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block: # issue #22775
proc h(c: int) = discard
template k(v: int) =
template p() = v.h()
p()
let a = @[0]
k(0 and not a[0])
block: # issue #22775 case 2
proc h(c: int, q: int) = discard
template k(v: int) =
template p() = h(v, v)
p()
let a = [0]
k(0 and not a[0])
block: # issue #22775 minimal cases
proc h(c: int) = discard
template k(v: int) =
template p() = h(v)
p()
let a = [0]
k(not a[0])
block:
k(-a[0])
block:
proc f(x: int): int = x
k(f a[0])
block: # bracket assignment case of above tests
proc h(c: int) = discard
template k(v: int) =
template p() = h(v)
p()
var a = [0]
k(not (block:
a[0] = 1
1))
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