P tl ==> P (node tl)) ==> !t. P t",
REWRITE_TAC [induct_lemma1;induct_lemma2] THEN
GEN_TAC THEN DISCH_TAC THEN GEN_TAC THEN
let is_thm = RIGHT_BETA (AP_THM Is_tree_REP "trep:^ty") in
DISCH_THEN (MATCH_MP_TAC o (REWRITE_RULE [is_thm])) THEN
REWRITE_TAC [ALL_EL_CONJ] THEN
REPEAT STRIP_TAC THEN CONV_TAC BETA_CONV THEN
RES_TAC THEN ASM_REWRITE_TAC [Is_tree_lemma4]);;
% --------------------------------------------------------------------- %
% tree_INDUCT: thm -> thm %
% %
% A |- !tl. ALL_EL \t.P[t] tl ==> P[node tl] %
% ======================================================= %
% A |- !t. P[t] %
% %
% --------------------------------------------------------------------- %
let tree_INDUCT th =
(let (tl,body) = dest_forall(concl th) in
let (asm,con) = (dest_imp body) in
let ALL_EL,[P;tll] = strip_comb asm in
let b = genvar bool_ty in
let concth = SYM(RIGHT_BETA(REFL "^P(node ^tl)")) and
IND = SPEC P tree_Induct and
th' = (SPEC tl th) in
let th1 = SUBST [concth,b]
"^(concl th') = (ALL_EL ^P ^tl ==> ^b)"
(REFL (concl th')) in
let th2 = GEN tl (EQ_MP th1 th') in
CONV_RULE (ONCE_DEPTH_CONV BETA_CONV) (MP IND th2)?failwith `tree_INDUCT`);;
% --------------------------------------------------------------------- %
% %
% tree_INDUCT_TAC %
% %
% [A] !t.P[t] %
% ================================ %
% [A,ALL_EL \t.P[t] trl] |- P[node trl] %
% %
% --------------------------------------------------------------------- %
let tree_INDUCT_TAC (A,term) =
(let t,body = dest_forall term in
let t' = variant ((frees term) @ (freesl A)) t in
let body' = subst [t',t] body in
let trl = variant ((frees body') @ (freesl A)) "trl:(tree)list" in
let asm = "ALL_EL (\^t'.^body') trl" in
([ (asm.A, subst["node ^trl",t']body')],
\[thm]. tree_INDUCT (GEN trl (DISCH asm thm)))
) ? failwith `tree_INDUCT_TAC`;;
% --------------------------------------------------------------------- %
% Definition of a height function on trees... %
% %
% --------------------------------------------------------------------- %
% First, define a relation "bht n tr" which is true if tr has height %
% bounded by n. I.e. bht n tr = height of tr <= n. %
let bht =
new_definition
(`bht`,
"bht = PRIM_REC
(\tr. tr = node NIL)
(\res n. \tr. ?trl. (tr = node trl) /\ ALL_EL res trl)");;
% show that bht has the following recursive definition: %
let bht_thm =
TAC_PROOF(
([], "(bht 0 tr = (tr = node NIL)) /\
(bht (SUC n) tr = ?trl. (tr = node trl) /\ ALL_EL (bht n) trl)"),
PURE_REWRITE_TAC [bht;PRIM_REC_THM] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
STRIP_TAC THEN REFL_TAC);;
% Show that if height t <= n then height t <= (SUC n) %
let bht_lemma1 =
TAC_PROOF(([], "!n. !tr:tree. bht n tr ==> bht (SUC n) tr"),
INDUCT_TAC THENL
[REWRITE_TAC [bht_thm] THEN
REPEAT STRIP_TAC THEN
EXISTS_TAC "NIL:(tree)list" THEN
ASM_REWRITE_TAC [ALL_EL];
ONCE_REWRITE_TAC [bht_thm] THEN
REPEAT STRIP_TAC THEN
EXISTS_TAC "trl:(tree)list" THEN
ASM_REWRITE_TAC [] THEN
MAP_EVERY POP_ASSUM [MP_TAC;K ALL_TAC] THEN
SPEC_TAC ("trl:(tree)list","trl:(tree)list") THEN
LIST_INDUCT_TAC THEN
REWRITE_TAC [ALL_EL] THEN
REPEAT STRIP_TAC THEN RES_TAC]);;
% show that if height tr <= n then height tr <= n+m %
let bht_lemma2 =
(GEN_ALL o DISCH_ALL o GEN "m:num" o UNDISCH o SPEC_ALL)
(TAC_PROOF(([], "!m n. !tr:tree. bht n tr ==> bht (n+m) tr"),
INDUCT_TAC THEN
REWRITE_TAC [ADD_CLAUSES] THEN
REPEAT STRIP_TAC THEN
RES_TAC THEN IMP_RES_TAC bht_lemma1));;
% show that height bounds for all the trees in a list implies a single %
% bound for all the trees in the list. %
let bht_lemma3 =
TAC_PROOF(
([],"!trl.ALL_EL (\tr:tree.?n.bht n tr) trl ==> ?n. ALL_EL (bht n) trl"),
LIST_INDUCT_TAC THEN
REWRITE_TAC [ALL_EL] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THEN RES_TAC THEN
POP_ASSUM STRIP_ASSUME_TAC THEN
EXISTS_TAC "n+n'" THEN
STRIP_TAC THENL
[IMP_RES_TAC bht_lemma2 THEN FIRST_ASSUM MATCH_ACCEPT_TAC;
POP_ASSUM MP_TAC THEN REPEAT (POP_ASSUM (K ALL_TAC)) THEN
ONCE_REWRITE_TAC [ADD_SYM] THEN
SPEC_TAC ("trl:(tree)list","trl:(tree)list") THEN
LIST_INDUCT_TAC THEN
REWRITE_TAC [ALL_EL] THEN
REPEAT STRIP_TAC THEN RES_TAC THEN
IMP_RES_TAC bht_lemma2 THEN
POP_ASSUM MATCH_ACCEPT_TAC]);;
% show that there always exists an n such that height tr <= n. %
let exists_bht =
TAC_PROOF(([], "!tr:tree. ?n. bht n tr"),
tree_INDUCT_TAC THEN
POP_ASSUM (STRIP_ASSUME_TAC o MATCH_MP bht_lemma3) THEN
EXISTS_TAC "SUC n" THEN
REWRITE_TAC [bht_thm] THEN
EXISTS_TAC "trl:(tree)list" THEN
ASM_REWRITE_TAC[]);;
% Show that there is always a minimum bound on the height of a tree. %
let min_bht =
CONV_RULE (DEPTH_CONV BETA_CONV)
(TAC_PROOF(
([], "!t:tree.?n.(\n. bht n t)n /\ (!m. m < n ==> ~((\n. bht n t)m))"),
GEN_TAC THEN
MATCH_MP_TAC WOP THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
MATCH_ACCEPT_TAC exists_bht));;
% We can now define our hieght function as follows: %
let HT =
new_definition
(`HT`,
"HT (t:tree) = @n. bht n t /\ (!m. m < n ==> ~bht m t)");;
% A number of theorems about HT follow: %
% The main thing is to show that: %
% 1) !tl. ALL_EL (\t. HT t < HT(node tl)) tl %
% 2) !trl. (HT (node trl) = 0) = (trl = NIL) %
let HT_thm1 =
TAC_PROOF(([], "!tr:tree. bht (HT tr) tr"),
REWRITE_TAC [HT] THEN
GEN_TAC THEN
STRIP_ASSUME_TAC (SELECT_RULE (SPEC "tr:tree" min_bht)));;
let HT_thm2 =
TAC_PROOF(([], "!tr:tree.!m. m < (HT tr) ==> ~bht m tr"),
REWRITE_TAC [HT] THEN
GEN_TAC THEN
STRIP_ASSUME_TAC (SELECT_RULE (SPEC "tr:tree" min_bht)));;
% A Key result about HT. %
let HT_leaf =
TAC_PROOF(([], "!trl. (HT (node trl) = 0) = (trl = NIL)"),
REPEAT STRIP_TAC THEN EQ_TAC THENL
[DISCH_TAC THEN MP_TAC (SPEC "node trl" HT_thm1) THEN
POP_ASSUM SUBST1_TAC THEN
REWRITE_TAC [bht_thm;node_11] THEN
STRIP_TAC;
DISCH_THEN SUBST1_TAC THEN
STRIP_ASSUME_TAC (SPEC "HT(node NIL)" num_CASES) THEN
MP_TAC (SPEC "node NIL" HT_thm2) THEN
POP_ASSUM SUBST1_TAC THEN
REWRITE_TAC [NOT_SUC] THEN
CONV_TAC NOT_FORALL_CONV THEN
REWRITE_TAC [taut1] THEN
EXISTS_TAC "0" THEN
REWRITE_TAC [bht_thm;LESS_0]]);;
let HT_thm3 =
TAC_PROOF(([], "!m. !tr:tree. (~bht m tr) ==> m < (HT tr)"),
CONV_TAC (ONCE_DEPTH_CONV CONTRAPOS_CONV) THEN
REWRITE_TAC [NOT_LESS;LESS_OR_EQ] THEN
REPEAT STRIP_TAC THENL
[POP_ASSUM
((STRIP_THM_THEN SUBST1_TAC) o MATCH_MP LESS_ADD_1) THEN
STRIP_ASSUME_TAC (SPEC "tr:tree" HT_thm1) THEN
IMP_RES_TAC bht_lemma2 THEN POP_ASSUM MATCH_ACCEPT_TAC;
POP_ASSUM (SUBST1_TAC o SYM) THEN
MATCH_ACCEPT_TAC HT_thm1]);;
let HT_thm4 =
TAC_PROOF(([], "!tr:tree. !m. m < (HT tr) = ~bht m tr"),
REPEAT STRIP_TAC THEN EQ_TAC THENL
(map MATCH_ACCEPT_TAC [HT_thm2;HT_thm3]));;
% TFM: fixed error "tl" for "trl" after quantifier. 88.11.17 %
let HT_thm5 =
TAC_PROOF(
([], "!n tl h. ~bht n (node tl) ==> ~bht n (node (CONS h tl))"),
CONV_TAC (ONCE_DEPTH_CONV CONTRAPOS_CONV) THEN
GEN_TAC THEN STRIP_ASSUME_TAC (SPEC "n:num" num_CASES) THEN
ASM_REWRITE_TAC [bht_thm] THEN
POP_ASSUM (K ALL_TAC) THENL
[REWRITE_TAC [node_11] THEN
REPEAT STRIP_TAC THEN
POP_ASSUM (MP_TAC o (AP_TERM "NULL:(tree)list->bool")) THEN
REWRITE_TAC [NULL];
REWRITE_TAC [node_11] THEN
REPEAT STRIP_TAC THEN
MAP_EVERY POP_ASSUM [MP_TAC;SUBST1_TAC o SYM] THEN
REWRITE_TAC [ALL_EL] THEN STRIP_TAC THEN
EXISTS_TAC "tl:tree list" THEN
ASM_REWRITE_TAC []]);;
let HT_thm6 =
TAC_PROOF(
([], "!trl tl. !t:tree.
ALL_EL (\t. ~bht (HT t) (node tl)) trl ==>
ALL_EL (\t. ~bht (HT t) (node (CONS h tl))) trl"),
LIST_INDUCT_TAC THEN
REWRITE_TAC [ALL_EL] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THENL
[IMP_RES_TAC HT_thm5;RES_TAC]);;
% A Key result about HT. %
let HT_node =
TAC_PROOF(([], "!tl. ALL_EL (\t. HT t < HT(node tl)) tl"),
REWRITE_TAC [HT_thm4] THEN
LIST_INDUCT_TAC THEN
REWRITE_TAC [ALL_EL] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REPEAT GEN_TAC THEN STRIP_TAC THENL
[STRIP_ASSUME_TAC (SPEC "HT (h:tree)" num_CASES) THENL
[ASM_REWRITE_TAC [bht_thm;node_11;CONS_11] THEN
DISCH_THEN (MP_TAC o AP_TERM "NULL:(tree)list->bool") THEN
REWRITE_TAC [NULL];
MP_TAC (SPEC "h:tree" HT_thm2) THEN
ASM_REWRITE_TAC [bht_thm;ALL_EL;node_11] THEN
DISCH_TAC THEN
CONV_TAC (REDEPTH_CONV NOT_EXISTS_CONV) THEN
ONCE_REWRITE_TAC [DE_MORGAN_THM] THEN
ONCE_REWRITE_TAC [SYM(SPEC_ALL IMP_DISJ_THM)] THEN
REPEAT GEN_TAC THEN
DISCH_THEN (SUBST1_TAC o SYM) THEN
REWRITE_TAC [ALL_EL;DE_MORGAN_THM] THEN
DISJ1_TAC THEN
FIRST_ASSUM MATCH_MP_TAC THEN
MATCH_ACCEPT_TAC LESS_SUC_REFL];
IMP_RES_THEN MATCH_ACCEPT_TAC HT_thm6]);;
% The following lemmas are used in the proof of approx_lemma below: %
let Less_lemma =
TAC_PROOF(([], "!n m. (n < SUC m) = (n <= m)"),
REWRITE_TAC [LESS_OR_EQ] THEN
CONV_TAC (ONCE_DEPTH_CONV (REWR_CONV DISJ_SYM)) THEN
MATCH_ACCEPT_TAC LESS_THM);;
let less_HT =
TAC_PROOF(([], "!trl m n.
(m <= n) ==>
ALL_EL (\t. HT t < m) trl ==>
ALL_EL (\t:tree. HT t <= n) trl"),
LIST_INDUCT_TAC THEN
REWRITE_TAC [ALL_EL] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THENL
[IMP_RES_TAC LESS_IMP_LESS_OR_EQ THEN
IMP_RES_TAC LESS_EQ_TRANS;
RES_TAC]);;
let less_HT2 =
TAC_PROOF(
([], "!trl n. HT(node trl) < n ==> ALL_EL (\t. HT t < n) trl"),
REPEAT GEN_TAC THEN
DISCH_THEN (STRIP_THM_THEN SUBST1_TAC o MATCH_MP LESS_ADD_1) THEN
MP_TAC (SPEC "trl:(tree)list" HT_node) THEN
SPEC_TAC ("HT(node trl)","n:num") THEN
REWRITE_TAC [ADD_CLAUSES;num_CONV "1"] THEN
SPEC_TAC ("trl:(tree)list","trl:(tree)list") THEN
LIST_INDUCT_TAC THEN
REWRITE_TAC [ALL_EL] THEN
CONV_TAC (REDEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THEN RES_TAC THEN
STRIP_ASSUME_TAC (REWRITE_RULE [LESS_OR_EQ]
(SPECL ["n:num";"p:num"] LESS_EQ_ADD)) THENL
[IMP_RES_TAC LESS_TRANS;
POP_ASSUM (SUBST1_TAC o SYM)] THEN
IMP_RES_TAC LESS_SUC);;
let less_HT3 =
TAC_PROOF(
([],"!trl.
(HT(node trl) <= HT(node (CONS (node trl) NIL)))"),
REPEAT STRIP_TAC THEN
MP_TAC (SPEC "CONS (node trl) NIL" HT_node) THEN
REWRITE_TAC [ALL_EL] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
STRIP_TAC THEN IMP_RES_TAC LESS_IMP_LESS_OR_EQ);;
% Following proof revised for version 1.12 resolution. [TFM 91.01.18] %
let less_HT4 =
TAC_PROOF
(([], "!trl m n. (m <= n) ==>
ALL_EL (\t. HT t < m) trl ==>
ALL_EL (\t:tree. HT t < n) trl"),
PURE_ONCE_REWRITE_TAC [LESS_OR_EQ] THEN
REPEAT GEN_TAC THEN
DISCH_THEN (STRIP_THM_THEN (\th g. SUBST1_TAC th g ? MP_TAC th g)) THENL
[MAP_EVERY (\t. SPEC_TAC(t,t)) ["n:num";"m:num";"trl:(tree)list"] THEN
LIST_INDUCT_TAC THEN REWRITE_TAC [ALL_EL] THEN
CONV_TAC (ONCE_DEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THENL [IMP_RES_TAC LESS_TRANS; RES_TAC];
DISCH_THEN ACCEPT_TAC]);;
let less_HT5 =
let spec = SPEC "CONS (h:tree) NIL" HT_node in
let rew = CONV_RULE (DEPTH_CONV BETA_CONV)
(REWRITE_RULE [ALL_EL] spec) in
GEN_ALL rew;;
let less_HT6 =
let spec = SPEC "CONS (h:tree) trl" HT_node in
let rew = CONV_RULE (DEPTH_CONV BETA_CONV)
(REWRITE_RULE [ALL_EL] spec) in
let less1 = CONJUNCT1(SPEC_ALL rew) in
let spec2 = SPEC "node (CONS h trl)" (GEN_ALL less_HT5) in
GEN_ALL(MATCH_MP LESS_TRANS (CONJ less1 spec2));;
let less_HT7 =
let less1 = (SPEC_ALL HT_node) in
let less2 = (SPEC_ALL less_HT3) in
(MATCH_MP (GEN_ALL(MATCH_MP less_HT4 less2)) less1);;
let less_HT8 =
let sp = REWRITE_RULE [ALL_EL]
(SPEC "CONS (h:tree) trl" (GEN_ALL less_HT7)) in
(CONJUNCT2 sp);;
% Show that dest is the destructor for node. %
let dest_node_thm =
TAC_PROOF(([], "!tl. dest_node (node tl) = tl"),
REWRITE_TAC [dest_node;node_11] THEN
REPEAT STRIP_TAC THEN
CONV_TAC SYM_CONV THEN
CONV_TAC SELECT_CONV THEN
EXISTS_TAC "tl:(tree)list" THEN REFL_TAC);;
% we now show that for all n there is a recursive function that works %
% as desired for trees of height <= n. %
let approx_lemma =
TAC_PROOF
(([], "!f. !n. ?fn. !trl.
(HT(node trl) <= n) ==>
(fn (node trl) = f (MAP fn trl):**)"),
GEN_TAC THEN INDUCT_TAC THENL
[REWRITE_TAC [NOT_LESS_0;LESS_OR_EQ;HT_leaf] THEN
EXISTS_TAC "\t:tree. f (NIL:(**)list):**" THEN
REPEAT (STRIP_GOAL_THEN SUBST1_TAC) THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REWRITE_TAC [MAP];
POP_ASSUM STRIP_ASSUME_TAC THEN
REWRITE_TAC [LESS_OR_EQ] THEN REWRITE_TAC [Less_lemma] THEN
EXISTS_TAC
"\t:tree. ((HT t) <= n) => (fn t:**) | f(MAP fn (dest_node t))" THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REWRITE_TAC [dest_node_thm] THEN
REPEAT STRIP_TAC THENL
[RES_TAC THEN ASM_REWRITE_TAC [] THEN
ASSUME_TAC (SPEC "trl:(tree)list" HT_node) THEN
IMP_RES_TAC less_HT THEN
POP_ASSUM MP_TAC THEN POP_ASSUM_LIST (K ALL_TAC) THEN
DISCH_THEN (\th. AP_TERM_TAC THEN MP_TAC th) THEN
SPEC_TAC ("trl:(tree)list","trl:(tree)list") THEN
LIST_INDUCT_TAC THEN
REWRITE_TAC [ALL_EL;MAP] THEN
CONV_TAC (REDEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THEN RES_TAC THEN ASM_REWRITE_TAC[];
MP_TAC (SPEC "trl:(tree)list" HT_node) THEN
ASM_REWRITE_TAC [Less_lemma;SYM(SPEC_ALL LESS_EQ);LESS_REFL] THEN
POP_ASSUM_LIST (K ALL_TAC) THEN
DISCH_THEN (\th. AP_TERM_TAC THEN MP_TAC th) THEN
SPEC_TAC ("trl:(tree)list","trl:(tree)list") THEN
LIST_INDUCT_TAC THEN
REWRITE_TAC [ALL_EL;MAP] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THEN RES_TAC THEN ASM_REWRITE_TAC[]]]);;
% Now, define tree_rec_fun n f to be the function that works for trees %
% shorter than n. %
let trf =
new_definition
(`trf`,
"trf n f = @fn. !trl.
(HT(node trl)) <= n ==>
(fn(node trl):** = f(MAP fn trl))");;
% Prove that trf has the appropriate property. %
let trf_thm =
TAC_PROOF(([], "!f n trl.
(HT (node trl)) <= n ==>
(trf n f (node trl):** = f(MAP (trf n f) trl))"),
REWRITE_TAC [trf] THEN
CONV_TAC (DEPTH_CONV SELECT_CONV) THEN
MATCH_ACCEPT_TAC approx_lemma);;
% show that trf n f = trf m f for trees shorter than n amd m. %
let trf_EQ_thm =
TAC_PROOF(([], "!t:tree. !n m f. HT(t) < n /\ HT(t) < m ==>
(trf n f t:** = trf m f t)"),
tree_INDUCT_TAC THEN
REPEAT STRIP_TAC THEN
IMP_RES_TAC LESS_IMP_LESS_OR_EQ THEN
IMP_RES_THEN (SUBST1_TAC o SPEC_ALL) trf_thm THEN
AP_TERM_TAC THEN
MAP_EVERY POP_ASSUM [K ALL_TAC;K ALL_TAC] THEN
REPEAT (POP_ASSUM (MP_TAC o MATCH_MP less_HT2)) THEN
POP_ASSUM MP_TAC THEN
SPEC_TAC ("trl:(tree)list","trl:(tree)list") THEN
LIST_INDUCT_TAC THEN REWRITE_TAC [MAP;ALL_EL] THEN
CONV_TAC (REDEPTH_CONV BETA_CONV) THEN
GEN_TAC THEN CONV_TAC ANTE_CONJ_CONV THEN
DISCH_THEN
(\th. ASSUME_TAC th THEN REPEAT STRIP_TAC THEN
MP_TAC (SPECL ["n:num";"m:num";"f:(**)list->**"] th)) THEN
RES_TAC THEN POP_ASSUM SUBST1_TAC THEN
REWRITE_TAC [CONS_11] THEN
STRIP_TAC THEN RES_TAC THEN FIRST_ASSUM ACCEPT_TAC);;
% extend the above result for lists of trees. %
let trf_EQ_thm2 =
TAC_PROOF(
([], "!trl:(tree)list.
!n m f. (ALL_EL (\t. HT t < n) trl /\ ALL_EL (\t. HT t < m) trl) ==>
(MAP (trf n f) trl:(**)list = MAP(trf m f) trl)"),
LIST_INDUCT_TAC THEN
REWRITE_TAC [MAP;ALL_EL] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THEN
IMP_RES_THEN (ASSUME_TAC o SPEC_ALL) trf_EQ_thm THEN RES_TAC THEN
REWRITE_TAC [CONS_11] THEN CONJ_TAC THEN FIRST_ASSUM MATCH_ACCEPT_TAC);;
% Now, by taking "\t. trf (HT (node [t])) f t" we have a function that %
% works for all trees t. %
let FN_EXISTS =
TAC_PROOF(
([], "!f. ?fn. !trl. (fn (node trl):** = f (MAP fn trl))"),
STRIP_TAC THEN
EXISTS_TAC
"\t. trf (HT(node (CONS t NIL))) (f:(**)list->**) t" THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THEN
ASSUME_TAC (SPEC "trl:(tree)list" less_HT3) THEN
IMP_RES_THEN (SUBST1_TAC o SPEC_ALL) trf_thm THEN
POP_ASSUM (K ALL_TAC) THEN
AP_TERM_TAC THEN
SPEC_TAC ("trl:(tree)list","trl:(tree)list") THEN
LIST_INDUCT_TAC THEN
REWRITE_TAC [ALL_EL;MAP] THEN
REPEAT STRIP_TAC THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REWRITE_TAC [CONS_11] THEN STRIP_TAC THENL
[MATCH_MP_TAC trf_EQ_thm THEN STRIP_TAC THENL
[MATCH_ACCEPT_TAC less_HT6;
MATCH_ACCEPT_TAC less_HT5];
FIRST_ASSUM (SUBST1_TAC o SYM) THEN
MATCH_MP_TAC trf_EQ_thm2 THEN
STRIP_TAC THENL
[ACCEPT_TAC less_HT8;
MATCH_ACCEPT_TAC (GEN_ALL less_HT7)]]);;
% Now show that there is a function that produces the desired tree %
% recursive function, given f. %
let FN_thm =
TAC_PROOF
(([], "?FN. !f. !trl. ((FN f) (node trl) = f (MAP (FN f) trl):**)"),
EXISTS_TAC "\f. @fn. !trl. (fn(node trl):** = f(MAP fn trl))" THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
CONV_TAC (DEPTH_CONV SELECT_CONV) THEN
MATCH_ACCEPT_TAC FN_EXISTS);;
% Prove the existence of a certain function AP. %
let AP =
prove_rec_fn_exists list_Axiom
"(!l. AP NIL l = NIL) /\
(!h t l. AP (CONS h t) l = CONS (h (HD l:*):**) (AP t (TL l)))";;
% Got to have the types just right for use of AP below. %
let AP = INST_TYPE [":tree",":*"] AP;;
let AP_DEF = conjuncts(snd(dest_exists(concl AP)));;
% A lemma about AP and MAP. %
let AP_MAP =
TAC_PROOF((AP_DEF,
"!l. AP (MAP (f:tree->tree->**) l) l = MAP (\x. f x x) l"),
LIST_INDUCT_TAC THEN
ASM_REWRITE_TAC [MAP;HD;TL] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
STRIP_TAC THEN REFL_TAC);;
% Now, prove the existence of the recursively defined functions. %
let EXISTS_THM =
TAC_PROOF(
([], "!f. ?fn. !tl. fn (node tl):** = f (MAP fn tl) tl"),
STRIP_TAC THEN
STRIP_ASSUME_TAC (INST_TYPE [":tree->**",":**"] FN_thm) THEN
STRIP_ASSUME_TAC AP THEN
let fn =
"\n:tree. ((FN (\fnl:(tree->**)list.\n:tree.
f (AP fnl (dest_node n):(**)list)
(dest_node n):**)) (n:tree) (n:tree):**)" in
EXISTS_TAC fn THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
ASM_REWRITE_TAC [] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REWRITE_TAC [dest_node_thm;AP_MAP]);;
% A little lemma... %
let lemma =
TAC_PROOF(([],"!l. ALL_EL (\x:*. f x:** = g x) l ==> (MAP f l = MAP g l)"),
LIST_INDUCT_TAC THEN
REWRITE_TAC [MAP;ALL_EL] THEN
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THEN RES_TAC THEN
ASM_REWRITE_TAC[]);;
% Finally, prove the theorem for trees! %
let tree_Axiom =
prove_thm
(`tree_Axiom`,
"!f. ?!fn. !tl. fn (node tl):** = f (MAP fn tl) tl",
GEN_TAC THEN
CONV_TAC EXISTS_UNIQUE_CONV THEN
STRIP_TAC THENL
[MATCH_ACCEPT_TAC EXISTS_THM;
CONV_TAC (DEPTH_CONV BETA_CONV) THEN
REPEAT STRIP_TAC THEN CONV_TAC FUN_EQ_CONV THEN
tree_INDUCT_TAC THEN
IMP_RES_TAC lemma THEN
ASM_REWRITE_TAC []]);;
% Close the theory. %
close_theory();;
quit();;
|