File: specialization-default-types.rs

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rustc 1.85.0%2Bdfsg2-3
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// It should not be possible to use the concrete value of a defaulted
// associated type in the impl defining it -- otherwise, what happens
// if it's overridden?

#![feature(specialization)] //~ WARN the feature `specialization` is incomplete

trait Example {
    type Output;
    fn generate(self) -> Self::Output;
}

impl<T> Example for T {
    default type Output = Box<T>;
    default fn generate(self) -> Self::Output {
        Box::new(self) //~ ERROR mismatched types
    }
}

impl Example for bool {
    type Output = bool;
    fn generate(self) -> bool { self }
}

fn trouble<T>(t: T) -> Box<T> {
    Example::generate(t) //~ ERROR mismatched types
}

fn weaponize() -> bool {
    let b: Box<bool> = trouble(true);
    *b
}

fn main() {
    weaponize();
}