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#!/usr/bin/env bash
#
# @license Apache-2.0
#
# Copyright (c) 2017 The Stdlib Authors.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
# Prints the number of days an author has committed.
#
# <author_first_name> <author_last_name> <number_of_days> <percentage>
#
# Notes:
#
# - The percentage is computed based on the date of the first repository commit.
# * `git log`
# - Show logs.
# * `awk '{}'`
# - Compute statistics.
# * `sort -k3nr`
# - Sort in reverse numerical order based on the number of days active.
git log --format=format:"%ad %aN" --date=format:"%b %d %Y" --use-mailmap | awk '
BEGIN {
# Get the date of the first commit:
cmd = "git log --reverse --date=short | grep Date | head -n 1"
(cmd | getline tmp)
close(cmd)
split(tmp, date, OFS)
split(date[2], t1, "-")
# Get the date for "now":
cmd = "date '\''+%Y %m %d'\''"
(cmd | getline now)
close(cmd)
split(now, t2, OFS)
# Compute the number of days between the first commit and "now":
num = daynum(t1[1], t2[1], 0+t1[2], 0+t2[2], 0+t1[3], 0+t2[3])
}
{
day = $1 OFS $2 OFS $3
lines[day,$4,$5] = 1
}
END {
for (k in lines) {
split(k, keys, SUBSEP)
name = keys[2] OFS keys[3]
names[name] += 1
}
for (k in names) {
n = names[k]
pct = n/num
print k OFS n OFS pct
}
}
# Computes the number of days between a start date and an end date.
#
# Parameters:
# y1 - start year
# y2 - end year
# m1 - start month
# m2 - end month
# d1 - start day
# d2 - end day
#
# Returns:
# number of days
#
function daynum(y1, y2, m1, m2, d1, d2, days, i, n) {
split("31 28 31 30 31 30 31 31 30 31 30 31", days)
# 365 days in a year, plus one during a leap year:
if (y2 > y1) {
n = (y2-y1)*365 + int((y2-y1)/4)
}
# Adjust number of days in February if leap year...
if (y2 % 4 == 0) {
days[2] += 1
}
if ( m2 > m1 ) {
for (i = m1; i < m2; i++) {
n += days[i]
}
} else if ( m2 < m1 ) {
for (i = m1; i >= m2; i--) {
n -= days[i]
}
}
return n + d2 - d1
}
' | sort -k3nr
|
