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"""
Usage: simple.py <password> <url>
This downloads an NTML-protected webpage to stdout. The username is
constructed from the USERDOMAIN and USERNAME environment variables.
Note that the password is entered on the command line; this is almost
certainly a security risk but unfortunately I know of no foolproof
method in Python for prompting for a password from standard input.
This script only understands NTML authentication.
"""
import urllib2
import inspect, os, sys
try:
from ntlm import HTTPNtlmAuthHandler
except ImportError:
# assume ntlm is in the directory "next door"
ntlm_folder = os.path.realpath(os.path.join(
os.path.dirname(inspect.getfile(inspect.currentframe())),
'..'))
sys.path.insert(0, ntlm_folder)
from ntlm import HTTPNtlmAuthHandler
def process(password, url):
user = '%s\%s' % ( os.environ["USERDOMAIN"], os.environ["USERNAME"] )
passman = urllib2.HTTPPasswordMgrWithDefaultRealm()
passman.add_password(None, url, user, password)
# create the NTLM authentication handler
auth_NTLM = HTTPNtlmAuthHandler.HTTPNtlmAuthHandler(passman)
# create and install the opener
opener = urllib2.build_opener(auth_NTLM)
urllib2.install_opener(opener)
# retrieve the result
response = urllib2.urlopen(url)
print(response.read())
# The following is adapted from Guido van van Rossum's suggestion.
# http://www.artima.com/weblogs/viewpost.jsp?thread=4829
class Usage(Exception):
def __init__(self, msg):
self.msg = msg
import sys
import getopt
def main(argv=None):
if argv is None:
argv = sys.argv
try:
try:
opts, args = getopt.getopt(argv[1:], "h", ["help"])
except getopt.error, msg:
raise Usage(msg)
if opts:
raise Usage(__doc__)
if len(args) != 2:
raise Usage('need exactly 2 arguments (%d given)' % len(args))
process(*args)
except Usage, err:
print >>sys.stderr, err.msg
if err.msg is not __doc__:
print >>sys.stderr, "for help use --help"
return 2
if __name__ == "__main__":
sys.exit(main())
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