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/*
Fortran text parsers
Copyright © 2013, 2018 F.Hroch (hroch@physics.muni.cz)
This file is part of Munipack.
Munipack is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
Munipack is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with Munipack. If not, see <http://www.gnu.org/licenses/>.
*/
#include "fortranio.h"
#include <string>
#include <vector>
#include <iostream>
#include <fstream>
#include <cstring>
#include <cassert>
using namespace std;
// string tokenizer recognizing Fortran strings
// * delimiters are by norm, only ' ,;\t' acceptable
// * double apostrophes are treated as the single character
// * strings starts and finish with a single apostrophe character
vector<string> strftok(const string& fstring, const string& delimiters)
{
const char *a = fstring.c_str();
const char *delim = delimiters.size() > 0 ? delimiters.c_str() : " ,;\t\n\0";
vector<string> tokens;
char *b = new char[strlen(a)+1];
bool open = false;
bool str = false;
bool fin = false;
char apho = ' ';
int l = 0;
int i = 0;
for(;;) {
if( strchr(delim,a[i]) != NULL ) {
if( str )
// the separator inside string appostrophes
b[l++] = a[i];
else {
if( open )
// non-string value finished
fin = true;
}
}
else {
if( ((a[i] == '\'' || a[i] == '"') && apho == ' ') ||
(apho != ' ' && a[i] == apho) ) {
apho = a[i];
// appostroph encountered, what's now?
if( ! str ) {
str = true;
open = true;
}
else {
// inside string
if( a[i+1] != '\0' && ( a[i+1] == '\'' || a[i+1] == '"') ) {
// if( a[i+1] != '\0' && apho != ' ' && a[i+1] == apho ) {
// inside string, double appostrophes are treated as a single char
i++;
b[l++] = a[i];
}
else if( a[i+1] != '\0' && strchr(delim,a[i+1]) != NULL ) {
// finishing string
str = false;
open = false;
fin = true;
}
else if( a[i+1] == '\0' ) {
// finishing string
str = false;
open = false;
fin = true;
}
}
}
else {
// non-empty, separator character
open = true;
b[l++] = a[i];
}
}
if( fin ) {
b[l++] = '\0';
// cerr << "number:" << b << endl;
tokens.push_back(b);
l = 0;
open = false;
str = false;
fin = false;
apho = ' ';
}
if( a[i] == '\0' ) break;
i++;
}
delete[] b;
return tokens;
}
string forstr(const string& a)
{
vector<string> s = strftok(a," \t\n\0");
if( s.size() == 1)
return s[0];
else
return "";
}
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