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// Copyright (C) 2017 Robin Templeton. All rights reserved.
// This code is governed by the BSD license found in the LICENSE file.
/*---
description: Comparisons of BigInt and Number values
esid: sec-abstract-relational-comparison
info: |
...
3. If both px and py are Strings, then
...
4. Else,
a. Let nx be ? ToNumeric(px). Because px and py are primitive values evaluation order is not important.
b. Let ny be ? ToNumeric(py).
c. If Type(nx) is Type(ny), return ? Type(nx)::lessThan(nx, ny).
d. Assert: Type(nx) is BigInt and Type(ny) is Number, or if Type(nx) is Number and Type(ny) is BigInt.
e. If x or y are any of NaN, return undefined.
f. If x is -∞, or y is +∞, return true.
g. If x is +∞, or y is -∞, return false.
h. If the mathematical value of nx is less than the mathematical value of ny, return true, otherwise return false.
features: [BigInt]
---*/
assert.sameValue(0n <= 0, true, "0n <= 0");
assert.sameValue(0 <= 0n, true, "0 <= 0n");
assert.sameValue(0n <= -0, true, "0n <= -0");
assert.sameValue(-0 <= 0n, true, "-0 <= 0n");
assert.sameValue(0n <= 0.000000000001, true, "0n <= 0.000000000001");
assert.sameValue(0.000000000001 <= 0n, false, "0.000000000001 <= 0n");
assert.sameValue(0n <= 1, true, "0n <= 1");
assert.sameValue(1 <= 0n, false, "1 <= 0n");
assert.sameValue(1n <= 0, false, "1n <= 0");
assert.sameValue(0 <= 1n, true, "0 <= 1n");
assert.sameValue(1n <= 0.999999999999, false, "1n <= 0.999999999999");
assert.sameValue(0.999999999999 <= 1n, true, "0.999999999999 <= 1n");
assert.sameValue(1n <= 1, true, "1n <= 1");
assert.sameValue(1 <= 1n, true, "1 <= 1n");
assert.sameValue(0n <= Number.MIN_VALUE, true, "0n <= Number.MIN_VALUE");
assert.sameValue(Number.MIN_VALUE <= 0n, false, "Number.MIN_VALUE <= 0n");
assert.sameValue(0n <= -Number.MIN_VALUE, false, "0n <= -Number.MIN_VALUE");
assert.sameValue(-Number.MIN_VALUE <= 0n, true, "-Number.MIN_VALUE <= 0n");
assert.sameValue(-10n <= Number.MIN_VALUE, true, "-10n <= Number.MIN_VALUE");
assert.sameValue(Number.MIN_VALUE <= -10n, false, "Number.MIN_VALUE <= -10n");
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