1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87
|
-- author: Lily Silverstein
doc ///
Key
substring
(substring, String, ZZ)
(substring, ZZ, String)
(substring, ZZ, ZZ, String)
(substring, String, ZZ, ZZ)
(substring, Sequence, String)
Headline
extract part of a string
Usage
substring(i, s)
substring(i, n, s)
substring(s, i, n)
substring(s, i)
substring((i, n), s)
Inputs
i:ZZ
starting index of substring
n:ZZ
length of substring
s:String
Outputs
:String
Description
Text
The expressions {\tt substring(i, n, s)}, {\tt substring(s, i, n)}, and
{\tt substring((i, n), s)} all return the substring that starts at index
{\tt i} and has {\tt n} characters.
In other words, if $s=s_0s_1s_2\ldots s_k$, then
the substring returned is $s_i s_{i+1}\ldots s_{i+n-1}$.
Indices begin at zero, and a negative index is counted from
the end of the string. Requests for out-of-bound character positions
are silently ignored.
Example
s = "I love computing Gröbner bases in Macaulay2.";
substring(0, 5, s)
substring(s, -10, 5)
substring(s, 100, 5)
substring((3, 10), s)
Text
The expressions {\tt substring(i, s)} and {\tt substring(s, i)} return
the substring that starts at index {\tt i} and continues to the end of the string.
In other words, if $s=s_0s_1s_2\ldots s_k$, then
the substring returned is $s_i s_{i+1}\ldots s_k$.
Example
substring(3, s)
substring(s, -10)
SeeAlso
lines
separate
"strings and nets"
"regular expressions"
utf8substring
///
doc ///
Key
utf8substring
Headline
extract part of a utf8 string
Usage
utf8substring(s, i, n)
Inputs
s:String
i:ZZ
starting index of substring
n:ZZ
length of substring
Outputs
:String
Description
Text
Returns the substring of {\tt s} that starts at index
{\tt i} and has {\tt n} characters, both measured in utf8 characters.
Example
s = "π ≈ 3.14159";
utf8substring(s, 4, 4)
SeeAlso
substring
///
|