1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
|
/*
* methods/iterate.c
*
* Calculate the sum of a given range of integer numbers.
*
* This particular method of implementation works by way of brute force,
* i.e. it iterates over the entire range while adding the numbers to finally
* get the total sum. As a positive side effect, we're able to easily detect
* overflows, i.e. situations in which the sum would exceed the capacity
* of an integer variable.
*
*/
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
#include "iterate.h"
void test_data_logging(int, int);
int iterate_get_sum (int min, int max)
{
int i, total;
test_data_logging(min, max);
total = 0;
/* This is where we loop over each number in the range, including
both the minimum and the maximum number. */
for (i = min; i <= max; i++)
{
/* We can detect an overflow by checking whether the new
sum would exceed the maximum integer value. */
if (total > INT_MAX - i)
{
printf ("Error: sum too large!\n");
exit (1);
}
/* Everything seems to fit into an int, so continue adding. */
total += i;
}
return total;
}
void
test_data_logging(int min, int max)
{
(void)min; /* quiet compiler complaints */
(void)max;
printf("this is some debug data logging code that gets removed in the final product\n");
}
|
