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<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8" />
<style>
body { font-family: Helvetica, Arial, sans-serif; line-height: 1.3em; -webkit-font-smoothing: antialiased; }
.container {
width: 90%;
margin: 20px auto;
background-color: #FFF;
padding: 20px;
}
pre, code {
font-family: Monaco, Menlo, Consolas, "Courier New", monospace;
font-size: 12px;
color: #333;
-webkit-border-radius: 3px;
-moz-border-radius: 3px;
border-radius: 3px;
}
pre { border: 1px solid #CCC; background-color: #EEE; color: #333; padding: 10px; overflow: scroll; }
code { padding: 2px 4px; background-color: #F7F7F9; border: 1px solid #E1E1E8; color: #D14; }
</style>
</head>
<body>
<div class="container">
<h1>Click Demo</h1>
<p>This demonstrates a commonly-asked question: how do I replace Backstretch's image once it's been called? The simple answer is, you can just call Backstretch again, and the image will be replaced.</p>
<p><em>Note: Any options that you previously passed in will be preserved.</em></p>
<p>
<input type="button" id="pot-holder" value="Show Pot Holder Background" />
<input type="button" id="coffee" value="Show Coffee Background" />
</p>
<pre><script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script src="jquery.backstretch.min.js"></script>
<script>
$.backstretch("pot-holder.jpg", {speed: 500});
$("#pot-holder").click(function (e) {
e.preventDefault();
$.backstretch("pot-holder.jpg");
});
$("#coffee").click(function (e) {
e.preventDefault();
$.backstretch("coffee.jpg");
});
</script></pre>
</div>
<script src="../libs/jquery/jquery.js"></script>
<script src="../src/jquery.backstretch.js"></script>
<script>
$.backstretch("pot-holder.jpg", {fade: 500});
$("#pot-holder").click(function (e) {
e.preventDefault();
$.backstretch("pot-holder.jpg");
});
$("#coffee").click(function (e) {
e.preventDefault();
$.backstretch("coffee.jpg");
});
</script>
</body>
</html>
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