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/*=========================================================================
*
* Copyright Insight Software Consortium
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0.txt
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*
*=========================================================================*/
/*
This file tests the syntax that the compiler supports for declaring
templated functions as friends of a templated class.
*/
//
// Here is our templated function, forward declared
//
template <class T> class WantToHaveFriend;
template <class T>
bool operator==( const WantToHaveFriend<T> & a, const WantToHaveFriend<T> & b );
//
// Here is our templated class
//
template <class T>
class WantToHaveFriend
{
public:
typedef WantToHaveFriend Self;
WantToHaveFriend()
{
x = 0;
}
void DoNothing() const
{
// of course... do nothing.
}
//
// Here are the variants that some compilers use
//
#ifdef TRY_COMPILE_FRIEND_WITH_NULL_TEMPLATE_STRING
friend bool operator==(const Self &, const Self &);
#endif
#ifdef TRY_COMPILE_FRIEND_WITH_EMPTY_TEMPLATE_BRACKETS
friend bool operator==<>(const Self &, const Self &);
#endif
#ifdef TRY_COMPILE_FRIEND_WITH_TEMPLATE_ARGUMENTS
friend bool operator==<Self>(const Self &, const Self &);
#endif
private:
int x;
};
template <class T>
bool operator==( const WantToHaveFriend<T> & a, const WantToHaveFriend<T> & b )
{ return a.x == b.x; }
int main()
{
typedef WantToHaveFriend<int> FriendlyType;
FriendlyType foo1;
FriendlyType foo2;
bool result = ( foo1 == foo2 );
if( result )
{
return 1;
}
return 0;
}
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