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/*
Adept MobileRobots Robotics Interface for Applications (ARIA)
Copyright (C) 2004, 2005 ActivMedia Robotics LLC
Copyright (C) 2006, 2007, 2008, 2009, 2010 MobileRobots Inc.
Copyright (C) 2011, 2012, 2013 Adept Technology
This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 2 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program; if not, write to the Free Software
Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
If you wish to redistribute ARIA under different terms, contact
Adept MobileRobots for information about a commercial version of ARIA at
robots@mobilerobots.com or
Adept MobileRobots, 10 Columbia Drive, Amherst, NH 03031; +1-603-881-7960
*/
#include "Aria.h"
ArPose fn1(void)
{
static ArPose pose;
pose.setX(pose.getX() + 1);
pose.setY(pose.getY() + 1);
pose.setTh(pose.getTh() - 1);
return pose;
}
void fn2(ArPose pose)
{
pose.log();
}
int main(void)
{
printf("Entering 100 iterations of incrementing pose X and Y and decrementing Theta...");
for (int i = 0; i < 100; i++)
fn2(fn1());
printf("\nTesting ArPose::operator+(const ArPose&) and ArPose::operator-(const ArPose&)...\n");
ArPose p1(10, 10, 90);
ArPose p2(10, 10, 45);
ArPose p3(0, 0, 0);
ArPose p4(-20, 0, 360);
ArPose p5(-20, -20, -180);
printf("(10,10,90) + (10,10,90) => ");
(p1 + p1).log();
printf("(10,10,90) - (10,10,90) => ");
(p1 - p1).log();
printf("(10,10,90) + (10,10,45) => ");
(p1 + p2).log();
printf("(10,10,90) + (0,0,0) => ");
(p1 + p3).log();
printf("(10,10,90) - (0,0,0) => ");
(p1 - p3).log();
printf("(0,0,0) + (-20,0,360) => ");
(p3 + p4).log();
printf("(0,0,0) - (-20,0,360) => ");
(p3 - p4).log();
printf("(10,10,90) + (-20,0,360) => ");
(p1 + p4).log();
printf("(-20,0,360) + (-20,0,360) => ");
(p4 + p4).log();
printf("(-20,-20,-180) - (10,10,45) => ");
(p5 - p2).log();
}
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