1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175
|
---
jupytext:
text_representation:
extension: .md
format_name: myst
format_version: 0.13
jupytext_version: 1.10.3
kernelspec:
display_name: Python 3
language: python
name: python3
---
How to filter arrays: cutting vs. masking
=========================================
```{code-cell} ipython3
import awkward as ak
import numpy as np
```
## The problem with slicing
When you write a mathematical formula using binary operators like `+` and `*`, or [NumPy universal functions (ufuncs)](https://numpy.org/doc/stable/reference/ufuncs.html) like `np.sqrt`, the shapes of nested lists must align. If the arrays in an expression were derived from a single array, this is often automatic. For instance,
```{code-cell} ipython3
original_array = ak.Array([
[
{"title": "zero", "x": 0, "y": 0},
{"title": "one", "x": 1, "y": 1.1},
{"title": "two", "x": 2, "y": 2.2},
],
[],
[
{"title": "three", "x": 3, "y": 3.3},
{"title": "four", "x": 4, "y": 4.4},
],
[
{"title": "five", "x": 5, "y": 5.5},
],
[
{"title": "six", "x": 6, "y": 6.6},
{"title": "seven", "x": 7, "y": 7.7},
{"title": "eight", "x": 8, "y": 8.8},
{"title": "nine", "x": 9, "y": 9.9},
],
])
```
```{code-cell} ipython3
array_x = original_array.x
array_y = original_array.y
```
The `array_x` and `array_y` have the same number of lists and the same numbers of items in each list because they were both slices of the `original_array`.
```{code-cell} ipython3
array_x
```
```{code-cell} ipython3
array_y
```
Thus, they can be used together in a mathematical formula.
```{code-cell} ipython3
array_x**2 + array_y**2
```
However, if one array is sliced, or if the two arrays are sliced by different criteria, they would no longer line up:
```{code-cell} ipython3
sliced_x = array_x[array_x > 3]
sliced_y = array_y[array_y > 3]
```
```{code-cell} ipython3
sliced_x
```
```{code-cell} ipython3
sliced_y
```
Notice that the first was sliced with `array_x > 3` and the second was sliced with `array_y > 3`, and as a result, the third list differs in length between the two arrays:
```{code-cell} ipython3
sliced_x[2], sliced_y[2]
```
+++ {"editable": true, "slideshow": {"slide_type": ""}}
If we try to use these together, we get a ValueError:
```{code-cell} ipython3
---
editable: true
slideshow:
slide_type: ''
tags: [raises-exception]
---
sliced_x**2 + sliced_y**2
```
Sometimes, these misalignments are overt, but sometimes they're subtle and embedded deep within a very large array. You can start investigating a problem like this with {func}`ak.num`:
```{code-cell} ipython3
ak.num(sliced_x) != ak.num(sliced_y)
```
```{code-cell} ipython3
np.nonzero(ak.to_numpy(ak.num(sliced_x) != ak.num(sliced_y)))
```
But it's also possible to avoid them in the first place.
## Masking with missing values
The problem was that the two arrays' shapes changed differently; instead, we'll slice them in such a way that their shapes don't change at all.
The {func}`ak.mask` function uses a boolean array like a slice, but takes values that line up with `False` and returns `None` instead of removing them.
```{code-cell} ipython3
ak.mask(array_x, array_x > 3)
```
It can also be accessed as an array property, with square brackets, so that it resembles a slice:
```{code-cell} ipython3
masked_x = array_x.mask[array_x > 3]
masked_y = array_y.mask[array_y > 3]
```
```{code-cell} ipython3
masked_x
```
```{code-cell} ipython3
masked_y
```
The results of these two masks can be used in a mathematical expression because they line up:
```{code-cell} ipython3
result = masked_x**2 + masked_y**2
result
```
Now only one problem remains: the `None` (missing) values might be undesirable in the output. There are several ways to get rid of them:
* {func}`ak.drop_none` eliminates `None`, like a slice, but it can be done once at the end of a calculation,
* {func}`ak.fill_none` replaces `None` with a chosen value,
* {func}`ak.flatten` removes list structure, and if the `None` values are at the level of a list (the ones in `result` aren't), they'll be removed too,
* {func}`ak.singletons` replaces `None` with `[]` and any other value `x` with `[x]`. The resulting lists all have length 0 or length 1.
```{code-cell} ipython3
ak.drop_none(result, axis=1)
```
```{code-cell} ipython3
ak.fill_none(result, -1, axis=1)
```
```{code-cell} ipython3
ak.singletons(result, axis=1)
```
As a final note, the difference between using {func}`ak.drop_none` and slicing with the result of {func}`ak.is_none` is that {func}`ak.drop_none` also removes "missingness" from the data type; a slice does not.
```{code-cell} ipython3
result[~ak.is_none(result, axis=1)]
```
(Note the `?` for "option-type" before `float64`. This could have consequences, good or bad, at a later stage in processing.)
|