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/*
* The contents of this file are subject to the Netscape Public
* License Version 1.1 (the "License"); you may not use this file
* except in compliance with the License. You may obtain a copy of
* the License at http://www.mozilla.org/NPL/
*
* Software distributed under the License is distributed on an "AS IS"
* basis, WITHOUT WARRANTY OF ANY KIND, either expressed
* or implied. See the License for the specific language governing
* rights and limitations under the License.
*
* The Original Code is mozilla.org code.
*
* The Initial Developer of the Original Code is Netscape
* Communications Corporation. Portions created by Netscape are
* Copyright (C) 1998 Netscape Communications Corporation.
* All Rights Reserved.
*
* Contributor(s): pschwartau@netscape.com
* Date: 23 October 2001
*
* SUMMARY: Testing regexps with the global flag set.
* NOT every substring fitting the given pattern will be matched.
* The parent string is CONSUMED as successive matches are found.
*
* From the ECMA-262 Final spec:
*
* 15.10.6.2 RegExp.prototype.exec(string)
* Performs a regular expression match of string against the regular
* expression and returns an Array object containing the results of
* the match, or null if the string did not match.
*
* The string ToString(string) is searched for an occurrence of the
* regular expression pattern as follows:
*
* 1. Let S be the value of ToString(string).
* 2. Let length be the length of S.
* 3. Let lastIndex be the value of the lastIndex property.
* 4. Let i be the value of ToInteger(lastIndex).
* 5. If the global property is false, let i = 0.
* 6. If i < 0 or i > length then set lastIndex to 0 and return null.
* 7. Call [[Match]], giving it the arguments S and i.
* If [[Match]] returned failure, go to step 8;
* otherwise let r be its State result and go to step 10.
* 8. Let i = i+1.
* 9. Go to step 6.
* 10. Let e be r's endIndex value.
* 11. If the global property is true, set lastIndex to e.
*
* etc.
*
*
* So when the global flag is set, |lastIndex| is incremented every time
* there is a match; not from i to i+1, but from i to "endIndex" e:
*
* e = (index of last input character matched so far by the pattern) + 1
*
* Thus in the example below, the first endIndex e occurs after the
* first match 'a b'. The next match will begin AFTER this, and so
* will NOT be 'b c', but rather 'c d'. Similarly, 'd e' won't be matched.
*/
//-----------------------------------------------------------------------------
var i = 0;
var bug = '(none)';
var summary = 'Testing regexps with the global flag set';
var status = '';
var statusmessages = new Array();
var pattern = '';
var patterns = new Array();
var string = '';
var strings = new Array();
var actualmatch = '';
var actualmatches = new Array();
var expectedmatch = '';
var expectedmatches = new Array();
status = inSection(1);
string = 'a b c d e';
pattern = /\w\s\w/g;
actualmatch = string.match(pattern);
expectedmatch = ['a b','c d']; // see above explanation -
addThis();
status = inSection(2);
string = '12345678';
pattern = /\d\d\d/g;
actualmatch = string.match(pattern);
expectedmatch = ['123','456'];
addThis();
//-----------------------------------------------------------------------------
test();
//-----------------------------------------------------------------------------
function addThis()
{
statusmessages[i] = status;
patterns[i] = pattern;
strings[i] = string;
actualmatches[i] = actualmatch;
expectedmatches[i] = expectedmatch;
i++;
}
function test()
{
enterFunc ('test');
printBugNumber (bug);
printStatus (summary);
testRegExp(statusmessages, patterns, strings, actualmatches, expectedmatches);
exitFunc ('test');
}
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