File: issue-67037-pat-tup-scrut-ty-diff-less-fields.rs

package info (click to toggle)
rustc 1.85.0%2Bdfsg3-1
  • links: PTS, VCS
  • area: main
  • in suites: experimental, sid, trixie
  • size: 893,396 kB
  • sloc: xml: 158,127; python: 35,830; javascript: 19,497; cpp: 19,002; sh: 17,245; ansic: 13,127; asm: 4,376; makefile: 1,051; perl: 29; lisp: 29; ruby: 19; sql: 11
file content (21 lines) | stat: -rw-r--r-- 1,047 bytes parent folder | download | duplicates (11)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
// Regression test for #67037.
//
// In type checking patterns, E0023 occurs when the tuple pattern and the expected
// tuple pattern have different number of fields. For example, as below, `P()`,
// the tuple struct pattern, has 0 fields, but requires 1 field.
//
// In emitting E0023, we try to see if this is a case of e.g., `Some(a, b, c)` but where
// the scrutinee was of type `Some((a, b, c))`, and suggest that parentheses be added.
//
// However, we did not account for the expected type being different than the tuple pattern type.
// This caused an issue when the tuple pattern type (`P<T>`) was generic.
// Specifically, we tried deriving the 0th field's type using the `substs` of the expected type.
// When attempting to substitute `T`, there was no such substitution, so "out of range" occurred.

struct U {} // 0 type parameters offered
struct P<T>(T); // 1 type parameter wanted

fn main() {
    let P() = U {}; //~ ERROR mismatched types
    //~^ ERROR this pattern has 0 fields, but the corresponding tuple struct has 1 field
}