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# -*- coding: utf-8 -*-
# The MIT License (MIT)
#
# Copyright © 2014 Tim Bielawa <timbielawa@gmail.com>
#
# Permission is hereby granted, free of charge, to any person
# obtaining a copy of this software and associated documentation files
# (the "Software"), to deal in the Software without restriction,
# including without limitation the rights to use, copy, modify, merge,
# publish, distribute, sublicense, and/or sell copies of the Software,
# and to permit persons to whom the Software is furnished to do so,
# subject to the following conditions:
#
# The above copyright notice and this permission notice shall be
# included in all copies or substantial portions of the Software.
#
# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND,
# EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
# MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
# NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS
# BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN
# ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN
# CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
# SOFTWARE.
import platform
(major, minor, patch) = platform.python_version_tuple()
if int(major) == 2 and int(minor) < 7:
import unittest2 as unittest
else:
import unittest
class TestCase(unittest.TestCase):
"""
Parent TestCase to use for all tests.
"""
def assertListEqual(self, l1, l2, msg=None):
"""Assert that the contents of l1 and l2 are equal (disregarding
ordering)"""
self.assertEqual(len(l1), len(l2))
# OK, the lists are of the same size. Let's test that each
# item in l1 is in l2. This assumes that what you provided in
# l1 are what you expected to find in l2.
for item in l1:
if item not in l2:
raise AssertionError("List 1 and list 2 are not equivalent: %s %s" % (
str(l1),
str(l2)))
return True
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