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//===-- GlobPattern.cpp - Glob pattern matcher implementation -------------===//
//
// Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions.
// See https://llvm.org/LICENSE.txt for license information.
// SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception
//
//===----------------------------------------------------------------------===//
//
// This file implements a glob pattern matcher.
//
//===----------------------------------------------------------------------===//
#include "llvm/Support/GlobPattern.h"
#include "llvm/ADT/ArrayRef.h"
#include "llvm/ADT/Optional.h"
#include "llvm/ADT/StringRef.h"
#include "llvm/Support/Errc.h"
using namespace llvm;
static bool hasWildcard(StringRef S) {
return S.find_first_of("?*[\\") != StringRef::npos;
}
// Expands character ranges and returns a bitmap.
// For example, "a-cf-hz" is expanded to "abcfghz".
static Expected<BitVector> expand(StringRef S, StringRef Original) {
BitVector BV(256, false);
// Expand X-Y.
for (;;) {
if (S.size() < 3)
break;
uint8_t Start = S[0];
uint8_t End = S[2];
// If it doesn't start with something like X-Y,
// consume the first character and proceed.
if (S[1] != '-') {
BV[Start] = true;
S = S.substr(1);
continue;
}
// It must be in the form of X-Y.
// Validate it and then interpret the range.
if (Start > End)
return make_error<StringError>("invalid glob pattern: " + Original,
errc::invalid_argument);
for (int C = Start; C <= End; ++C)
BV[(uint8_t)C] = true;
S = S.substr(3);
}
for (char C : S)
BV[(uint8_t)C] = true;
return BV;
}
// This is a scanner for the glob pattern.
// A glob pattern token is one of "*", "?", "\", "[<chars>]", "[^<chars>]"
// (which is a negative form of "[<chars>]"), "[!<chars>]" (which is
// equivalent to "[^<chars>]"), or a non-meta character.
// This function returns the first token in S.
static Expected<BitVector> scan(StringRef &S, StringRef Original) {
switch (S[0]) {
case '*':
S = S.substr(1);
// '*' is represented by an empty bitvector.
// All other bitvectors are 256-bit long.
return BitVector();
case '?':
S = S.substr(1);
return BitVector(256, true);
case '[': {
// ']' is allowed as the first character of a character class. '[]' is
// invalid. So, just skip the first character.
size_t End = S.find(']', 2);
if (End == StringRef::npos)
return make_error<StringError>("invalid glob pattern: " + Original,
errc::invalid_argument);
StringRef Chars = S.substr(1, End - 1);
S = S.substr(End + 1);
if (Chars.startswith("^") || Chars.startswith("!")) {
Expected<BitVector> BV = expand(Chars.substr(1), Original);
if (!BV)
return BV.takeError();
return BV->flip();
}
return expand(Chars, Original);
}
case '\\':
// Eat this character and fall through below to treat it like a non-meta
// character.
S = S.substr(1);
LLVM_FALLTHROUGH;
default:
BitVector BV(256, false);
BV[(uint8_t)S[0]] = true;
S = S.substr(1);
return BV;
}
}
Expected<GlobPattern> GlobPattern::create(StringRef S) {
GlobPattern Pat;
// S doesn't contain any metacharacter,
// so the regular string comparison should work.
if (!hasWildcard(S)) {
Pat.Exact = S;
return Pat;
}
// S is something like "foo*", and the "* is not escaped. We can use
// startswith().
if (S.endswith("*") && !S.endswith("\\*") && !hasWildcard(S.drop_back())) {
Pat.Prefix = S.drop_back();
return Pat;
}
// S is something like "*foo". We can use endswith().
if (S.startswith("*") && !hasWildcard(S.drop_front())) {
Pat.Suffix = S.drop_front();
return Pat;
}
// Otherwise, we need to do real glob pattern matching.
// Parse the pattern now.
StringRef Original = S;
while (!S.empty()) {
Expected<BitVector> BV = scan(S, Original);
if (!BV)
return BV.takeError();
Pat.Tokens.push_back(*BV);
}
return Pat;
}
bool GlobPattern::match(StringRef S) const {
if (Exact)
return S == *Exact;
if (Prefix)
return S.startswith(*Prefix);
if (Suffix)
return S.endswith(*Suffix);
return matchOne(Tokens, S);
}
// Runs glob pattern Pats against string S.
bool GlobPattern::matchOne(ArrayRef<BitVector> Pats, StringRef S) const {
for (;;) {
if (Pats.empty())
return S.empty();
// If Pats[0] is '*', try to match Pats[1..] against all possible
// tail strings of S to see at least one pattern succeeds.
if (Pats[0].size() == 0) {
Pats = Pats.slice(1);
if (Pats.empty())
// Fast path. If a pattern is '*', it matches anything.
return true;
for (size_t I = 0, E = S.size(); I < E; ++I)
if (matchOne(Pats, S.substr(I)))
return true;
return false;
}
// If Pats[0] is not '*', it must consume one character.
if (S.empty() || !Pats[0][(uint8_t)S[0]])
return false;
Pats = Pats.slice(1);
S = S.substr(1);
}
}
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