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/**************************************************************************
* *
* Regina - A Normal Surface Theory Calculator *
* Computational Engine *
* *
* Copyright (c) 1999-2025, Ben Burton *
* For further details contact Ben Burton (bab@debian.org). *
* *
* This program is free software; you can redistribute it and/or *
* modify it under the terms of the GNU General Public License as *
* published by the Free Software Foundation; either version 2 of the *
* License, or (at your option) any later version. *
* *
* As an exception, when this program is distributed through (i) the *
* App Store by Apple Inc.; (ii) the Mac App Store by Apple Inc.; or *
* (iii) Google Play by Google Inc., then that store may impose any *
* digital rights management, device limits and/or redistribution *
* restrictions that are required by its terms of service. *
* *
* This program is distributed in the hope that it will be useful, but *
* WITHOUT ANY WARRANTY; without even the implied warranty of *
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU *
* General Public License for more details. *
* *
* You should have received a copy of the GNU General Public License *
* along with this program. If not, see <https://www.gnu.org/licenses/>. *
* *
**************************************************************************/
#include "angle/anglestructures.h"
#include "enumerate/treeconstraint.h"
#include "enumerate/treelp.h"
#include "triangulation/dim3.h"
namespace regina {
bool Triangulation<3>::knowsStrictAngleStructure() const {
if (std::holds_alternative<AngleStructure>(strictAngleStructure_))
return true; // already known: a solution exists
if (std::get<bool>(strictAngleStructure_))
return true; // already known: no solution exists
// There are some simple cases for which we can deduce the answer
// automatically.
if (simplices_.empty()) {
strictAngleStructure_ = AngleStructure(*this, { 1 });
return true;
}
if (! hasBoundaryTriangles()) {
// It is easy to prove that, if an angle structure exists,
// then we must have #edges = #tetrahedra.
if (countEdges() != simplices_.size()) {
strictAngleStructure_ = true; // confirmed: no solution
return true;
}
}
// Don't know. This requres a real computation.
return false;
}
bool Triangulation<3>::hasStrictAngleStructure() const {
// The following test also catches any easy cases.
if (knowsStrictAngleStructure())
return std::holds_alternative<AngleStructure>(strictAngleStructure_);
// Run the full computation and cache the resulting structure, if any.
LPInitialTableaux<LPConstraintNone> eqns(*this, NormalCoords::Angle, false);
LPData<LPConstraintNone, Integer> lp;
lp.reserve(eqns);
// Find an initial basis.
lp.initStart();
// Set all angles to be strictly positive.
unsigned i;
for (i = 0; i < eqns.columns(); ++i) {
// std::cerr << "Constraining +ve: "
// << i << " / " << eqns.columns() << std::endl;
lp.constrainPositive(i);
}
// Test for a solution!
if (! lp.isFeasible()) {
strictAngleStructure_ = true; // confirmed: no solution
return false;
}
// We have a strict angle structure: reconstruct it.
strictAngleStructure_ = AngleStructure(*this,
lp.extractSolution<VectorInt>(nullptr /* type vector */));
return true;
}
bool Triangulation<3>::hasGeneralAngleStructure() const {
if (std::holds_alternative<AngleStructure>(generalAngleStructure_)) {
return true; // known to have a solution
} else if (std::get<bool>(generalAngleStructure_)) {
return false; // known to have no solution
}
// Run the full computation and cache the resulting structure, if any.
// There are some simple cases for which we can deduce the answer
// automatically.
if (simplices_.empty()) {
generalAngleStructure_ = AngleStructure(*this, { 1 });
return true;
}
if (! hasBoundaryTriangles()) {
// It is easy to prove that, if an angle structure exists,
// then we must have #edges = #tetrahedra.
if (countEdges() != simplices_.size()) {
generalAngleStructure_ = true; // confirmed: no solution
return false;
}
// If the triangulation is valid, we also need every vertex link
// to be a torus or Klein bottle. The only way this can *not*
// happen at this point in the code, given that we know that
// #edges = #tetrahedra, is to have some combination of internal
// vertices and higher-genus vertex links. This seems sufficiently
// exotic that we won't waste time testing it here; instead we
// just run the full linear algebra code (which still does the right
// thing if there is no solution).
}
// We want *any* solution to the homogeneous angle structure equations
// where the final coordinate (representing the scaling factor) is non-zero.
// The MatrixInt::rowEchelonForm() routine is enough for this: if there is
// any solution where the final coordinate is non-zero, then the final
// column will not appear as a leading coefficient in row echelon form.
MatrixInt eqns = regina::makeAngleEquations(*this);
size_t rank = eqns.rowEchelonForm();
// Note: the rank is always positive, since the triangulation is
// non-empty and so we always have tetrahedron equations present.
// Go down through the matrix from top-left to bottom-right and work
// out where the leading coefficients of each row appear.
auto* leading = new size_t[rank];
size_t row = 0;
size_t col = 0;
while (row < rank) {
if (eqns.entry(row, col) != 0) {
leading[row] = col;
++row;
}
++col;
}
if (leading[rank - 1] + 1 == eqns.columns()) {
// The final column appears as a leading coefficient.
delete[] leading;
generalAngleStructure_ = true; // confirmed: no solution
return false;
}
// Build up the final vector from back to front.
VectorInt v(eqns.columns());
v[eqns.columns() - 1] = 1;
// We currently have row == rank.
while (row > 0) {
// INV:
// - We have enforced equations row,...,(rank-1);
// - The current solution has gcd=1.
--row;
// Enforce equation #row.
col = leading[row];
Integer den = eqns.entry(row, col);
Integer num; // set to 0
for (++col; col < v.size(); ++col)
if (eqns.entry(row, col) != 0)
num += (eqns.entry(row, col) * v[col]);
// Our row echelon form guarantees that den > 0.
// We need to set v[leading[row]] = -num/den.
if (den == 1) {
v[leading[row]] = -num;
} else {
Integer gcd = den.gcd(num); // guaranteed >= 0.
if (gcd > 1) {
den.divByExact(gcd);
num.divByExact(gcd);
}
// Still we have den > 0.
if (den > 1)
v *= den;
// Now the current solution has gcd == den.
v[leading[row]] = -num;
// Since gcd(num, den) == 1, there is no need to scale down again.
}
}
delete[] leading;
generalAngleStructure_ = AngleStructure(*this, std::move(v));
return true;
}
} // namespace regina
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