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/* driver for lmder1 example. */
#include <stdio.h>
#include <math.h>
#include <minpack.h>
void fcn(int *m, int *n, double *x, double *fvec, double *fjac,
int *ldfjac, int *iflag);
int main()
{
int j, m, n, ldfjac, info, lwa;
int ipvt[3];
double tol, fnorm;
double x[3], fvec[15], fjac[15*3], wa[30];
int one=1;
m = 15;
n = 3;
/* the following starting values provide a rough fit. */
x[1-1] = 1.;
x[2-1] = 1.;
x[3-1] = 1.;
ldfjac = 15;
lwa = 30;
/* set tol to the square root of the machine precision. */
/* unless high solutions are required, */
/* this is the recommended setting. */
tol = sqrt(dpmpar_(&one));
lmder1_(&fcn, &m, &n, x, fvec, fjac, &ldfjac, &tol,
&info, ipvt, wa, &lwa);
fnorm = enorm_(&m, fvec);
printf(" final l2 norm of the residuals%15.7g\n\n", fnorm);
printf(" exit parameter %10i\n\n", info);
printf(" final approximate solution\n");
for (j=1; j<=n; j++) printf("%s%15.7g", j%3==1?"\n ":"", x[j-1]);
printf("\n");
return 0;
}
void fcn(int *m, int *n, double *x, double *fvec, double *fjac,
int *ldfjac, int *iflag)
{
/* subroutine fcn for lmder1 example. */
int i;
double tmp1, tmp2, tmp3, tmp4;
double y[15] = {1.4e-1, 1.8e-1, 2.2e-1, 2.5e-1, 2.9e-1, 3.2e-1, 3.5e-1,
3.9e-1, 3.7e-1, 5.8e-1, 7.3e-1, 9.6e-1, 1.34, 2.1, 4.39};
if (*iflag != 2)
{
for (i = 1; i <= 15; i++)
{
tmp1 = i;
tmp2 = 16 - i;
tmp3 = tmp1;
if (i > 8) tmp3 = tmp2;
fvec[i-1] = y[i-1] - (x[1-1] + tmp1/(x[2-1]*tmp2 + x[3-1]*tmp3));
}
}
else
{
for ( i = 1; i <= 15; i++)
{
tmp1 = i;
tmp2 = 16 - i;
tmp3 = tmp1;
if (i > 8) tmp3 = tmp2;
tmp4 = (x[2-1]*tmp2 + x[3-1]*tmp3); tmp4 = tmp4*tmp4;
fjac[i-1 + *ldfjac*(1-1)] = -1.;
fjac[i-1 + *ldfjac*(2-1)] = tmp1*tmp2/tmp4;
fjac[i-1 + *ldfjac*(3-1)] = tmp1*tmp3/tmp4;
}
}
}
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