1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
|
function df = struct2df(x, varargin)
%# function df = struct2df(x, varargin)
%# This function converts an ordinary structure into a dataframe.
%# Fieldnames are taken as columns names
%% Copyright (C) 2009-2017 Pascal Dupuis <cdemills@gmail.com>
%%
%% This file is part of the dataframe package for Octave.
%%
%% This package is free software; you can redistribute it and/or
%% modify it under the terms of the GNU General Public
%% License as published by the Free Software Foundation;
%% either version 2, or (at your option) any later version.
%%
%% This package is distributed in the hope that it will be useful,
%% but WITHOUT ANY WARRANTY; without even the implied
%% warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR
%% PURPOSE. See the GNU General Public License for more
%% details.
%%
%% You should have received a copy of the GNU General Public
%% License along with this package; see the file COPYING. If not,
%% see <http://www.gnu.org/licenses/>.
names = fieldnames (x);
if (isscalar (x))
rowcount = structfun (@(x) size(x, 1), x);
df = cell(1+max (rowcount), length (names));
df(1, :) = names;
for indi = (length (names) : -1 : 1)
if (isa (x.(names{indi}), 'cell'))
df(1+(1:rowcount(indi)), indi) = x.(names{indi});
else
dummy = mat2cell (x.(names{indi}), repmat (1, [rowcount(indi) 1], 1));
df(1+(1:rowcount(indi)), indi) = dummy;
endif
endfor
else
rowcount = size (x, 1);
df = cell (1 + rowcount, length (names));
df(1, :) = names;
for indi = (length (names) : -1 : 1)
for indj = (1:rowcount)
df(1+indj, indi) = x(indj).(names{indi});
endfor
endfor
endif
df = dataframe (df);
end
|
