1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109
|
#! /usr/bin/env python
from __future__ import print_function
from openturns import *
dim = 10
R = CorrelationMatrix(dim)
for i in range(dim):
for j in range(i):
R[i, j] = (i + j + 1.0) / (2.0 * dim)
mean = NumericalPoint(dim, 2.0)
sigma = NumericalPoint(dim, 3.0)
distribution = Normal(mean, sigma, R)
size = 100
sample = distribution.getSample(size)
sampleX = NumericalSample(size, dim - 1)
sampleY = NumericalSample(size, 1)
for i in range(size):
sampleY[i, 0] = sample[i, 0]
for j in range(1, dim):
sampleX[i, j - 1] = sample[i, j]
sampleZ = NumericalSample(size, 1)
for i in range(size):
sampleZ[i, 0] = sampleY[i, 0] * sampleY[i, 0]
selection = Indices(5)
selection.fill()
print('selection = ', selection)
# PartialPearson : Independence Pearson test between 2 samples : firstSample of dimension n and secondSample of dimension 1. If firstSample[i] is the numerical sample extracted from firstSample (ith coordinate of each point of the numerical sample), PartialPearson performs the Independence Pearson test simultaneously on firstSample[i] and secondSample, for i in the selection. For all i, it is supposed that the couple (firstSample[i] and secondSample) is issued from a gaussian vector.
# Probability of the H0 reject zone : 1-0.90
print('PartialPearsonXY=', HypothesisTest.PartialPearson(
sampleX, sampleY, selection, 0.90))
selection2 = Indices(1, 0)
sampleX0 = NumericalSample(size, 1)
for i in range(size):
sampleX0[i, 0] = sampleX[i, 0]
# The three tests must be equal
print('PartialPearsonX0Y=', HypothesisTest.PartialPearson(
sampleX, sampleY, selection2, 0.90))
print('PearsonX0Y=', HypothesisTest.Pearson(sampleX0, sampleY, 0.90))
print('FullPearsonX0Y=', HypothesisTest.FullPearson(
sampleX0, sampleY, 0.90))
# FullPearson : Independence Pearson test between 2 samples : firstSample of dimension n and secondSample of dimension 1. If firstSample[i] is the numerical sample extracted from firstSample (ith coordinate of each point of the numerical sample), FullPearson performs the Independence Pearson test simultaneously on firstSample[i] and secondSample. For all i, it is supposed that the couple (firstSample[i] and secondSample) is issued from a gaussian vector.
# Probability of the H0 reject zone : 1-0.90
print('FullPearsonXY=', HypothesisTest.FullPearson(
sampleX, sampleY, 0.90))
print('FullPearsonYY=', HypothesisTest.FullPearson(
sampleY, sampleY, 0.90))
# PartialSpearman test between 2 samples : firstSample of dimension n and secondSample of dimension 1. If firstSample[i] is the numerical sample extracted from firstSample (ith coordinate of each point of the numerical sample), PartialSpearman performs the Independence Spearman test simultaneously on firstSample[i] and secondSample, for i in the selection.
# Probability of the H0 reject zone : 1-0.90
# The three tests must be equal
print('PartialSpearmanX0Y=', HypothesisTest.PartialSpearman(
sampleX, sampleY, selection2, 0.90))
print('SpearmanX0Y=', HypothesisTest.Spearman(sampleX0, sampleY, 0.90))
print('FullSpearmanX0Y=', HypothesisTest.FullSpearman(
sampleX0, sampleY, 0.90))
print('PartialSpearmanXY=', HypothesisTest.PartialSpearman(
sampleX, sampleY, selection, 0.90))
# FullSpearman : Spearman test between 2 samples : firstSample of dimension n and secondSample of dimension 1. If firstSample[i] is the numerical sample extracted from firstSample (ith coordinate of each point of the numerical sample), FullSpearman performs the Independence Spearman test simultaneously on all firstSample[i] and secondSample.
# Probability of the H0 reject zone : 1-0.90
print('FullSpearmanYZ=', HypothesisTest.FullSpearman(
sampleY, sampleZ, 0.90))
print('FullSpearmanYY=', HypothesisTest.FullSpearman(
sampleY, sampleY, 0.90))
# Regression test between 2 samples : firstSample of dimension n and
# secondSample of dimension 1. If firstSample[i] is the numerical sample
# extracted from firstSample (ith coordinate of each point of the
# numerical sample), PartialRegression performs the Regression test
# simultaneously on all firstSample[i] and secondSample, for i in the
# selection. The Regression test tests ifthe regression model between two
# scalar numerical samples is significant. It is based on the deviation
# analysis of the regression. The Fisher distribution is used.
# The two tests must be equal
print('PartialRegressionX0Y=', HypothesisTest.PartialRegression(
sampleX, sampleY, selection2, 0.90))
print('FullRegressionX0Y=', HypothesisTest.FullRegression(
sampleX0, sampleY, 0.90))
print('PartialRegressionXY=', HypothesisTest.PartialRegression(
sampleX, sampleY, selection, 0.90))
# Regression test between 2 samples : firstSample of dimension n and
# secondSample of dimension 1. If firstSample[i] is the numerical sample
# extracted from firstSample (ith coordinate of each point of the
# numerical sample), FullRegression performs the Regression test
# simultaneously on all firstSample[i] and secondSample. The Regression
# test tests if the regression model between two scalar numerical samples
# is significant. It is based on the deviation analysis of the regression.
# The Fisher distribution is used.
print('FullRegressionXZ=', HypothesisTest.FullRegression(
sampleX, sampleY, 0.90))
print('FullRegressionZZ=', HypothesisTest.FullRegression(
sampleZ, sampleZ, 0.90))
|