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//===----------------------------------------------------------------------===//
//
// The LLVM Compiler Infrastructure
//
// This file is dual licensed under the MIT and the University of Illinois Open
// Source Licenses. See LICENSE.TXT for details.
//
//===----------------------------------------------------------------------===//
// <tuple>
// template <class... Types> class tuple;
// template <class... UTypes>
// tuple& operator=(tuple<UTypes...>&& u);
// UNSUPPORTED: c++98, c++03
#include <tuple>
#include <string>
#include <memory>
#include <utility>
#include <cassert>
struct B
{
int id_;
explicit B(int i= 0) : id_(i) {}
virtual ~B() {}
};
struct D
: B
{
explicit D(int i) : B(i) {}
};
struct E {
E() = default;
E& operator=(int) {
return *this;
}
};
int main()
{
{
typedef std::tuple<long> T0;
typedef std::tuple<long long> T1;
T0 t0(2);
T1 t1;
t1 = std::move(t0);
assert(std::get<0>(t1) == 2);
}
{
typedef std::tuple<long, char> T0;
typedef std::tuple<long long, int> T1;
T0 t0(2, 'a');
T1 t1;
t1 = std::move(t0);
assert(std::get<0>(t1) == 2);
assert(std::get<1>(t1) == int('a'));
}
{
typedef std::tuple<long, char, D> T0;
typedef std::tuple<long long, int, B> T1;
T0 t0(2, 'a', D(3));
T1 t1;
t1 = std::move(t0);
assert(std::get<0>(t1) == 2);
assert(std::get<1>(t1) == int('a'));
assert(std::get<2>(t1).id_ == 3);
}
{
D d(3);
D d2(2);
typedef std::tuple<long, char, D&> T0;
typedef std::tuple<long long, int, B&> T1;
T0 t0(2, 'a', d2);
T1 t1(1, 'b', d);
t1 = std::move(t0);
assert(std::get<0>(t1) == 2);
assert(std::get<1>(t1) == int('a'));
assert(std::get<2>(t1).id_ == 2);
}
{
typedef std::tuple<long, char, std::unique_ptr<D>> T0;
typedef std::tuple<long long, int, std::unique_ptr<B>> T1;
T0 t0(2, 'a', std::unique_ptr<D>(new D(3)));
T1 t1;
t1 = std::move(t0);
assert(std::get<0>(t1) == 2);
assert(std::get<1>(t1) == int('a'));
assert(std::get<2>(t1)->id_ == 3);
}
{
// Test that tuple evaluates correctly applies an lvalue reference
// before evaluating is_assignable (ie 'is_assignable<int&, int&&>')
// instead of evaluating 'is_assignable<int&&, int&&>' which is false.
int x = 42;
int y = 43;
std::tuple<int&&, E> t(std::move(x), E{});
std::tuple<int&&, int> t2(std::move(y), 44);
t = std::move(t2);
assert(std::get<0>(t) == 43);
assert(&std::get<0>(t) == &x);
}
}
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