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# holidays
# --------
# A fast, efficient Python library for generating country, province and state
# specific sets of holidays on the fly. It aims to make determining whether a
# specific date is a holiday as fast and flexible as possible.
#
# Authors: Vacanza Team and individual contributors (see CONTRIBUTORS file)
# dr-prodigy <dr.prodigy.github@gmail.com> (c) 2017-2023
# ryanss <ryanssdev@icloud.com> (c) 2014-2017
# Website: https://github.com/vacanza/holidays
# License: MIT (see LICENSE file)
from unittest import TestCase
from holidays.countries.lesotho import Lesotho
from tests.common import CommonCountryTests
class TestLesotho(CommonCountryTests, TestCase):
@classmethod
def setUpClass(cls):
super().setUpClass(Lesotho, years=range(1996, 2040))
def test_special_holidays(self):
self.assertHoliday("2002-05-25")
def test_heroes_day(self):
name = "Heroes Day"
self.assertHolidayName(name, (f"{year}-04-04" for year in range(1996, 2003)))
self.assertNoHolidayName(name, range(2003, 2040))
self.assertNoHoliday(f"{year}-04-04" for year in range(2003, 2040))
def test_africa_heroes_day(self):
name = "Africa/Heroes Day"
self.assertHolidayName(name, (f"{year}-05-25" for year in range(2003, 2040)))
self.assertNoHolidayName(name, range(1996, 2003))
self.assertNoHoliday(f"{year}-05-25" for year in range(1996, 2002))
def test_kings_birthday(self):
name = "King's Birthday"
self.assertHolidayName(name, (f"{year}-05-02" for year in range(1996, 1998)))
self.assertHolidayName(name, (f"{year}-07-17" for year in range(1998, 2040)))
self.assertNoHoliday(f"{year}-05-02" for year in range(1998, 2040))
self.assertNoHoliday(f"{year}-07-17" for year in range(1996, 1998))
def test_2022(self):
self.assertHolidaysInYear(
2022,
("2022-01-01", "New Year's Day"),
("2022-03-11", "Moshoeshoe's Day"),
("2022-04-15", "Good Friday"),
("2022-04-18", "Easter Monday"),
("2022-05-01", "Workers' Day"),
("2022-05-25", "Africa/Heroes Day"),
("2022-05-26", "Ascension Day"),
("2022-07-17", "King's Birthday"),
("2022-10-04", "Independence Day"),
("2022-12-25", "Christmas Day"),
("2022-12-26", "Boxing Day"),
)
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