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/**************************************************************************
* *
* Regina - A Normal Surface Theory Calculator *
* Computational Engine *
* *
* Copyright (c) 1999-2025, Ben Burton *
* For further details contact Ben Burton (bab@debian.org). *
* *
* This program is free software; you can redistribute it and/or *
* modify it under the terms of the GNU General Public License as *
* published by the Free Software Foundation; either version 2 of the *
* License, or (at your option) any later version. *
* *
* As an exception, when this program is distributed through (i) the *
* App Store by Apple Inc.; (ii) the Mac App Store by Apple Inc.; or *
* (iii) Google Play by Google Inc., then that store may impose any *
* digital rights management, device limits and/or redistribution *
* restrictions that are required by its terms of service. *
* *
* This program is distributed in the hope that it will be useful, but *
* WITHOUT ANY WARRANTY; without even the implied warranty of *
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU *
* General Public License for more details. *
* *
* You should have received a copy of the GNU General Public License *
* along with this program. If not, see <https://www.gnu.org/licenses/>. *
* *
**************************************************************************/
#include "link.h"
#include <algorithm>
namespace regina {
bool Link::hasReducingPass() const {
// Get rid of 0-crossing links.
if (crossings_.empty())
return false;
// The planarity test is expensive (linear time), but finding a reducing
// pass is more expensive (cubic time), and it's best to tell users if
// they're doing things that will give mysteriously wrong answers.
if (! isClassical())
throw FailedPrecondition("Regina can only work with pass moves "
"in classical link diagrams, not virtual link diagrams");
// We consider sides of arcs: for crossing i, we denote:
// 4i = left side of upper outgoing arc
// 4i+1 = right side of upper outgoing arc
// 4i+2 = left side of lower outgoing arc
// 4i+3 = right side of lower outgoing arc
//
// Thus the index is:
// 4 * crossing index + (2 if lower) + (1 if right side)
// We will build an all-pairs shortest paths matrix between sides of
// arcs, where the distance represents the number of strands we must
// cross to get from one (side of arc) to the other. Here we only
// allow crossing a single strand (i.e., we cannot move between
// regions by passing through a crossing).
//
// For links diagrams with multiple disjoint components, our shortest paths
// algorithm will fail to realise that you can jump between components
// (since it essentially works by crawling around the boundary curves of
// cells in the link diagram). As a result, the "shortest paths" between
// disjoint components will be infinity. This does not matter, since a
// pass move always begins in a single component of the diagram, and (as
// we want a _reducing_ pass) it is never beneficial for such a move to
// interact with other components.
size_t nSides = 4 * crossings_.size();
// A distance that is larger than anything we should legitimately see:
size_t infinity = nSides + 1;
// dist[nSides*i + j] denotes the distance from (side of arc) i to j.
FixedArray<size_t> dist(nSides * nSides, infinity);
size_t upperOutgoing, lowerOutgoing, upperIncoming, lowerIncoming;
StrandRef prev;
for (Crossing* c : crossings_) {
upperOutgoing = 4 * c->index();
lowerOutgoing = upperOutgoing + 2;
prev = c->upper().prev();
upperIncoming = 4 * prev.crossing()->index() +
(prev.strand() == 0 ? 2 : 0);
prev = c->lower().prev();
lowerIncoming = 4 * prev.crossing()->index() +
(prev.strand() == 0 ? 2 : 0);
// Identify the initial distance 0 pairs:
if (c->sign() > 0) {
// Clockwise order:
// upper outgoing; lower incoming; upper incoming; lower outgoing
dist[nSides * (upperOutgoing + 1) + (lowerIncoming + 1)] =
dist[nSides * (lowerIncoming + 1) + (upperOutgoing + 1)] =
dist[nSides * (lowerIncoming) + (upperIncoming + 1)] =
dist[nSides * (upperIncoming + 1) + (lowerIncoming)] =
dist[nSides * (upperIncoming) + (lowerOutgoing)] =
dist[nSides * (lowerOutgoing) + (upperIncoming)] =
dist[nSides * (lowerOutgoing + 1) + (upperOutgoing)] =
dist[nSides * (upperOutgoing) + (lowerOutgoing + 1)] = 0;
} else {
// Clockwise order:
// upper outgoing; lower outgoing; upper incoming; lower incoming
dist[nSides * (upperOutgoing + 1) + (lowerOutgoing)] =
dist[nSides * (lowerOutgoing) + (upperOutgoing + 1)] =
dist[nSides * (lowerOutgoing + 1) + (upperIncoming + 1)] =
dist[nSides * (upperIncoming + 1) + (lowerOutgoing + 1)] =
dist[nSides * (upperIncoming) + (lowerIncoming + 1)] =
dist[nSides * (lowerIncoming + 1) + (upperIncoming)] =
dist[nSides * (lowerIncoming) + (upperOutgoing)] =
dist[nSides * (upperOutgoing) + (lowerIncoming)] = 0;
}
}
// Identify the initial distance 1 pairs, which are just the
// matching left/right pairs:
size_t i, j, k;
for (i = 0; i < nSides; i += 2)
dist[nSides * i + (i + 1)] =
dist[nSides * (i + 1) + i] = 1;
// Run Floyd-Warshall to compute all-pairs shortest paths:
for (k = 0; k < nSides; ++k)
for (i = 0; i < nSides; ++i)
for (j = 0; j < nSides; ++j) {
// To get from i to j, go via k if this helps.
if (dist[nSides * i + j] >
dist[nSides * i + k] + dist[nSides * k + j])
dist[nSides * i + j] =
dist[nSides * i + k] + dist[nSides * k + j];
}
#if 0
for (i = 0; i < nSides; ++i)
for (j = i + 1; j < nSides; ++j) {
std::cout << ((i & 2) ? '_' : '^') << (i / 4)
<< ((i & 1) ? '>' : '<') << " <--> ";
std::cout << ((j & 2) ? '_' : '^') << (j / 4)
<< ((j & 1) ? '>' : '<') << " : ";
std::cout << dist[nSides * i + j] << " == "
<< dist[nSides * j + i] << std::endl;
}
#endif
// Now we need to identify maximal sequences of strands that either
// (i) only involve over-crossings, or (ii) only involve under-crossings;
// and then see compare the number of crossings in these sequences
// against the corresponding shortest-paths entries in dist[].
// We make two passes through each link component: once looking for
// sequences of over-crossings, and then once looking for sequences of
// under-crossings. This is wasteful, but I've been flying for 28 hours
// now and this increases my chances of getting it right the first time. :/
for (auto comp : components_) {
// Zero-crossing components do not have reducing pass moves.
if (! comp)
continue;
// Start with over-crossings. This requires us to begin our
// traversal from an under-crossing.
StrandRef start = underForComponent(comp);
if (! start) {
// This component is a zero-crossing knot placed above the rest of
// the diagram, which means the entire knot can be slid away.
// This can be viewed as a reducing pass.
return true;
}
StrandRef s = start;
StrandRef beginSeq; // Arc from under-crossing to over-crossing
StrandRef endSeq; // Arc from over-crossing to under-crossing
size_t seqLen;
do {
if (s.strand() == 0) {
// This is always run in the first iteration of the loop,
// thereby initialising beginSeq and seqLen.
beginSeq = s;
seqLen = 0;
} else
++seqLen;
++s;
if (s.strand() == 0) {
endSeq = s.prev();
if (seqLen > 0) {
// Compare this to the shortest path in dist[].
// Note: we know that beginSeq is a (lower outgoing) arc,
// and that endSeq is an (upper outgoing) arc.
i = 4 * beginSeq.crossing()->index() + 2;
j = 4 * endSeq.crossing()->index();
if (dist[nSides * i + j] < seqLen ||
dist[nSides * i + j + 1] < seqLen ||
dist[nSides * (i + 1) + j] < seqLen ||
dist[nSides * (i + 1) + j + 1] < seqLen) {
return true;
}
}
}
} while (s != start);
// Now look for sequences of under-crossings.
// This time we must begin our traversal from an over-crossing.
start = overForComponent(comp);
if (! start) {
// This component is a zero-crossing knot placed below the rest of
// the diagram. Again this can be viewed as a reducing pass.
return true;
}
s = start;
do {
if (s.strand() == 1) {
// This is always run in the first iteration of the loop,
// thereby initialising beginSeq and seqLen.
beginSeq = s;
seqLen = 0;
} else
++seqLen;
++s;
if (s.strand() == 1) {
endSeq = s.prev();
if (seqLen > 0) {
// Compare this to the shortest path in dist[].
// Note: we know that beginSeq is an (upper outgoing) arc,
// and that endSeq is a (lower outgoing) arc.
i = 4 * beginSeq.crossing()->index();
j = 4 * endSeq.crossing()->index() + 2;
if (dist[nSides * i + j] < seqLen ||
dist[nSides * i + j + 1] < seqLen ||
dist[nSides * (i + 1) + j] < seqLen ||
dist[nSides * (i + 1) + j + 1] < seqLen) {
return true;
}
}
}
} while (s != start);
}
// Nothing found!
return false;
}
} // namespace regina
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