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# holidays
# --------
# A fast, efficient Python library for generating country, province and state
# specific sets of holidays on the fly. It aims to make determining whether a
# specific date is a holiday as fast and flexible as possible.
#
# Authors: Vacanza Team and individual contributors (see CONTRIBUTORS file)
# dr-prodigy <dr.prodigy.github@gmail.com> (c) 2017-2023
# ryanss <ryanssdev@icloud.com> (c) 2014-2017
# Website: https://github.com/vacanza/holidays
# License: MIT (see LICENSE file)
from datetime import date
from unittest import TestCase
from holidays.calendars.gregorian import TUE, SAT, _timedelta, _get_nth_weekday_of_month
class TestGregorianCalendar(TestCase):
def test_get_nth_weekday_of_month(self):
year = 2023
# The first Tuesdays of 2023.
for month, day in enumerate((3, 7, 7, 4, 2, 6, 4, 1, 5, 3, 7, 5), 1):
first_tuesday = _get_nth_weekday_of_month(1, TUE, month, year)
self.assertEqual(first_tuesday.day, day)
# The last Saturdays of 2023.
for month, day in enumerate((28, 25, 25, 29, 27, 24, 29, 26, 30, 28, 25, 30), 1):
last_friday = _get_nth_weekday_of_month(-1, SAT, month, year)
self.assertEqual(last_friday.day, day)
def test_delta_days(self):
for ymd1, ymd2 in (
((2023, 1, 1), (2023, 1, 6)),
((2023, 1, 31), (2023, 2, 5)),
((2023, 2, 24), (2023, 3, 1)),
((2023, 2, 26), (2023, 3, 3)),
((2024, 1, 1), (2024, 1, 6)),
((2024, 1, 31), (2024, 2, 5)),
((2024, 2, 24), (2024, 2, 29)),
((2024, 2, 26), (2024, 3, 2)),
):
dt1 = date(*ymd1)
dt2 = date(*ymd2)
self.assertEqual(_timedelta(dt1, +5), dt2)
self.assertEqual(_timedelta(dt2, -5), dt1)
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