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from itertools import count
nums = (1, 2, 3)
# these should match
for index, _ in enumerate(nums):
print(index)
for _, num in enumerate(nums):
print(num)
_ = (index for index, _ in enumerate(nums))
_ = (num for _, num in enumerate(nums))
_ = {"key": index for index, _ in enumerate(nums)}
_ = {"key": num for _, num in enumerate(nums)}
_ = (1 for index, num in enumerate(nums))
_ = {"key": "value" for index, num in enumerate(nums)}
nums2 = [4, 5, 6]
nums3 = tuple((7, 8, 9)) # noqa: FURB123
_ = (index for index, _ in enumerate(nums3))
for index, num in enumerate(nums):
pass
# these should not
# "count" is an infinite generator. In general, we only want to warn on
# sequence types because you can call len() on them without exhausting some
# iterator.
counter = count()
for index, _ in enumerate(counter):
pass
_ = (num for index, num in enumerate(nums) if index)
for index, _ in enumerate(nums):
print(index, _)
_ = ((index, _) for index, _ in enumerate(nums))
_ = ((_, num) for _, num in enumerate(nums))
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