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# -*- coding: utf-8 -*-
"""
The Pygments Markdown Preprocessor
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
This fragment is a Markdown_ preprocessor that renders source code
to HTML via Pygments. To use it, invoke Markdown like so::
from markdown import Markdown
md = Markdown()
md.preprocessors.insert(0, CodeBlockPreprocessor())
markdown = md.__str__
markdown is then a callable that can be passed to the context of
a template and used in that template, for example.
This uses CSS classes by default, so use
``pygmentize -S <some style> -f html > pygments.css``
to create a stylesheet to be added to the website.
You can then highlight source code in your markdown markup::
[sourcecode:lexer]
some code
[/sourcecode]
.. _Markdown: http://www.freewisdom.org/projects/python-markdown/
:copyright: 2007 by Jochen Kupperschmidt.
:license: BSD, see LICENSE for more details.
"""
# Options
# ~~~~~~~
# Set to True if you want inline CSS styles instead of classes
INLINESTYLES = False
import re
from markdown import Preprocessor
from pygments import highlight
from pygments.formatters import HtmlFormatter
from pygments.lexers import get_lexer_by_name, TextLexer
class CodeBlockPreprocessor(Preprocessor):
pattern = re.compile(
r'\[sourcecode:(.+?)\](.+?)\[/sourcecode\]', re.S)
formatter = HtmlFormatter(noclasses=INLINESTYLES)
def run(self, lines):
def repl(m):
try:
lexer = get_lexer_by_name(m.group(1))
except ValueError:
lexer = TextLexer()
code = highlight(m.group(2), lexer, formatter)
code = code.replace('\n\n', '\n \n')
return '\n\n<div class="code">%s</div>\n\n' % code
return self.pattern.sub(
repl, '\n'.join(lines)).split('\n')
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