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from __future__ import division, print_function, absolute_import
# duplicates()
##############
import petl as etl
table1 = [['foo', 'bar', 'baz'],
['A', 1, 2.0],
['B', 2, 3.4],
['D', 6, 9.3],
['B', 3, 7.8],
['B', 2, 12.3],
['E', None, 1.3],
['D', 4, 14.5]]
table2 = etl.duplicates(table1, 'foo')
table2
# compound keys are supported
table3 = etl.duplicates(table1, key=['foo', 'bar'])
table3
# unique()
##########
import petl as etl
table1 = [['foo', 'bar', 'baz'],
['A', 1, 2],
['B', '2', '3.4'],
['D', 'xyz', 9.0],
['B', u'3', u'7.8'],
['B', '2', 42],
['E', None, None],
['D', 4, 12.3],
['F', 7, 2.3]]
table2 = etl.unique(table1, 'foo')
table2
# conflicts()
#############
import petl as etl
table1 = [['foo', 'bar', 'baz'],
['A', 1, 2.7],
['B', 2, None],
['D', 3, 9.4],
['B', None, 7.8],
['E', None],
['D', 3, 12.3],
['A', 2, None]]
table2 = etl.conflicts(table1, 'foo')
table2
# isunique()
############
import petl as etl
table1 = [['foo', 'bar'],
['a', 1],
['b'],
['b', 2],
['c', 3, True]]
etl.isunique(table1, 'foo')
etl.isunique(table1, 'bar')
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