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function resu = df_check_char_array(x, nelem, required)
%# auxiliary function: pad a char array to some width
%% Copyright (C) 2009-2017 Pascal Dupuis <cdemills@gmail.com>
%%
%% This file is part of the dataframe package for Octave.
%%
%% This package is free software; you can redistribute it and/or
%% modify it under the terms of the GNU General Public
%% License as published by the Free Software Foundation;
%% either version 2, or (at your option) any later version.
%%
%% This package is distributed in the hope that it will be useful,
%% but WITHOUT ANY WARRANTY; without even the implied
%% warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR
%% PURPOSE. See the GNU General Public License for more
%% details.
%%
%% You should have received a copy of the GNU General Public
%% License along with this package; see the file COPYING. If not,
%% see <http://www.gnu.org/licenses/>.
if (2 == nargin) required = [nelem 1]; end
if (nelem < required(1))
error ('Too many elements to assign');
end
%# a zero-length element is still considered as a space by char
if (isempty (x)) x = ' '; end
if (size (x, 1) < max (required(1), nelem))
%# pad vertically
dummy = repmat (' ', nelem-size (x, 1), 1);
resu = char (x, dummy);
else
resu = x;
end
if (size (resu, 2) < required(2))
%# pad horizontally
dummy = repmat (' ', nelem, required(2)-size (resu, 2));
resu = horzcat (resu, dummy);
end
end
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