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"""
==============
Font Table TTF
==============
Matplotlib has support for FreeType fonts. Here's a little example
using the 'table' command to build a font table that shows the glyphs
by character code.
Usage python font_table_ttf.py somefile.ttf
"""
import sys
import os
import matplotlib
from matplotlib.ft2font import FT2Font
from matplotlib.font_manager import FontProperties
import matplotlib.pyplot as plt
# the font table grid
labelc = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9',
'A', 'B', 'C', 'D', 'E', 'F']
labelr = ['00', '10', '20', '30', '40', '50', '60', '70', '80', '90',
'A0', 'B0', 'C0', 'D0', 'E0', 'F0']
if len(sys.argv) > 1:
fontname = sys.argv[1]
else:
fontname = os.path.join(matplotlib.get_data_path(),
'fonts', 'ttf', 'DejaVuSans.ttf')
font = FT2Font(fontname)
codes = sorted(font.get_charmap().items())
# a 16,16 array of character strings
chars = [['' for c in range(16)] for r in range(16)]
colors = [[(0.95, 0.95, 0.95) for c in range(16)] for r in range(16)]
plt.figure(figsize=(8, 4), dpi=120)
for ccode, glyphind in codes:
if ccode >= 256:
continue
r, c = divmod(ccode, 16)
s = chr(ccode)
chars[r][c] = s
lightgrn = (0.5, 0.8, 0.5)
plt.title(fontname)
tab = plt.table(cellText=chars,
rowLabels=labelr,
colLabels=labelc,
rowColours=[lightgrn] * 16,
colColours=[lightgrn] * 16,
cellColours=colors,
cellLoc='center',
loc='upper left')
for key, cell in tab.get_celld().items():
row, col = key
if row > 0 and col > 0:
cell.set_text_props(fontproperties=FontProperties(fname=fontname))
plt.axis('off')
plt.show()
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