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function resu = end(df, k, n)
%# function resu = end(df, k, n)
%# This is the end operator for a dataframe object, returning the
%# maximum number of rows or columns
%% Copyright (C) 2009-2017 Pascal Dupuis <cdemills@gmail.com>
%%
%% This file is part of the dataframe package for Octave.
%%
%% This package is free software; you can redistribute it and/or
%% modify it under the terms of the GNU General Public
%% License as published by the Free Software Foundation;
%% either version 3, or (at your option) any later version.
%%
%% This package is distributed in the hope that it will be useful,
%% but WITHOUT ANY WARRANTY; without even the implied
%% warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR
%% PURPOSE. See the GNU General Public License for more
%% details.
%%
%% You should have received a copy of the GNU General Public
%% License along with this package; see the file COPYING. If not,
%% see <http://www.gnu.org/licenses/>.
try
if k < 3,
resu = df.x_cnt(k);
else
resu = max(cellfun(@length, df.x_rep));
end
catch
error('incorrect call to end, index greater than number of dimensions');
end
end
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