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/*
* Sample application to change password using pam_pgsql
*
* William Grzybowski <william@agencialivre.com.br>
*/
#include <config.h>
#include <stdio.h>
#include <stdlib.h>
#include <security/pam_appl.h>
#if HAVE_SECURITY_OPENPAM_H
#include <security/openpam.h>
#elif HAVE_SECURITY_PAM_MISC_H
#include <security/pam_misc.h>
#endif
static struct pam_conv conv = {
#if HAVE_OPENPAM_TTYCONV
openpam_ttyconv,
#elif HAVE_MISC_CONV
misc_conv,
#else
# error "No PAM conversation found"
#endif
NULL
};
int main(int argc, char **argv) {
pam_handle_t *pamh=NULL;
int retval;
const char *user="nobody";
if(argc == 2)
user = argv[1];
else if(argc > 2) {
fprintf(stderr, "Usage: chpass [username]\n");
exit(1);
}
retval = pam_start("pgsql", user, &conv, &pamh);
if(retval == PAM_SUCCESS) {
printf("PAM started.\n");
retval = pam_chauthtok(pamh, 0);
}
printf("Changing authentication token...\n");
if(retval != PAM_SUCCESS) {
printf("Failed: %s\n", pam_strerror(pamh, retval));
} else {
printf("Token changed.\n");
}
/* This is where we have been authorized or not. */
if (pam_end(pamh,retval) != PAM_SUCCESS) { /* close Linux-PAM */
pamh = NULL;
fprintf(stderr, "check_user: failed to release authenticator\n");
exit(1);
}
return ( retval == PAM_SUCCESS ? 0:1 ); /* indicate success */
}
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