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/*
* Copyright (C) by Argonne National Laboratory
* See COPYRIGHT in top-level directory
*/
#include "mpi.h"
#include <stdio.h>
#include "mpitest.h"
#define BAD_ANSWER 100000
/*
The operation is inoutvec[i] = invec[i] op inoutvec[i]
(see 4.9.4). The order is important.
Note that the computation is in process rank (in the communicator)
order, independent of the root.
*/
static void assoc(int *invec, int *inoutvec, int *len, MPI_Datatype * dtype)
{
int i;
for (i = 0; i < *len; i++) {
if (inoutvec[i] <= invec[i]) {
int rank;
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
fprintf(stderr, "[%d] inout[0] = %d, in[0] = %d\n", rank, inoutvec[0], invec[0]);
inoutvec[i] = BAD_ANSWER;
} else
inoutvec[i] = invec[i];
}
}
int main(int argc, char **argv)
{
int rank, size;
int data;
int errors = 0;
int result = -100;
MPI_Op op;
MTest_Init(&argc, &argv);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &size);
data = rank;
MPI_Op_create((MPI_User_function *) assoc, 0, &op);
MPI_Reduce(&data, &result, 1, MPI_INT, op, size - 1, MPI_COMM_WORLD);
MPI_Bcast(&result, 1, MPI_INT, size - 1, MPI_COMM_WORLD);
MPI_Op_free(&op);
if (result == BAD_ANSWER)
errors++;
MTest_Finalize(errors);
return MTestReturnValue(errors);
}
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