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/*
* The contents of this file are subject to the Netscape Public
* License Version 1.1 (the "License"); you may not use this file
* except in compliance with the License. You may obtain a copy of
* the License at http://www.mozilla.org/NPL/
*
* Software distributed under the License is distributed on an "AS IS"
* basis, WITHOUT WARRANTY OF ANY KIND, either expressed
* or implied. See the License for the specific language governing
* rights and limitations under the License.
*
* The Original Code is mozilla.org code.
*
* The Initial Developer of the Original Code is Netscape
* Communications Corporation. Portions created by Netscape are
* Copyright (C) 1998 Netscape Communications Corporation.
* All Rights Reserved.
*
* Contributor(s): mozilla@pdavis.cx, pschwartau@netscape.com
* Date: 22 October 2001
*
* SUMMARY: Regression test for Bugzilla bug 105972:
* "/^.*?$/ will not match anything"
*
* See http://bugzilla.mozilla.org/show_bug.cgi?id=105972
*/
//-----------------------------------------------------------------------------
var i = 0;
var bug = 105972;
var summary = 'Regression test for Bugzilla bug 105972';
var cnEmptyString = '';
var status = '';
var statusmessages = new Array();
var pattern = '';
var patterns = new Array();
var string = '';
var strings = new Array();
var actualmatch = '';
var actualmatches = new Array();
var expectedmatch = '';
var expectedmatches = new Array();
/*
* The bug: this match was coming up null in Rhino and SpiderMonkey.
* It should match the whole string. The reason:
*
* The * operator is greedy, but *? is non-greedy: it will stop
* at the simplest match it can find. But the pattern here asks us
* to match till the end of the string. So the simplest match must
* go all the way out to the end, and *? has no choice but to do it.
*/
status = inSection(1);
pattern = /^.*?$/;
string = 'Hello World';
actualmatch = string.match(pattern);
expectedmatch = Array(string);
addThis();
/*
* Leave off the '$' condition - here we expect the empty string.
* Unlike the above pattern, we don't have to match till the end of
* the string, so the non-greedy operator *? doesn't try to...
*/
status = inSection(2);
pattern = /^.*?/;
string = 'Hello World';
actualmatch = string.match(pattern);
expectedmatch = Array(cnEmptyString);
addThis();
/*
* Try '$' combined with an 'or' operator.
*
* The operator *? will consume the string from left to right,
* attempting to satisfy the condition (:|$). When it hits ':',
* the match will stop because the operator *? is non-greedy.
*
* The submatch $1 = (:|$) will contain the ':'
*/
status = inSection(3);
pattern = /^.*?(:|$)/;
string = 'Hello: World';
actualmatch = string.match(pattern);
expectedmatch = Array('Hello:', ':');
addThis();
/*
* Again, '$' combined with an 'or' operator.
*
* The operator * will consume the string from left to right,
* attempting to satisfy the condition (:|$). When it hits ':',
* the match will not stop since * is greedy. The match will
* continue until it hits $, the end-of-string boundary.
*
* The submatch $1 = (:|$) will contain the empty string
* conceived to exist at the end-of-string boundary.
*/
status = inSection(4);
pattern = /^.*(:|$)/;
string = 'Hello: World';
actualmatch = string.match(pattern);
expectedmatch = Array(string, cnEmptyString);
addThis();
//-----------------------------------------------------------------------------
test();
//-----------------------------------------------------------------------------
function addThis()
{
statusmessages[i] = status;
patterns[i] = pattern;
strings[i] = string;
actualmatches[i] = actualmatch;
expectedmatches[i] = expectedmatch;
i++;
}
function test()
{
enterFunc ('test');
printBugNumber (bug);
printStatus (summary);
testRegExp(statusmessages, patterns, strings, actualmatches, expectedmatches);
exitFunc ('test');
}
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